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Author: Tinku Tara

Prove-that-the-area-of-any-quadrilateral-ABCD-is-s-a-s-b-s-c-s-d-abcd-cos-2-A-C-2-

Question Number 128178 by bemath last updated on 05/Jan/21 $$\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{any}\: \\ $$$$\mathrm{quadrilateral}\:\mathrm{ABCD}\:\mathrm{is}\: \\ $$$$\:\sqrt{\left(\mathrm{s}−\mathrm{a}\right)\left(\mathrm{s}−\mathrm{b}\right)\left(\mathrm{s}−\mathrm{c}\right)\left(\mathrm{s}−\mathrm{d}\right)−\mathrm{abcd}\:\mathrm{cos}\:^{\mathrm{2}} \left(\frac{\mathrm{A}+\mathrm{C}}{\mathrm{2}}\right)}\:. \\ $$ Answered by mr W last updated on 05/Jan/21…

show-me-that-y-x-2-4x-6-is-the-solution-of-y-y-2-x-1-0-

Question Number 128179 by bounhome last updated on 05/Jan/21 $${show}\:{me}\:{that}\:{y}={x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{6}\:{is}\:{the}\:{solution}\:{of} \\ $$$${y}''−{y}'+\mathrm{2}\left({x}+\mathrm{1}\right)=\mathrm{0} \\ $$ Answered by bemath last updated on 05/Jan/21 $$\:\mathrm{y}=\mathrm{x}^{\mathrm{2}} +\mathrm{4x}−\mathrm{6}\:\rightarrow\begin{cases}{\mathrm{y}'=\mathrm{2x}+\mathrm{4}}\\{\mathrm{y}''=\mathrm{2}}\end{cases} \\…

Given-t-x-ax-4-bx-2-x-5-where-a-and-b-are-constant-If-t-4-3-then-t-4-

Question Number 128176 by liberty last updated on 05/Jan/21 $$\mathrm{Given}\:\mathrm{t}\left(\mathrm{x}\right)=\mathrm{ax}^{\mathrm{4}} +\mathrm{bx}^{\mathrm{2}} +\mathrm{x}+\mathrm{5}\:;\:\mathrm{where}\:\mathrm{a}\:\mathrm{and}\:\mathrm{b} \\ $$$$\mathrm{are}\:\mathrm{constant}.\:\mathrm{If}\:\mathrm{t}\left(−\mathrm{4}\right)=\mathrm{3}\:\mathrm{then}\:\mathrm{t}\left(\mathrm{4}\right)=? \\ $$ Answered by bemath last updated on 05/Jan/21 $$\left(\Rightarrow\right)\:\mathrm{t}\left(\mathrm{x}\right)=\mathrm{ax}^{\mathrm{4}} +\mathrm{bx}^{\mathrm{2}}…

Question-128172

Question Number 128172 by shaker last updated on 05/Jan/21 Commented by mr W last updated on 05/Jan/21 $${you}\:{can}\:{only}\:“{see}''\:{the}\:{solution}: \\ $$$${x}=\mathrm{0},\:{y}=\mathrm{1},\:{z}=\mathrm{2} \\ $$$$\left({x},\:{y},\:{z}\:{are}\:{interchangeable}\right) \\ $$$$ \\…

x-2-x-3-4x-1-10-for-x-R-

Question Number 128166 by bramlexs22 last updated on 05/Jan/21 $$\:\sqrt{\mathrm{x}−\mathrm{2}}\:+\:\sqrt{\mathrm{x}+\mathrm{3}}\:+\sqrt{\mathrm{4x}+\mathrm{1}}\:=\:\mathrm{10} \\ $$$$\:\mathrm{for}\:\mathrm{x}\in\mathbb{R}\: \\ $$ Answered by liberty last updated on 05/Jan/21 $$\:\sqrt{\mathrm{4x}+\mathrm{1}}\:=\:\left[\:−\sqrt{\mathrm{x}+\mathrm{3}}−\sqrt{\mathrm{x}−\mathrm{2}}+\mathrm{10}\:\right] \\ $$$$\:\mathrm{4x}+\mathrm{1}\:=\:\mathrm{2}\sqrt{\mathrm{x}−\mathrm{2}\:}\:\sqrt{\mathrm{x}+\mathrm{3}}\:−\mathrm{20}\sqrt{\mathrm{x}+\mathrm{3}}\:+\mathrm{2x}\:−\mathrm{20}\sqrt{\mathrm{x}−\mathrm{2}}\:+\mathrm{101} \\…