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Author: Tinku Tara

dx-1-x-97-7-

Question Number 129672 by Dwaipayan Shikari last updated on 17/Jan/21 $$\int\frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{97}} \right)^{\mathrm{7}} } \\ $$ Answered by mindispower last updated on 17/Jan/21 $${u}={x}^{\mathrm{97}} \Rightarrow{dx}=\frac{{u}^{−\frac{\mathrm{96}}{\mathrm{97}}} }{\mathrm{97}}{du}…

4x-12-x-x-2-7-x-1-x-

Question Number 64130 by ANTARES VY last updated on 14/Jul/19 $$\sqrt{\mathrm{4}\boldsymbol{\mathrm{x}}+\frac{\mathrm{12}}{\boldsymbol{\mathrm{x}}}}=\frac{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{7}}{\boldsymbol{\mathrm{x}}+\mathrm{1}} \\ $$$$\boldsymbol{\mathrm{x}}=? \\ $$ Commented by Prithwish sen last updated on 14/Jul/19 $$\mathrm{x}=\:\mathrm{1},\mathrm{1},\mathrm{3}\:\mathrm{and}\:\frac{−\mathrm{1}\pm\mathrm{15i}}{\mathrm{2}}…

14-3-26-5-3-1-3-

Question Number 129663 by liberty last updated on 17/Jan/21 $$\:\sqrt{\mathrm{14}+\sqrt{\mathrm{3}}\:+\sqrt[{\mathrm{3}}]{\mathrm{26}−\mathrm{5}\sqrt{\mathrm{3}}}}\:=?\: \\ $$ Commented by MathSh last updated on 17/Jan/21 $$\sqrt[{\mathrm{3}}]{\left(\mathrm{26}−\mathrm{15}\sqrt{\mathrm{3}}\right)^{\mathrm{3}} }=\sqrt[{\mathrm{3}}]{\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{\mathrm{3}} }=\mathrm{2}−\sqrt{\mathrm{3}} \\ $$$$\sqrt{\mathrm{14}+\sqrt{\mathrm{3}}+\mathrm{2}−\sqrt{\mathrm{3}}}=\sqrt{\mathrm{16}}=\mathrm{4} \\…

Question-64126

Question Number 64126 by Cheyboy last updated on 13/Jul/19 Answered by ajfour last updated on 13/Jul/19 $$\:\:\mathrm{32}\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:−\mathrm{8}\:\:\:\:\:\:\:\:\:−\mathrm{10}\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\mathrm{24} \\ $$$$\:\:\:\:\:\:\:\:\:−\mathrm{32}\:\:\:\:\:−\mathrm{8}\:\:\:\:\:\:\:\:\:−\mathrm{2}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\mathrm{14} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{24}\:\:\:\:\:\:\:\:\:\:\mathrm{6}\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\mathrm{12} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\mathrm{18}\:\:\:\:\:\:\:−\mathrm{18} \\ $$$${d}_{{n}}…

Question-129660

Question Number 129660 by ajfour last updated on 17/Jan/21 Commented by ajfour last updated on 17/Jan/21 $${If}\:{a}\:{plank}\:{is}\:{released}\:{in}\:{contact} \\ $$$${with}\:{a}\:{smooth}\:{cylinder}\:{of}\:{radius} \\ $$$${R},\:{at}\:{an}\:{angle}\:\alpha.\:{Find}\:{the}\:{angle} \\ $$$$\theta\:{when}\:{plank}\:{is}\:{about}\:{to}\:{leave} \\ $$$${contact}\:{with}\:{cylinder}.…

2014-x-3-4029x-2-2-0-x-1-lt-x-2-lt-x-3-x-2-x-1-x-3-

Question Number 64124 by ANTARES VY last updated on 13/Jul/19 $$\sqrt{\mathrm{2014}}\boldsymbol{\mathrm{x}}^{\mathrm{3}} −\mathrm{4029}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{2}=\mathrm{0} \\ $$$$\boldsymbol{\mathrm{x}}_{\mathrm{1}} <\boldsymbol{\mathrm{x}}_{\mathrm{2}} <\boldsymbol{\mathrm{x}}_{\mathrm{3}} \\ $$$$\boldsymbol{\mathrm{x}}_{\mathrm{2}} \left(\boldsymbol{\mathrm{x}}_{\mathrm{1}} +\boldsymbol{\mathrm{x}}_{\mathrm{3}} \right)=? \\ $$ Terms…