Question Number 63710 by aliesam last updated on 07/Jul/19 Commented by mathmax by abdo last updated on 08/Jul/19 $${let}\:{A}_{{n}} =\int_{\mathrm{0}} ^{\frac{\mathrm{1}}{{n}}} {n}^{\mathrm{2}} \:{x}^{{x}+\mathrm{1}} \:{ex}\:\Rightarrow{A}_{{n}} =\int_{\mathrm{0}}…
Question Number 129244 by ajfour last updated on 14/Jan/21 Commented by ajfour last updated on 14/Jan/21 $${In}\:{terms}\:{of}\:{the}\:{sides}\:{of}\:\bigtriangleup{ABC}, \\ $$$${find}\:{largest}\:{radius}\:{sphere}\:{that} \\ $$$${can}\:{be}\:{placed}\:{against}\:{the}\:{room} \\ $$$${corner}\:{and}\:{triangle}.\:\:\:\:\: \\ $$…
Question Number 129242 by Adel last updated on 14/Jan/21 $$\mathrm{cot}^{\mathrm{2}} \frac{\pi}{\mathrm{7}}+\mathrm{cot}^{\mathrm{2}} \frac{\mathrm{2}\pi}{\mathrm{7}}+\mathrm{cot}^{\mathrm{2}} \frac{\mathrm{7}\pi}{\mathrm{2}}=? \\ $$$$\mathrm{answer}\:\:\mathrm{by}\:\mathrm{solve} \\ $$ Commented by liberty last updated on 14/Jan/21 $$\mathrm{qn}\:\mathrm{128582}…
Question Number 129243 by Engr_Jidda last updated on 14/Jan/21 $$ \\ $$ Answered by bemath last updated on 14/Jan/21 $$\:\:\:\:\:\:\: \\ $$ Commented by Engr_Jidda…
Question Number 129240 by abdurehime last updated on 14/Jan/21 $$\int\mathrm{e}^{\mathrm{x}^{\mathrm{x}} } \mathrm{dx}\:\:\:\:\:\mathrm{please}\:\mathrm{help}\:\mathrm{me} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129241 by BHOOPENDRA last updated on 14/Jan/21 $$\frac{{e}^{−\pi{s}} }{{s}^{\mathrm{2}} \left({s}^{\mathrm{2}} +\mathrm{1}\right)}\:{find}\:{inverse}\:{laplace} \\ $$ Answered by Olaf last updated on 14/Jan/21 $$\mathscr{L}\left({f}\left({t}\right)\right)\left({s}\right)\:=\:\frac{{e}^{−\pi{s}} }{{s}^{\mathrm{2}} \left({s}^{\mathrm{2}}…
Question Number 63703 by kaivan.ahmadi last updated on 07/Jul/19 $${sin}^{\mathrm{3}} {x}+{cos}^{\mathrm{3}} {x}=\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}{sin}\mathrm{2}{x}\:\::{x}\in\left[\mathrm{0},\mathrm{2}\pi\right]. \\ $$$${find}\:\:{x} \\ $$ Commented by Prithwish sen last updated on 08/Jul/19 $$\left(\mathrm{sinx}\:+\:\mathrm{cosx}\:\right)\:\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{sin2x}\right)\:−\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{sin2x}\right)=\mathrm{0}…
Question Number 63700 by Tawa1 last updated on 07/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129234 by bemath last updated on 14/Jan/21 $$\:\mathrm{cos}\:^{\mathrm{2}} \mathrm{47}°+\mathrm{cos}^{\mathrm{2}} \:\:\mathrm{73}°+\mathrm{cos}\:\mathrm{47}°\mathrm{cos}\:\mathrm{73}°+\frac{\mathrm{1}}{\mathrm{2}}=? \\ $$ Answered by liberty last updated on 14/Jan/21 $$\left(\mathrm{cos}\:\mathrm{73}°+\mathrm{cos}\:\mathrm{47}°\right)^{\mathrm{2}} −\mathrm{cos}\:\mathrm{73}°\mathrm{cos}\:\mathrm{47}°+\frac{\mathrm{1}}{\mathrm{2}}= \\ $$$$\left(\mathrm{2cos}\:\mathrm{60}°\mathrm{cos}\:\mathrm{13}°\right)^{\mathrm{2}}…
Question Number 129235 by enter last updated on 14/Jan/21 $$\:\:\boldsymbol{{a}}=\:\sqrt[{\mathrm{3}}]{\mathrm{7}}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{9}}\: \\ $$$$\:\:\:\boldsymbol{{b}}=\mathrm{4}\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{Taqqoslang}} \\ $$ Commented by enter last updated on 14/Jan/21 $${compare} \\ $$ Commented…