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Author: Tinku Tara

dx-x-3-x-5-1-3-1-5-

Question Number 127851 by bemath last updated on 02/Jan/21 $$\:\psi\:=\:\int\:\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{3}} \:\sqrt[{\mathrm{5}}]{\left(\mathrm{x}^{\mathrm{5}} +\mathrm{1}\right)^{\mathrm{3}} }}\:?\: \\ $$ Answered by liberty last updated on 02/Jan/21 $$\:\psi\:=\:\int\:\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{3}} \:\sqrt[{\mathrm{5}}]{\mathrm{x}^{\mathrm{15}} \left(\mathrm{1}+\mathrm{x}^{−\mathrm{5}}…

6-3-2-6-3-2-

Question Number 127848 by Study last updated on 02/Jan/21 $$\mathrm{6}\boldsymbol{\div}\mathrm{3}\left(\mathrm{2}\right)=? \\ $$$$\mathrm{6}\boldsymbol{\div}\mathrm{3}\centerdot\mathrm{2}=? \\ $$ Commented by AgnibhoMukhopadhyay last updated on 02/Jan/21 $$\left.\mathrm{1}\right)\:\mathrm{6}\boldsymbol{\div}\mathrm{3}\left(\mathrm{2}\right) \\ $$$$=\:\mathrm{6}\boldsymbol{\div}\mathrm{3}\:{or}\:\mathrm{2} \\…

lim-x-0-x-3-sin-1-x-sin-2-x-

Question Number 127846 by bemath last updated on 02/Jan/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{x}^{\mathrm{3}} \:\mathrm{sin}\:\left(\frac{\mathrm{1}}{\mathrm{x}}\right)}{\mathrm{sin}\:^{\mathrm{2}} \left(\mathrm{x}\right)}\:?\: \\ $$ Commented by Dwaipayan Shikari last updated on 02/Jan/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{xsin}\left(\frac{\mathrm{1}}{{x}}\right)}{{sin}^{\mathrm{2}}…

Question-62308

Question Number 62308 by aliesam last updated on 19/Jun/19 Commented by maxmathsup by imad last updated on 20/Jun/19 $${x}^{\mathrm{2}} −\mathrm{2}{x}\:\:+\mathrm{2}\:=\mathrm{0}\:\rightarrow\Delta^{'} \:=\mathrm{1}−\mathrm{2}\:=−\mathrm{1}\:={i}^{\mathrm{2}} \:\Rightarrow\alpha\:=\mathrm{1}+{i}\:\:{and}\:\beta\:=\mathrm{1}−{i}\:=\overset{−} {\alpha}\:\Rightarrow \\ $$$$\alpha^{{n}}…

if-0-1-ln-1-2-x-x-1-2-2-x-2-x-2-1-dx-find-Re-Im-

Question Number 127839 by mnjuly1970 last updated on 02/Jan/21 $$\:\:\: \\ $$$${if}\:\:\Omega\:=\int_{\mathrm{0}} ^{\:\mathrm{1}} {ln}\left(\frac{\Gamma\left(\frac{\mathrm{1}}{\mathrm{2}}−{x}\right)\Gamma\left({x}−\frac{\mathrm{1}}{\mathrm{2}}\right)}{\Gamma\left(\mathrm{2}−\frac{{x}}{\mathrm{2}}\right)\left(\frac{{x}}{\mathrm{2}}−\mathrm{1}\right)}\right){dx} \\ $$$$\:\:{find}\:\:\:\:\frac{{Re}\left(\Omega\right)}{{Im}\left(\Omega\right)}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

If-k-1-10-cos-kpi-11-2-n-then-n-

Question Number 127835 by bemath last updated on 02/Jan/21 $$\:\mathrm{If}\:\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{10}} {\prod}}\:\mathrm{cos}\:\left(\frac{\mathrm{k}\pi}{\mathrm{11}}\right)\:=\:−\mathrm{2}^{\mathrm{n}} \:,\:\mathrm{then}\:\mathrm{n}\:=\:? \\ $$$$ \\ $$ Answered by liberty last updated on 02/Jan/21 $$\:\mathrm{let}\:\mathrm{Y}\:=\:\mathrm{cos}\:\mathrm{x}\:\mathrm{cos}\:\mathrm{2x}\:\mathrm{cos}\:\mathrm{3x}\:\mathrm{cos}\:\mathrm{4x}\:…

Question-127833

Question Number 127833 by Algoritm last updated on 02/Jan/21 Answered by mathmax by abdo last updated on 02/Jan/21 $$\mathrm{I}\:=\int_{\mathrm{0}} ^{\mathrm{4}} \:\frac{\mathrm{cosx}}{\:\sqrt{\mathrm{4}−\mathrm{x}}}\mathrm{dx}\:\mathrm{we}\:\mathrm{do}\:\mathrm{the}\:\mathrm{changement}\:\sqrt{\mathrm{4}−\mathrm{x}}=\mathrm{t}\:\Rightarrow\mathrm{4}−\mathrm{x}=\mathrm{t}^{\mathrm{2}} \\ $$$$\mathrm{I}\:=\int_{\mathrm{2}} ^{\mathrm{0}} \:\frac{\mathrm{cos}\left(\mathrm{4}−\mathrm{t}^{\mathrm{2}}…

Question-62291

Question Number 62291 by rajesh4661kumar@gamil.com last updated on 19/Jun/19 Commented by maxmathsup by imad last updated on 19/Jun/19 $$\Rightarrow\left({e}^{{x}} −\mathrm{1}\right){e}^{{y}} \:={e}^{{x}} \:\Rightarrow{e}^{{y}} \:=\frac{{e}^{{x}} }{{e}^{{x}} −\mathrm{1}}\:\Rightarrow{y}\:={ln}\left(\frac{{e}^{{x}}…

Question-62289

Question Number 62289 by naka3546 last updated on 19/Jun/19 Answered by MJS last updated on 19/Jun/19 $$\mathrm{we}\:\mathrm{have} \\ $$$${A}_{\mathrm{1}} =\mathrm{3}=\frac{\mathrm{1}}{\mathrm{2}}×{a}×{x}\:\Rightarrow\:{x}=\frac{\mathrm{6}}{{a}} \\ $$$${A}_{\mathrm{2}} =\mathrm{5}=\frac{\mathrm{1}}{\mathrm{2}}×{b}×{y}\:\Rightarrow\:{y}=\frac{\mathrm{10}}{{b}} \\ $$$$\mathrm{side}\:\mathrm{of}\:\mathrm{triangle}\:=\:{c}…