Question Number 128845 by Dwaipayan Shikari last updated on 10/Jan/21 $$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}.\frac{\mathrm{1}.\mathrm{4}}{\left(\mathrm{5}.\mathrm{1}!\right)^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{3}}.\frac{\mathrm{1}.\mathrm{4}.\mathrm{6}.\mathrm{9}}{\left(\mathrm{5}^{\mathrm{2}} .\mathrm{2}!\right)^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{4}}.\frac{\mathrm{1}.\mathrm{4}.\mathrm{6}.\mathrm{9}.\mathrm{11}.\mathrm{14}}{\left(\mathrm{5}^{\mathrm{3}} .\mathrm{3}!\right)^{\mathrm{2}} }+…=\frac{{b}^{\mathrm{2}} \sqrt{\frac{{b}−\sqrt{{b}}}{\mathrm{2}}}}{{a}\pi} \\ $$$${Find}\:\mathrm{5}{a}−\mathrm{8}{b} \\ $$ Answered by mindispower last…
Question Number 128841 by mnjuly1970 last updated on 10/Jan/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…{nice}\:{calculus}\:… \\ $$$$\:\:\:\:\mathscr{E}{valuation}\:{of}\:::\:\Phi=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} {ln}\left({x}\right).{arctan}\left({x}\right){dx} \\ $$$${solution}:: \\ $$$$\:\:\:\:{note}\:\mathrm{1}::\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}−\mathrm{1}} }{\mathrm{2}{n}−\mathrm{1}}={arctan}\left(\mathrm{1}\right)=\frac{\pi}{\mathrm{4}} \\ $$$${note}\:\mathrm{2}\:::\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}−\mathrm{1}}…
Question Number 63301 by Rio Michael last updated on 02/Jul/19 $${find}\:\frac{{dy}}{{dx}}\:{if}\:\:{x}\left({x}\:+{y}\right)\:=\:{y}^{\mathrm{2}} \\ $$ Commented by kaivan.ahmadi last updated on 02/Jul/19 $${f}\left({x},{y}\right)={x}^{\mathrm{2}} +{xy}−{y}^{\mathrm{2}} =\mathrm{0} \\ $$$$\frac{{dy}}{{dx}}=−\frac{{f}'_{{x}}…
Question Number 128837 by BHOOPENDRA last updated on 10/Jan/21 Commented by BHOOPENDRA last updated on 10/Jan/21 $${without}\:{using}\:{gauss}\:{divergence}\:{theorm}\: \\ $$$${calculate}\:{surface}\:{integral}? \\ $$$${help}\:{me}\:{out}\:{this}? \\ $$ Terms of…
Question Number 63300 by Rio Michael last updated on 02/Jul/19 $${show}\:{that}\:\: \\ $$$$\left.{a}\right)\:\mathrm{1}\:+\:{tan}\:\left(\frac{\pi}{\mathrm{4}}\:+\:{A}\right)\:=\:\frac{\mathrm{2}}{\mathrm{1}−{tanA}} \\ $$$$\left.{b}\right)\:\mathrm{2}{cos}\mathrm{2}\theta{sin}\theta\:+\:\mathrm{9}{sin}\theta\:+\:\mathrm{3}\:\equiv\:\mathrm{11}{sin}\theta\:−\:\mathrm{4}{sin}^{\mathrm{3}} \theta\:+\:\mathrm{3} \\ $$ Commented by kaivan.ahmadi last updated on 02/Jul/19…
Question Number 128834 by bounhome last updated on 10/Jan/21 $$\int_{\mathrm{0}} ^{\mathrm{3}} \mid{x}^{\mathrm{2}} −\mathrm{2}{x}\mid{dx}=…?\:{is}\:{there}\:{any}\:{one}\:{to}\: \\ $$$${explain}\:{the}\:{way}\:{to}\:{solve}\:{this}\: \\ $$ Answered by bobhans last updated on 10/Jan/21 $$\:\int_{\mathrm{0}}…
Question Number 63298 by Rio Michael last updated on 02/Jul/19 $${A}\:{particle}\:{P},\:{moves}\:{on}\:{the}\:{curve}\:{with}\:{polar}\:{equation}\:\: \\ $$$${r}\:=\:{e}^{{k}\theta} \:,\:{where}\:\left({r},\theta\right)\:{are}\:{polar}\:{coordinates}\:{referred}\:{to}\:{a}\:{fixed} \\ $$$${pole}\:{and}\:{k}\:{is}\:{a}\:{positive}\:{constant}.\:{Given}\:{that}\:{the}\:{radial}\:{velocity} \\ $$$${of}\:{P}\:{is}\:\frac{{k}}{{r}}\:\:{show}\:{that}\:{the}\:{transverse}\:{acceleration}\:{of}\:{th}\:{particle} \\ $$$${is}\:{zero}. \\ $$$$ \\ $$ Commented…
Question Number 63296 by Rio Michael last updated on 02/Jul/19 $${A}\:{random}\:{Variable}\:{Y}\:{has}\:{probability}\:{function}\:{P},\:{defined}\:{by} \\ $$$$\:{P}\left({y}\right)\:=\:\begin{cases}{\frac{{y}^{\mathrm{2}} }{{k}}\:,\:{y}=\:\mathrm{1},\mathrm{2},\mathrm{3}}\\{\frac{\left({y}−\mathrm{7}\right)^{\mathrm{2}} }{{k}}\:,\:{y}=\:\mathrm{4},\mathrm{5},\mathrm{6}}\\{\mathrm{0}\:\:\:\:,\:{otherwise}.}\end{cases} \\ $$$${Find}\: \\ $$$$\left({i}\right)\:{The}\:{value}\:{of}\:{the}\:{constant}\:{k}. \\ $$$$\left({ii}\right)\:{the}\:{mean}\:{and}\:{varriance}\:{of}\:{Y}. \\ $$$$\left({iii}\right)\:{The}\:{variance}\:{R},\:{where}\:{R}=\:\mathrm{2}{Y}\:−\mathrm{3}. \\ $$…
Question Number 128830 by bemath last updated on 10/Jan/21 Answered by liberty last updated on 10/Jan/21 $$\:\mathrm{let}\:\mid\overset{\rightarrow} {{a}}\mid\:=\:\mid\overset{\rightarrow} {{b}}\mid\:=\:\mathrm{1}\:;\:\mathrm{also}\:\mid\:\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\mid\:=\:\mathrm{1}\: \\ $$$$\:\mathrm{we}\:\mathrm{want}\:\mathrm{to}\:\mathrm{compute}\:\mid\overset{\rightarrow} {{a}}−\overset{\rightarrow} {{b}}\:\mid\:.…
Question Number 128829 by bemath last updated on 10/Jan/21 $$\:\mathrm{If}\:\mathrm{x},\mathrm{y}\:\mathrm{and}\:\mathrm{x}\:\mathrm{in}\:\mathrm{HP}\:\mathrm{show}\:\mathrm{that}\: \\ $$$$\mathrm{log}\:\left(\mathrm{x}+\mathrm{z}\right)\:+\mathrm{log}\:\left(\mathrm{x}+\mathrm{z}−\mathrm{y}\right)\:=\:\mathrm{2}\:\mathrm{log}\:\left(\mathrm{x}−\mathrm{z}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com