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Author: Tinku Tara

lim-n-a-1-n-b-1-n-2-n-a-b-R-

Question Number 127961 by bramlexs22 last updated on 03/Jan/21 $$\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\sqrt[{\mathrm{n}}]{\mathrm{a}}\:+\:\sqrt[{\mathrm{n}}]{\mathrm{b}}}{\mathrm{2}}\:\right)^{\mathrm{n}} \:=\:?\: \\ $$$$\:\mathrm{a},\:\mathrm{b}\:\in\mathbb{R}\: \\ $$ Answered by liberty last updated on 03/Jan/21 $$\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\left(\frac{\sqrt[{\mathrm{n}}]{\mathrm{a}}\:+\sqrt[{\mathrm{n}}]{\mathrm{b}}}{\mathrm{2}}\right)^{\mathrm{n}}…

Question-62424

Question Number 62424 by aliesam last updated on 21/Jun/19 Commented by mathmax by abdo last updated on 21/Jun/19 $$\mathrm{1}\:{is}\:{not}\:{root}\:{for}\:{this}\:{equatio}\: \\ $$$$\left({e}\right)\:\Leftrightarrow\frac{\mathrm{1}−{x}^{\mathrm{5}} }{\mathrm{1}−{x}}\:=\mathrm{0}\:\Leftrightarrow\:{x}^{\mathrm{5}} \:=\mathrm{1}\:\:{let}\:{x}\:={re}^{{i}\theta} \:\:\:\:\:\left(\:\:{we}\:{take}\:{x}\:{from}\:{C}\right) \\…

let-u-n-x-1-n-x-n-n-1-dt-t-x-with-x-1-2-1-prove-that-0-u-n-x-1-n-x-1-n-1-x-n-gt-0-2-prove-that-u-n-x-converges-let-n-1-u-n-1-3-find-n-1-u-n-x-i

Question Number 62420 by mathsolverby Abdo last updated on 20/Jun/19 $${let}\:{u}_{{n}} \left({x}\right)=\frac{\mathrm{1}}{{n}^{{x}} }\:−\int_{{n}} ^{{n}+\mathrm{1}} \frac{{dt}}{{t}^{{x}} }\:\:{with}\:{x}\in\left[\mathrm{1},\mathrm{2}\right] \\ $$$$\left.\mathrm{1}\right){prove}\:{that}\:\mathrm{0}\leqslant\:{u}_{{n}} \left({x}\right)\leqslant\frac{\mathrm{1}}{{n}^{{x}} }−\frac{\mathrm{1}}{\left({n}+\mathrm{1}\right)^{{x}} }\:\left({n}>\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){prove}\:{that}\:\Sigma\:{u}_{{n}} \left({x}\right){converges} \\…

Question-127952

Question Number 127952 by rs4089 last updated on 03/Jan/21 Answered by Ar Brandon last updated on 03/Jan/21 $$\Psi=\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{x}^{\mathrm{2}} \sqrt{\frac{\mathrm{1}−\mathrm{x}^{\mathrm{2}} }{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }}\mathrm{dx}=\int_{\mathrm{0}} ^{\mathrm{1}} \left\{\frac{\mathrm{x}^{\mathrm{2}}…