Question Number 208976 by efronzo1 last updated on 30/Jun/24 Answered by mr W last updated on 30/Jun/24 $${say}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={u},\:{xy}={v} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} \geqslant\mathrm{2}\sqrt{{x}^{\mathrm{2}} {y}^{\mathrm{2}}…
Question Number 209041 by alcohol last updated on 30/Jun/24 Commented by alcohol last updated on 30/Jun/24 $${find}\:{r} \\ $$ Commented by mr W last updated…
Question Number 209036 by Tawa11 last updated on 30/Jun/24 There are 5 people in a school, 2 boys and 3girls, two students, are chosen at…
Question Number 209030 by Spillover last updated on 30/Jun/24 Answered by aleks041103 last updated on 30/Jun/24 $${moment}\:{generating}\:{function}\:{is} \\ $$$${m}\left({t}\right)=\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{m}_{{k}} }{{k}!}{t}^{{k}} ={m}_{\mathrm{0}} +{m}_{\mathrm{1}} {t}+……
Question Number 209031 by Spillover last updated on 30/Jun/24 Answered by Spillover last updated on 07/Jul/24 $${f}\left({x}\right)=\begin{cases}{\frac{\mathrm{1}}{{n}}\:\:\:\:{x}=\mathrm{1},\mathrm{2},\mathrm{3},…..=\frac{\mathrm{1}}{{n}}\left[{e}^{{t}} +{e}^{\mathrm{2}{t}} +{e}^{\mathrm{3}{t}} +……..\right]}\\{\mathrm{0}\:\:{else}\:{where}}\end{cases} \\ $$$$\left({a}\right)\:{moment}\:{generating}\:{function} \\ $$$${M}_{{x}} \left({t}\right)={E}\left({e}^{{tx}}…
Question Number 208999 by Spillover last updated on 30/Jun/24 Answered by mr W last updated on 30/Jun/24 Commented by mr W last updated on 30/Jun/24…
Question Number 209024 by Spillover last updated on 30/Jun/24 Commented by Spillover last updated on 30/Jun/24 Answered by Spillover last updated on 01/Jul/24 Answered by…
Question Number 209026 by Spillover last updated on 30/Jun/24 Answered by Spillover last updated on 07/Jul/24 $${f}\left({x}\right)=\left(\frac{\mathrm{4}}{{x}}\right)\left(\frac{\mathrm{1}}{\mathrm{4}}\right)^{{x}} \left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{4}−{x}} \:\:\: \\ $$$${x}=\mathrm{0},\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4} \\ $$$${f}\left(\mathrm{1}\right)=\left(\frac{\mathrm{4}}{\mathrm{1}}\right)\left(\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{1}} \left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{4}−\mathrm{1}} =\left(\frac{\mathrm{4}}{\mathrm{1}}\right)\left(\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{3}}…
Question Number 209027 by Spillover last updated on 30/Jun/24 Answered by Spillover last updated on 05/Jul/24 $${f}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{2}^{{k}+\mathrm{1}} }\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}=\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5},…..{n} \\ $$$${from}\:{Moment}\:{generating}\:{function}\left({MGF}\right) \\ $$$${M}_{{x}} \left({t}\right)={E}\left({e}^{{tx}} \right) \\…
Question Number 208972 by Spillover last updated on 29/Jun/24 Answered by Spillover last updated on 30/Jun/24 Answered by Spillover last updated on 30/Jun/24 Answered by…