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Give-G-is-group-and-N-Q-G-Show-that-for-x-y-G-which-xN-yQ-N-Q-

Question Number 128216 by SOMEDAVONG last updated on 05/Jan/21 $$\mathrm{Give}\:\mathrm{G}\:\mathrm{is}\:\mathrm{group}\:\mathrm{and}\:\mathrm{N},\mathrm{Q}\leqslant\mathrm{G}.\mathrm{Show}\:\mathrm{that}\: \\ $$$$\mathrm{for}\:\mathrm{x},\mathrm{y}\in\mathrm{G}\:\mathrm{which}\:\mathrm{xN}=\mathrm{yQ}\Rightarrow\mathrm{N}=\mathrm{Q}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Let-f-be-defined-in-the-neighborhood-of-x-and-that-f-x-exists-Prove-that-lim-h-0-f-x-h-f-x-h-2f-x-h-2-f-x-

Question Number 62679 by ajfour last updated on 24/Jun/19 $${Let}\:{f}\:{be}\:{defined}\:{in}\:{the}\:{neighborhood} \\ $$$${of}\:{x}\:{and}\:{that}\:{f}\:''\left({x}\right)\:{exists}. \\ $$$${Prove}\:{that}\:\: \\ $$$$\:\underset{{h}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{f}\left({x}+{h}\right)+{f}\left({x}−{h}\right)−\mathrm{2}{f}\left({x}\right)}{{h}^{\mathrm{2}} }={f}\:''\left({x}\right)\:. \\ $$ Commented by kaivan.ahmadi last updated…

Question-62676

Question Number 62676 by bshahid010@gmail.com last updated on 24/Jun/19 Commented by kaivan.ahmadi last updated on 24/Jun/19 $${if}\:{tanx}={n}>\mathrm{0}\Rightarrow \\ $$$${n}^{\mathrm{2}} +{an}+{n}+{a}−\mathrm{3}<\mathrm{0}\Rightarrow{a}\left({n}+\mathrm{1}\right)<\mathrm{3}−{n}^{\mathrm{2}} −{n}\Rightarrow \\ $$$${a}<\frac{\mathrm{3}−{n}−{n}^{\mathrm{2}} }{{n}+\mathrm{1}} \\…

Let-x-y-z-be-pairwise-distinct-real-numbers-if-x-y-7-z-x-y-24-y-z-7-x-y-z-24-z-x-7-y-z-x-24-Find-x-2-y-2-

Question Number 128204 by I want to learn more last updated on 05/Jan/21 $$\mathrm{Let}\:\:\:\mathrm{x},\:\:\mathrm{y},\:\:\mathrm{z}\:\:\:\mathrm{be}\:\mathrm{pairwise}\:\mathrm{distinct}\:\mathrm{real}\:\mathrm{numbers},\:\mathrm{if} \\ $$$$\:\:\left(\mathrm{x}\:\:+\:\:\mathrm{y}\:\:−\:\:\mathrm{7}\right)\left[\mathrm{z}\left(\mathrm{x}\:\:+\:\:\mathrm{y}\right)\:\:+\:\:\mathrm{24}\right]\:\:\:=\:\:\left(\mathrm{y}\:\:+\:\:\mathrm{z}\:\:−\:\:\mathrm{7}\right)\left[\mathrm{x}\left(\mathrm{y}\:\:+\:\:\mathrm{z}\right)\:\:+\:\:\mathrm{24}\right]\:\:\:=\:\:\:\left(\mathrm{z}\:\:+\:\:\mathrm{x}\:\:−\:\:\mathrm{7}\right)\left[\mathrm{y}\left(\mathrm{z}\:\:+\:\:\mathrm{x}\right)\:\:+\:\:\mathrm{24}\right] \\ $$$$\mathrm{Find}\:\:\:\:\:\mathrm{x}^{\mathrm{2}} \:\:+\:\:\mathrm{y}^{\mathrm{2}} \:\:+\:\:\mathrm{z}^{\mathrm{2}} \\ $$ Terms of Service…