Question Number 210912 by Tawa11 last updated on 21/Aug/24 A uniform stick AB of length L and mass M is balanced horizontally on a knife…
Question Number 210896 by MrGHK last updated on 21/Aug/24 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\overset{−} {{H}}_{{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)^{{q}} }=?? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 210875 by peter frank last updated on 20/Aug/24 Answered by mahdipoor last updated on 20/Aug/24 $${get}\:{time}\:{is}\:{h}\::\:{m}\:\&\:{vertical}\:{line}\:{is}\:{refrence} \\ $$$${angle}\:{huur\_hand}\::\:\frac{\mathrm{360}}{\mathrm{12}}{h}+\frac{\mathrm{360}}{\mathrm{12}×\mathrm{60}}{m} \\ $$$${angle}\:{minute\_hand}\::\:\frac{\mathrm{360}}{\mathrm{60}}{m} \\ $$$$\Rightarrow\angle=\mid{h}−{m}\mid=\mid\mathrm{30}{h}−\mathrm{5}.\mathrm{5}{m}\mid\:{or}\:\mathrm{360}−\mid\mathrm{30}{h}−\mathrm{5}.\mathrm{5}{m}\mid \\…
Question Number 210868 by universe last updated on 20/Aug/24 $$\mathrm{let}\:\mathrm{p}\:,\mathrm{q}\:\mathrm{be}\:\mathrm{reals}\:\mathrm{such}\:\mathrm{that}\:\mathrm{p}>\mathrm{q}>\mathrm{0}\:\mathrm{define} \\ $$$$\mathrm{the}\:\mathrm{sequence}\:\left\{\mathrm{x}_{\mathrm{n}} \right\}\:\mathrm{where}\:\mathrm{x}_{\mathrm{1}} =\:\mathrm{p}+\mathrm{q}\:\mathrm{and} \\ $$$$\mathrm{x}_{\mathrm{n}} \:=\:\mathrm{x}_{\mathrm{1}} −\frac{\mathrm{pq}}{\mathrm{x}_{\mathrm{n}−\mathrm{1}} }\:\mathrm{for}\:\mathrm{n}\geqslant\mathrm{2}\:\mathrm{for}\:\mathrm{all}\:\mathrm{n}\:\mathrm{then}\:\mathrm{x}_{\mathrm{n}} \:=\:?? \\ $$ Commented by Ghisom…
Question Number 210870 by hardmath last updated on 20/Aug/24 $$\mathrm{8x}^{\mathrm{2}} \:−\:\mathrm{13x}\:+\:\mathrm{11}\:=\:\frac{\mathrm{2}}{\mathrm{x}}\:+\:\left(\mathrm{1}\:+\:\frac{\mathrm{3}}{\mathrm{x}}\right)\:\sqrt[{\mathrm{3}}]{\mathrm{3x}^{\mathrm{2}} −\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{x}}\:=\:? \\ $$ Commented by Ghisom last updated on 20/Aug/24 $$\mathrm{obviously}\:{x}=\mathrm{1} \\…
Question Number 210871 by hardmath last updated on 20/Aug/24 $$\mathrm{7}\left(\mathrm{x}−\mathrm{2}\right)\left(\sqrt{\mathrm{10}\:+\:\mathrm{x}}\:−\:\sqrt[{\mathrm{3}}]{\mathrm{7}−\mathrm{x}}\right)−\mathrm{15x}\:+\:\mathrm{6}\:=\:\mathrm{0} \\ $$$$\boldsymbol{\mathrm{x}}\:=\:? \\ $$ Commented by Ghisom last updated on 20/Aug/24 $$\mathrm{obviously}\:{x}=−\mathrm{1} \\ $$ Terms…
Question Number 210858 by hardmath last updated on 20/Aug/24 $$\mathrm{Solve}\:\mathrm{The}\:\mathrm{Equation}: \\ $$$$\left(\mathrm{7x}+\mathrm{1}\right)\left(\mathrm{9x}+\mathrm{1}\right)\left(\mathrm{21x}+\mathrm{1}\right)\left(\mathrm{63x}+\mathrm{1}\right)=\:\frac{\mathrm{160}}{\mathrm{189}} \\ $$ Answered by mm1342 last updated on 20/Aug/24 $$\left(\mathrm{63}{x}+\mathrm{9}\right)\left(\mathrm{63}{x}+\mathrm{7}\right)\left(\mathrm{63}{x}+\mathrm{3}\right)\left(\mathrm{63}{x}+\mathrm{1}\right)=\mathrm{160} \\ $$$$\mathrm{63}{x}+\mathrm{5}={u} \\…
Question Number 210855 by zhou0429 last updated on 20/Aug/24 Answered by Frix last updated on 20/Aug/24 $${x},\:{y}\:>\mathrm{0}\:\wedge\:{x}\neq{y} \\ $$$${x}\mathrm{ln}\:{x}\:={y}\mathrm{ln}\:{y} \\ $$$$\mathrm{Let}\:{y}={px}\wedge{p}>\mathrm{0}\wedge{p}\neq\mathrm{1} \\ $$$${x}\mathrm{ln}\:{x}\:={px}\mathrm{ln}\:{px} \\ $$$$\mathrm{ln}\:{x}\:={p}\mathrm{ln}\:{p}\:+{p}\mathrm{ln}\:{x}…