Question Number 129436 by mr W last updated on 07/Feb/21 Commented by mr W last updated on 07/Feb/21 $${see}\:{Q}\mathrm{129244} \\ $$ Commented by ajfour last…
Question Number 63900 by Rio Michael last updated on 10/Jul/19 Commented by Rio Michael last updated on 10/Jul/19 $${Inthe}\:{Diagram}\:{above}\:{ABCD}\:{and}\:{CDEF}\:{are}\:{parrallelograms} \\ $$$${which}\:{lie}\:{in}\:{thesame}\:{plane}. \\ $$$${A}\overset{\rightarrow} {{B}}=\boldsymbol{{p}}\:,\:{B}\overset{\rightarrow} {{C}}=\boldsymbol{{q}}\:\:{and}\:{C}\overset{\rightarrow}…
Question Number 129435 by Tinku Tara last updated on 15/Jan/21 $$\mathrm{For}\:\mathrm{any}\:\mathrm{app}\:\mathrm{related}\:\mathrm{question}\:\mathrm{please}\:\mathrm{write}\:\mathrm{in} \\ $$$$\mathrm{English}.\:\mathrm{Thank}\:\:\mathrm{You}. \\ $$$$\mathrm{You}\:\mathrm{can}\:\mathrm{also}\:\mathrm{send}\:\mathrm{us}\:\mathrm{an}\:\mathrm{email} \\ $$ Commented by mr W last updated on 16/Jan/21…
Question Number 129430 by MathSh last updated on 15/Jan/21 $$\mathrm{0}<{x}<\mathrm{1}\:\:\:{if}, \\ $$$${Compare}\:{it}: \\ $$$$\frac{\mathrm{1}}{{x}−\mathrm{1}}\:;\:\frac{{x}}{{x}−\mathrm{1}}\:;\:\frac{\mathrm{1}}{\mathrm{1}−{x}}\:;\:\frac{{x}}{\mathrm{1}−{x}}\:;\:\frac{{x}}{\mathrm{2}{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 63895 by aseer imad last updated on 10/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 63894 by mathmax by abdo last updated on 10/Jul/19 $${sove}\:{the}\:\left({de}\right)\:{x}^{\mathrm{2}} {y}^{'} \:−\left(\mathrm{2}{x}+\mathrm{3}\right){y}\:={sin}\left({x}^{\mathrm{2}} \right)\:\:{with}\:{y}\left(\mathrm{1}\right)=\mathrm{2}\:{and} \\ $$$${y}^{'} \left(\mathrm{1}\right)=\mathrm{1}\:. \\ $$ Commented by mathmax by abdo…
Question Number 63893 by mathmax by abdo last updated on 10/Jul/19 $$\left.\mathrm{1}\right)\:{simplify}\:{W}_{{n}} \left({z}\right)=\left(\mathrm{1}+{z}\right)\left(\mathrm{1}+{z}^{\mathrm{2}} \right)….\left(\mathrm{1}+{z}^{\mathrm{2}^{{n}} } \right)\:\left({z}\:{from}\:{C}\right) \\ $$$$\left.\mathrm{2}\right)\:{simplify}\:{P}_{{n}} \left(\theta\right)\:=\left(\mathrm{1}+{e}^{{i}\theta} \right)\left(\mathrm{1}+{e}^{\mathrm{2}{i}\theta} \right)…..\left(\mathrm{1}+{e}^{{i}\mathrm{2}^{{n}} \theta} \right)\:{and}\:{sove} \\ $$$${P}_{{n}}…
Question Number 63892 by mathmax by abdo last updated on 10/Jul/19 $${calculate}\:{A}=\int_{\mathrm{0}} ^{\infty} \:\:\frac{{x}^{\mathrm{2017}} }{\mathrm{1}+{x}^{\mathrm{2019}} }\:{dx}\:\:{and}\:{B}\:=\int_{\mathrm{0}} ^{\infty} \:\frac{{x}^{\mathrm{2019}} }{\mathrm{1}+{x}^{\mathrm{2021}} }\:{dx} \\ $$$${calculate}\:{the}\:{fraction}\:\frac{{A}}{{B}} \\ $$ Commented…
Question Number 63891 by Tawa1 last updated on 10/Jul/19 $$\mathrm{A}\:\mathrm{bus}\:\mathrm{is}\:\mathrm{travelling}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{road}\:\mathrm{at}\:\mathrm{100Km}/\mathrm{hr}\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{bus}\:\mathrm{conductor}\:\mathrm{walks}\:\mathrm{at}\:\mathrm{6Km}/\mathrm{hr}\:\mathrm{on}\:\mathrm{the}\:\mathrm{floor}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bus} \\ $$$$\mathrm{and}\:\mathrm{in}\:\mathrm{the}\:\mathrm{same}\:\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus}.\: \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{conductor}\:\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road},\:\mathrm{and} \\ $$$$\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{bus}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{bus}\:\mathrm{conductor}\:\mathrm{now}\:\mathrm{works}\:\mathrm{at}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{rate}\:\mathrm{but}\:\mathrm{in}\:\mathrm{the}\:\mathrm{opposite}\:\mathrm{direction}\:\mathrm{as}\:\mathrm{the}\:\mathrm{bus},\:\mathrm{find}\:\mathrm{his}\:\mathrm{new}\:\mathrm{speed} \\ $$$$\mathrm{relative}\:\mathrm{to}\:\mathrm{the}\:\mathrm{road}. \\ $$$$\mathrm{Answers}\:\mathrm{in}\:\mathrm{textbook}:\:\:\:\:\mathrm{106Km}/\mathrm{hr},\:\:\:\:\mathrm{64Km}/\mathrm{hr},\:\:\:\:\:\mathrm{94Km}/\mathrm{hr} \\…
Question Number 63888 by Mikael last updated on 10/Jul/19 $${y}\:=\:{log}_{\mathrm{2}} \left[{log}_{\mathrm{3}} \left({log}_{\mathrm{5}} {x}\right)\right] \\ $$$${y}\:=\:? \\ $$ Answered by Hope last updated on 10/Jul/19 $${y}={log}_{\mathrm{2}}…