Question Number 211190 by mr W last updated on 30/Aug/24 Answered by A5T last updated on 31/Aug/24 $${Let}\:\angle{BCD}=\angle{CBD}=\theta\Rightarrow\angle{DBA}=\mathrm{90}°−\theta \\ $$$$\Rightarrow\angle{ADB}=\mathrm{90}°−\theta\Rightarrow\angle{DAB}=\mathrm{2}\theta \\ $$$$\angle{BCA}=\angle{CAB}=\mathrm{45}°\Rightarrow\angle{ACD}=\mathrm{45}°−\theta\Rightarrow?=\mathrm{45}°−\mathrm{2}\theta \\ $$$${Let}\:{CD}={BD}={x}\:{and}\:{AD}={AB}={BC}={y} \\…
Question Number 211191 by Tawa11 last updated on 30/Aug/24 Answered by mm1342 last updated on 30/Aug/24 $$\left(\left(\mathrm{2}^{{x}} \right)^{{y}} \right)^{{x}} =\left(\mathrm{3}^{{y}} \right)^{{z}} =\mathrm{7}^{{z}} =\mathrm{11}\:\checkmark \\ $$$$…
Question Number 211184 by nothing48 last updated on 30/Aug/24 Answered by mm1342 last updated on 30/Aug/24 $${x}={sinu} \\ $$$$\Rightarrow\int{sin}^{\mathrm{3}} {udu}=\int\left(\mathrm{1}−{cos}^{\mathrm{2}} {u}\right){sinudu} \\ $$$$=−{cosu}+\frac{\mathrm{1}}{\mathrm{3}}{cos}^{\mathrm{3}} {u}+{c} \\…
Question Number 211155 by Spillover last updated on 30/Aug/24 $$\int\frac{\left(\mathrm{sin}\:^{{n}} \left(\theta\right)−\mathrm{sin}\:\left(\theta\right)\right)^{\frac{\mathrm{1}}{{n}}} \mathrm{cos}\:\left(\theta\right)}{\mathrm{sin}\:^{{n}+\mathrm{1}} \left(\theta\right)}{d}\theta \\ $$$$ \\ $$ Answered by Frix last updated on 30/Aug/24 $$=\int\frac{{d}\theta}{\mathrm{sin}\:\theta}\:−\int\left(\mathrm{sin}\:\theta\right)^{\frac{\mathrm{1}−{n}−{n}^{\mathrm{2}}…
Question Number 211180 by Durganand last updated on 30/Aug/24 Answered by mr W last updated on 30/Aug/24 $$\left({ax}+{by}+{c}\right)\left(\frac{{x}}{{a}}+\frac{{y}}{{b}}+{d}\right) \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\left(\frac{{a}}{{b}}+\frac{{b}}{{a}}\right){xy}+\left({ad}+\frac{{c}}{{a}}\right){x}+\left({bd}+\frac{{c}}{{b}}\right)+{cd} \\ $$$$={x}^{\mathrm{2}} +{y}^{\mathrm{2}}…
Question Number 211129 by depressiveshrek last updated on 29/Aug/24 Commented by depressiveshrek last updated on 29/Aug/24 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{this}\:\mathrm{series} \\ $$ Answered by mr W last updated…
Question Number 211152 by Spillover last updated on 29/Aug/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int\frac{\sqrt{{x}}}{\mathrm{1}+{x}+{x}^{\mathrm{2}} +{x}^{\mathrm{3}} }{dx} \\ $$$$ \\ $$ Answered by Ghisom last updated…
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Question Number 211150 by Spillover last updated on 29/Aug/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \left(\mathrm{tan}\:^{\mathrm{2}} \theta+\mathrm{tan}\:^{\mathrm{5}} \theta\right){e}^{\mathrm{tan}\:^{\mathrm{2}} \theta} {d}\theta \\ $$$$ \\ $$$$ \\ $$ Commented…