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Author: Tinku Tara

dx-xln-x-ln-ln-x-1-ln-ln-x-2-ln-ln-x-3-ln-ln-x-4-

Question Number 211151 by Spillover last updated on 29/Aug/24 $$ \\ $$$$ \\ $$$$\int\frac{{dx}}{{x}\mathrm{ln}\:{x}\left(\mathrm{ln}\:\mathrm{ln}\:{x}−\mathrm{1}\right)\left(\mathrm{ln}\:\mathrm{ln}\:{x}−\mathrm{2}\right)\left(\mathrm{ln}\:\mathrm{ln}\:{x}−\mathrm{3}\right)\left(\mathrm{ln}\:\mathrm{ln}\:{x}−\mathrm{4}\right)} \\ $$$$ \\ $$$$ \\ $$ Answered by Ghisom last updated…

Question-211143

Question Number 211143 by boblosh last updated on 29/Aug/24 Answered by A5T last updated on 29/Aug/24 $${Let}\:{width}\:{be}\:{w}\Rightarrow{w}={y}+\mathrm{12} \\ $$$${perimeter}=\mathrm{2}\left({w}+{y}\right) \\ $$$$\mathrm{2}\left({w}+\mathrm{30}+{y}+\mathrm{30}\right)=\mathrm{3}×\mathrm{2}\left({w}+{y}\right) \\ $$$$\Rightarrow{w}+{y}=\mathrm{30}\Rightarrow{y}+\mathrm{12}+{y}=\mathrm{30}\Rightarrow{y}=\mathrm{9} \\ $$$$\Rightarrow{length}=\mathrm{9}\:{and}\:{width}=\mathrm{21}…

Question-211115

Question Number 211115 by Durganand last updated on 28/Aug/24 Answered by som(math1967) last updated on 28/Aug/24 $${tanA}+\mathrm{2}{tan}\mathrm{2}{A}+\frac{\mathrm{4}}{{tan}\mathrm{2}.\mathrm{2}{A}} \\ $$$$={tanA}+\mathrm{2}{tan}\mathrm{2}{A}+\frac{\mathrm{4}\left(\mathrm{1}−{tan}^{\mathrm{2}} \mathrm{2}{A}\right)}{\mathrm{2}{tan}\mathrm{2}{A}} \\ $$$$={tanA}+\frac{\mathrm{2}{tan}^{\mathrm{2}} \mathrm{2}{A}+\mathrm{2}−\mathrm{2}{tan}^{\mathrm{2}} \mathrm{2}{A}}{{tan}\mathrm{2}{A}}\: \\…