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Author: Tinku Tara

ln-1-xsin-2-x-sin-2-x-dx-

Question Number 62997 by aliesam last updated on 27/Jun/19 $$\int\frac{{ln}\left(\mathrm{1}+{xsin}^{\mathrm{2}} \left({x}\right)\right)}{{sin}^{\mathrm{2}} \left({x}\right)}\:{dx} \\ $$ Commented by mathmax by abdo last updated on 27/Jun/19 $${perhaps}\:{the}\:{Q}\:{is}\:{find}\:\int\:\frac{{ln}\left(\mathrm{1}+{tsin}^{\mathrm{2}} {x}\right)}{{sin}^{\mathrm{2}}…

Question-128529

Question Number 128529 by bramlexs22 last updated on 08/Jan/21 Commented by liberty last updated on 08/Jan/21 $$\mathrm{considering}\:\frac{\mathrm{d}}{\mathrm{dx}}\left(\frac{\mathrm{u}}{\mathrm{v}}\right)=\frac{\mathrm{u}'\mathrm{v}−\mathrm{uv}'}{\mathrm{v}^{\mathrm{2}} } \\ $$$$\:\mathrm{obvious}\:\mathrm{v}=\mathrm{2}+\mathrm{3cos}\:\mathrm{x}\:\mathrm{and}\:\mathrm{3}+\mathrm{2cos}\:\mathrm{x}=\mathrm{u}'\left(\mathrm{2}+\mathrm{3cos}\:\mathrm{x}\right)−\mathrm{u}\left(−\mathrm{3sin}\:\mathrm{x}\right) \\ $$$$\Rightarrow\mathrm{2cos}\:\mathrm{x}+\mathrm{3}=\mathrm{2u}'+\mathrm{3u}'\mathrm{cos}\:\mathrm{x}+\mathrm{3u}\:\mathrm{sin}\:\mathrm{x} \\ $$$$\mathrm{check}\:\mathrm{u}\:=\:\mathrm{sin}\:\mathrm{x}\:\Rightarrow\:\mathrm{u}'\left(\mathrm{2}+\mathrm{3cosx}\right)+\mathrm{3u}\:\mathrm{sin}\:\mathrm{x}=\: \\…

A-curve-has-equation-y-2-x-4-The-normal-at-point-P-1-1-and-the-normal-at-point-Q-9-1-intersect-at-the-point-R-What-are-coordinates-at-point-R-

Question Number 128521 by bramlexs22 last updated on 08/Jan/21 $$\mathrm{A}\:\mathrm{curve}\:\mathrm{has}\:\mathrm{equation}\:\mathrm{y}\:=\:\left(\mathrm{2}−\sqrt{\mathrm{x}}\:\right)^{\mathrm{4}} \\ $$$$\mathrm{The}\:\mathrm{normal}\:\mathrm{at}\:\mathrm{point}\:\mathrm{P}\left(\mathrm{1},\mathrm{1}\right)\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{normal}\:\mathrm{at}\:\mathrm{point}\:\mathrm{Q}\left(\mathrm{9},\mathrm{1}\right)\:\mathrm{intersect} \\ $$$$\mathrm{at}\:\mathrm{the}\:\mathrm{point}\:\mathrm{R}.\:\mathrm{What}\:\mathrm{are}\:\mathrm{coordinates} \\ $$$$\mathrm{at}\:\mathrm{point}\:\mathrm{R}? \\ $$ Answered by mr W last…

Question-128518

Question Number 128518 by shaker last updated on 08/Jan/21 Commented by bramlexs22 last updated on 08/Jan/21 $$\mathrm{3}^{\frac{\mathrm{1}}{\mathrm{n}}} \:=\:\mathrm{u}\:\Rightarrow\:\mathrm{3}^{\frac{\mathrm{1}}{\mathrm{n}}} \:+\:\mathrm{3}^{−\frac{\mathrm{1}}{\mathrm{n}}} \:=\:\frac{\mathrm{u}^{\mathrm{2}} +\mathrm{1}}{\mathrm{u}} \\ $$$$\mathrm{x}\:=\:\frac{\mathrm{u}^{\mathrm{2}} +\mathrm{1}}{\mathrm{2u}}\:\Rightarrow\:\mathrm{x}+\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\:=\:\frac{\mathrm{u}^{\mathrm{2}}…

tg-x-2-1-ctg-x-2-2sin-x-2-x-180-540-

Question Number 62982 by ANTARES VY last updated on 27/Jun/19 $$\frac{\boldsymbol{\mathrm{tg}}\left(\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\right)−\mathrm{1}}{\boldsymbol{\mathrm{ctg}}\left(\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\right)}=\mathrm{2}\boldsymbol{\mathrm{sin}}\left(\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\right)\:\:\boldsymbol{\mathrm{x}}\in\left(\mathrm{180}°;\mathrm{540}°\right) \\ $$$$ \\ $$ Answered by MJS last updated on 27/Jun/19 $$\frac{\mathrm{1}}{\mathrm{cot}}=\mathrm{tan} \\ $$$$\mathrm{tan}^{\mathrm{2}}…

Question-62981

Question Number 62981 by hovea cw last updated on 27/Jun/19 Commented by mathmax by abdo last updated on 27/Jun/19 $$\left.\mathrm{2}\right)\:{let}\:{A}\:=\int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\:\frac{{x}\mid{sin}\left(\mathrm{2}{x}\right)\mid}{\mathrm{3}+{sin}^{\mathrm{2}} {x}}\:{dx}\:{changement}\:{x}\:=\pi\:+{t}\:{give} \\ $$$${A}\:=\int_{−\pi}…