Question Number 223580 by Nicholas666 last updated on 30/Jul/25 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}\:} \:\frac{{e}^{−\boldsymbol{{r}}^{\mathrm{2}} } \boldsymbol{\mathrm{sin}}\left(\mathrm{1}/\boldsymbol{{r}}^{\mathrm{2}} \right)\boldsymbol{\mathrm{ln}}\left(\boldsymbol{{r}}+\mathrm{1}\right)}{\boldsymbol{{r}}^{\mathrm{2}} }\:\boldsymbol{\mathrm{d}{r}} \\ $$$$ \\ $$ Answered by MathematicalUser2357…
Question Number 223585 by hardmath last updated on 30/Jul/25 Commented by hardmath last updated on 30/Jul/25 $$\mathrm{Radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\:=\:\mathrm{R} \\ $$$$\mathrm{AB}\:\bot\:\mathrm{CD} \\ $$$$\mathrm{AC}\:=\:\mathrm{a} \\ $$$$\mathrm{BD}\:=\:\mathrm{b} \\ $$$$\mathrm{Prove}\:\mathrm{that}:\:\mathrm{R}\:=\:\frac{\sqrt{\mathrm{a}^{\mathrm{2}}…
Question Number 223571 by hardmath last updated on 30/Jul/25 $$\mathrm{S}_{\mathrm{1}} \:=\:\mathrm{1}\centerdot\mathrm{1}!\:+\:\mathrm{2}\centerdot\mathrm{2}!\:+\:\mathrm{3}\centerdot\mathrm{3}!\:+…+\:\mathrm{16}\centerdot\mathrm{16}! \\ $$$$\mathrm{S}_{\mathrm{2}} \:=\:\mathrm{1}\centerdot\mathrm{1}!\:+\:\mathrm{2}\centerdot\mathrm{2}!\:+\:\mathrm{3}\centerdot\mathrm{3}!\:+…+\:\mathrm{14}\centerdot\mathrm{14}! \\ $$$$\mathrm{Find}:\:\:\:\frac{\mathrm{S}_{\mathrm{1}} }{\mathrm{S}_{\mathrm{2}} }\:=\:? \\ $$ Answered by parthasc last updated…
Question Number 223560 by fantastic last updated on 29/Jul/25 Commented by fantastic last updated on 29/Jul/25 $${area}=? \\ $$ Commented by fantastic last updated on…
Question Number 223544 by ajfour last updated on 29/Jul/25 Commented by ajfour last updated on 29/Jul/25 $${If}\:\mathrm{2}{R}\theta=\mathrm{2}\pi{r},\:{find}\:{R}/{r}\:{for}\:{h}=\mathrm{0}. \\ $$ Answered by mr W last updated…
Question Number 223569 by Atomusmaths last updated on 29/Jul/25 Answered by Raphael254 last updated on 30/Jul/25 $$ \\ $$$$\mathrm{5}^{\mathrm{50}} \:=\:\left(\mathrm{5}^{{x}} \right)^{\frac{\mathrm{50}}{{x}}} \\ $$$$\mathrm{5}^{{x}} \:=\:\frac{\mathrm{50}}{{x}} \\…
Question Number 223553 by fantastic last updated on 29/Jul/25 $${the}\:{length}\:{of}\:\mathrm{3}\:{meadians}\:{of}\:{a}\:{triangle}\:{is}\:{given} \\ $$$${how}\:{to}\:{calculate}\:{the}\:{area}? \\ $$ Commented by fantastic last updated on 29/Jul/25 $${please}\:{help} \\ $$ Answered…
Question Number 223570 by yapess3 last updated on 29/Jul/25 $${demontrer}\:{que}\:{quelque}\:{soit}\:{k}\:{appartenant}\:{N}\:\:{l} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 223534 by Tawa11 last updated on 28/Jul/25 $$\int_{\:\mathrm{0}} ^{\:\mathrm{1}} \:\frac{\mathrm{ln}\left(\mathrm{x}\right)}{\mathrm{x}}\:\mathrm{ln}^{\mathrm{3}} \left(\frac{\mathrm{1}\:\:−\:\:\mathrm{x}}{\mathrm{1}\:\:+\:\:\mathrm{x}}\right)\:\mathrm{dx} \\ $$ Answered by MathematicalUser2357 last updated on 31/Jul/25 $$\:\cancel{\:} \\ $$…
Question Number 223538 by fantastic last updated on 28/Jul/25 $${x}+{y}=\mathrm{36} \\ $$$${xy}_{{max}} =?? \\ $$ Answered by Frix last updated on 28/Jul/25 $$\mathrm{Max}\:\mathrm{at}\:{x}={y}=\mathrm{18}\:\mathrm{because}\:\mathrm{out}\:\mathrm{of}\:\mathrm{all}\:\mathrm{rectangles} \\ $$$$\mathrm{with}\:\mathrm{given}\:\mathrm{circumference}\:\mathrm{the}\:\mathrm{square}\:\mathrm{has}\:\mathrm{the}…