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Author: Tinku Tara

Question-223619

Question Number 223619 by Tawa11 last updated on 01/Aug/25 Answered by Frix last updated on 01/Aug/25 $$\mid{C}_{\mathrm{1}} {C}_{\mathrm{2}} \mid=\sqrt{\mathrm{2}} \\ $$$$\Rightarrow\:{C}_{\mathrm{1}} ,\:{C}_{\mathrm{2}} \:\mathrm{form}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{intersection}\:\mathrm{points}\:\mathrm{with}…

40-x-1-2-2x-1-

Question Number 223615 by fantastic last updated on 31/Jul/25 $$\mathrm{40}^{{x}−\mathrm{1}} =\mathrm{2}^{\mathrm{2}{x}+\mathrm{1}} \\ $$ Answered by mr W last updated on 31/Jul/25 $$\frac{\mathrm{40}^{{x}} }{\mathrm{40}}=\mathrm{2}×\mathrm{2}^{\mathrm{2}{x}} =\mathrm{2}×\mathrm{4}^{{x}} \\…