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Author: Tinku Tara

why-the-first-ionisation-H-i1-energy-of-Oxygen-smaller-than-the-second-A-Due-to-the-nuclear-charge-B-Due-to-the-distance-of-the-electron-from-the-nucleus-C-Due-to-the-effect-of-spin-pair-repul

Question Number 64101 by Rio Michael last updated on 13/Jul/19 $${why}\:{the}\:{first}\:{ionisation}\left(\bigtriangleup{H}_{{i}\mathrm{1}} \right){energy}\:{of}\:{Oxygen}\:{smaller} \\ $$$${than}\:{the}\:{second}? \\ $$$${A}.\:{Due}\:{to}\:{the}\:{nuclear}\:{charge} \\ $$$${B}.\:{Due}\:{to}\:{the}\:{distance}\:{of}\:{the}\:{electron}\:{from}\:{the}\:{nucleus} \\ $$$${C}.\:{Due}\:{to}\:{the}\:{effect}\:{of}\:{spin}−{pair}\:{repulsion} \\ $$$${D}.\:{Due}\:{to}\:{a}\:{shielding}\:{effect}. \\ $$ Commented…

sin-x-cos-x-1-proof-by-step-by-step-or-by-showing-all-steps-b-c-it-is-my-assignment-

Question Number 129634 by abdurehime last updated on 17/Jan/21 $$\boldsymbol{{sin}}^{ } \boldsymbol{{x}}+\boldsymbol{{cos}}^{ } \boldsymbol{{x}}=\mathrm{1}\:\mathrm{proof}\:\mathrm{by}\:\mathrm{step}\:\mathrm{by}\:\mathrm{step}\:\mathrm{or}\:\mathrm{by}\:\mathrm{showing}\:\mathrm{all}\:\mathrm{steps}\: \\ $$$$\mathrm{b}/\mathrm{c}\:\mathrm{it}\:\mathrm{is}\:\mathrm{my}\:\mathrm{assignment} \\ $$ Answered by MJS_new last updated on 17/Jan/21…

dx-x-2-1-2-k-1-n-1-k-k-1-2k-1-

Question Number 129635 by pticantor last updated on 17/Jan/21 $$\:\:\:\:\: \\ $$$$ \\ $$$$\:\:\:\:\:\:\int\frac{\boldsymbol{{dx}}}{\left(\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} }=? \\ $$$$\underset{\boldsymbol{{k}}=\mathrm{1}} {\overset{\boldsymbol{{n}}} {\sum}}\frac{\mathrm{1}}{\boldsymbol{{k}}\left(\boldsymbol{{k}}+\mathrm{1}\right)\left(\mathrm{2}\boldsymbol{{k}}+\mathrm{1}\right)}=? \\ $$ Commented by liberty…

Question-64097

Question Number 64097 by ajfour last updated on 13/Jul/19 Commented by ajfour last updated on 13/Jul/19 $${Find}\:{side}\:{length}\:\boldsymbol{{s}}\:{of}\:{equal}\:{sided} \\ $$$${hexagon}\:{inscribed}\:{in}\:{ellipse}\:{of} \\ $$$${parameters}\:\boldsymbol{{a}}\:{and}\:\boldsymbol{{b}}. \\ $$ Answered by…