Question Number 63920 by raj last updated on 11/Jul/19 $$\mathrm{If}\:\alpha,\beta\:\mathrm{are}\:\mathrm{root}\:\mathrm{of}\:\mathrm{quadratic}\:\mathrm{equation} \\ $$$${ax}^{\mathrm{2}} +{bx}+{c}\:\mathrm{then} \\ $$$$\underset{{x}\rightarrow\alpha} {\mathrm{lim}}\frac{\mathrm{1}−\mathrm{cos}\:\left({ax}^{\mathrm{2}} +{bx}+{c}\right)}{\left({x}−\alpha\right)^{\mathrm{2}} }=? \\ $$ Commented by Prithwish sen last…
Question Number 63919 by raj last updated on 11/Jul/19 $$\underset{{n}=\mathrm{2}} {\overset{\infty} {\prod}}\left(\mathrm{1}−\frac{\mathrm{1}}{{n}^{\mathrm{2}} }\right)=? \\ $$ Commented by Prithwish sen last updated on 11/Jul/19 $$\underset{\mathrm{n}=\mathrm{2}} {\overset{\mathrm{n}=\boldsymbol{\mathrm{n}}}…
Question Number 63918 by raj last updated on 11/Jul/19 $$\underset{{x}\rightarrow\pi/\mathrm{2}} {\mathrm{lim}}\frac{\left[\mathrm{1}−\mathrm{tan}\:{x}/\mathrm{2}\right]\left[\mathrm{1}−\mathrm{sin}\:{x}\right]}{\left[\mathrm{1}+\mathrm{tan}\:{x}/\mathrm{2}\right]\left[\pi−\mathrm{2}{x}\right]^{\mathrm{3}} }=? \\ $$ Answered by Cmr 237 last updated on 20/Aug/19 $${posons}\:{cette}\:{limite}\:{egale}\:{A} \\ $$$${par}\:{le}\:{developement}\:{limite}\:{we}\:{have}:…
Question Number 63917 by raj last updated on 11/Jul/19 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\sqrt{{x}+\sqrt{{x}+\sqrt{{x}}}}−\sqrt{{x}}\right) \\ $$ Commented by kaivan.ahmadi last updated on 11/Jul/19 $$×\frac{\sqrt{{x}+\sqrt{{x}+\sqrt{{x}}}}+\sqrt{{x}}}{\:\sqrt{{x}+\sqrt{{x}+\sqrt{{x}}}+\sqrt{{x}}}}={lim}_{{x}\rightarrow\infty} \frac{\sqrt{{x}+\sqrt{{x}}}}{\:\sqrt{{x}+\sqrt{{x}+\sqrt{{x}}}}}=\mathrm{1} \\ $$$$ \\…
Question Number 129451 by bemath last updated on 15/Jan/21 $$\:\mathrm{log}\:_{\mathrm{12}} \left(\sqrt{\mathrm{x}}\:+\:\sqrt[{\mathrm{4}}]{\mathrm{x}}\:\right)\:=\:\mathrm{log}\:_{\mathrm{9}} \left(\sqrt{\mathrm{x}}\:\right)\: \\ $$$$\:\mathrm{x}\:=\:? \\ $$ Answered by liberty last updated on 16/Jan/21 $$\:\mathrm{log}\:_{\mathrm{12}} \left(\sqrt{\mathrm{x}}\:+\:\sqrt[{\mathrm{4}}]{\mathrm{x}}\:\right)\:=\:\mathrm{log}\:_{\mathrm{3}}…
Question Number 129449 by Gulnoza last updated on 15/Jan/21 Answered by MJS_new last updated on 16/Jan/21 $$\mathrm{yes}. \\ $$ Commented by Gulnoza last updated on…
Question Number 129446 by Eric002 last updated on 15/Jan/21 $${find}\:{the}\:{fourier}\:{transform}\:{of}\:{signum} \\ $$$${function} \\ $$ Answered by Olaf last updated on 16/Jan/21 $$\mathrm{sgn}\left({x}\right)\:=\:\begin{cases}{−\mathrm{1},\:{x}\:<\:\mathrm{1}}\\{\mathrm{0},\:{x}\:=\:\mathrm{0}}\\{+\mathrm{1},\:{x}\:>\:\mathrm{1}}\end{cases}\: \\ $$$$\widehat {\mathrm{sgn}}\left({f}\right)\:=\:\underset{{T}\rightarrow\infty,\alpha\rightarrow\mathrm{0}}…
Question Number 129445 by Engr_Jidda last updated on 15/Jan/21 $${Solve}\:{the}\:{ODE}'{s}\:{using}\:{lipschitz}\:{condition} \\ $$$${with}\:{constant}\:{k}. \\ $$$$\left.\mathrm{1}\right)\:{f}\left({x},{y}\right)={x}^{\mathrm{2}} \varrho^{{x}+{y}} \\ $$$$\left.\mathrm{2}\right)\:{f}\left({x},{y}\right)={x}\mid{y}\mid \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 63904 by naka3546 last updated on 11/Jul/19 Commented by Prithwish sen last updated on 13/Jul/19 $$\frac{\mathrm{6}^{\mathrm{k}} }{\left(\mathrm{3}^{\mathrm{k}} −\mathrm{2}^{\mathrm{k}} \right)\left(\mathrm{3}^{\mathrm{k}+\mathrm{1}} −\mathrm{2}^{\mathrm{k}+\mathrm{1}} \right)}\:=\:\frac{\mathrm{3}^{\mathrm{k}} }{\mathrm{3}^{\mathrm{k}} −\mathrm{2}^{\mathrm{k}}…
Question Number 63903 by aliesam last updated on 10/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com