Question Number 62781 by Tawa1 last updated on 25/Jun/19 $$\int\:\mathrm{sec}\left(\mathrm{2x}\right)\:\mathrm{e}^{\mathrm{2x}} \:\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 128314 by 676597498 last updated on 06/Jan/21 $$\int_{\mathrm{0}} ^{\:\infty} \frac{\mathrm{sin}\left(\mathrm{px}\right)}{\:\sqrt{\mathrm{x}}}\:\mathrm{dx}\: \\ $$$$\forall\mathrm{p}\in\mathbb{R} \\ $$ Answered by Dwaipayan Shikari last updated on 06/Jan/21 $$\int_{\mathrm{0}}…
Question Number 62777 by James Bryan Botshabelo last updated on 25/Jun/19 $$\mathrm{5}^{\mathrm{3}{x}−\mathrm{1}} .\mathrm{4}^{\mathrm{2}{x}−\mathrm{2}} =\mathrm{625} \\ $$ Commented by kaivan.ahmadi last updated on 25/Jun/19 $$\mathrm{5}^{\mathrm{2}{x}−\mathrm{1}} .\mathrm{5}^{{x}}…
Question Number 62773 by ajfour last updated on 25/Jun/19 Commented by ajfour last updated on 25/Jun/19 $${Find}\:{maximum}\:{area}\:{of}\:{quadrilateral} \\ $$$${in}\:{yellow}\:{in}\:{terms}\:{of}\:{r}\:{and}\:{R}. \\ $$ Answered by ajfour last…
Question Number 128307 by bramlexs22 last updated on 06/Jan/21 can anyone explain the concept of negative binomial distribution? Commented by liberty last updated on 06/Jan/21…
Question Number 128303 by mr W last updated on 06/Jan/21 Commented by mr W last updated on 06/Jan/21 $${find}\:{side}\:{length}\:{s}\:{of}\:{the}\:{equilateral} \\ $$$${triangle}\:{ABC}\:{in}\:{terms}\:{of}\:{radii}\:{R} \\ $$$${and}\:{r}. \\ $$…
Question Number 62763 by naka3546 last updated on 25/Jun/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62762 by naka3546 last updated on 25/Jun/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62761 by lalitchand last updated on 25/Jun/19 $$\mathrm{if}\:\mathrm{cos}\theta=\frac{\mathrm{cosA}.\mathrm{cosB}}{\mathrm{1}−\mathrm{cosA}.\mathrm{cosB}}\:\:\:\mathrm{prove}\:\mathrm{that}\:\mathrm{Tan}\frac{\theta}{\mathrm{2}}=\mathrm{Tan}\frac{\mathrm{A}}{\mathrm{2}}.\mathrm{Cot}\frac{\mathrm{B}}{\mathrm{2}} \\ $$ Commented by Prithwish sen last updated on 25/Jun/19 $$\mathrm{I}\:\mathrm{think}\:\mathrm{it}\:\mathrm{is} \\ $$$$\mathrm{cos}\theta\:=\:\frac{\mathrm{cosA}−\mathrm{cosB}}{\mathrm{1}−\mathrm{cosAcosB}} \\ $$$$\frac{\mathrm{1}−\mathrm{cos}\theta}{\mathrm{1}+\mathrm{cos}\theta}\:=\:\frac{\mathrm{1}−\mathrm{cosA}+\mathrm{cosB}−\mathrm{cosAcosB}}{\mathrm{1}+\mathrm{cosA}−\mathrm{cosB}−\mathrm{cosAcosB}}…
Question Number 62759 by naka3546 last updated on 25/Jun/19 $${y}\:\:=\:\:{x}^{{y}} \\ $$$$\frac{{dy}}{{dx}}\:\:=\:\:? \\ $$ Answered by Kunal12588 last updated on 25/Jun/19 $${y}={x}^{{y}} \\ $$$$\Rightarrow{ln}\:{y}\:=\:{y}\:{ln}\:{x} \\…