Question Number 62102 by rajesh4661kumar@gamil.com last updated on 15/Jun/19 Answered by Kunal12588 last updated on 15/Jun/19 $$\sqrt{\mathrm{1}−{x}^{\mathrm{6}} }+\sqrt{\mathrm{1}−{y}^{\mathrm{6}} }=\mathrm{9}\left({x}^{\mathrm{3}} −{y}^{\mathrm{3}} \right) \\ $$$$\Rightarrow\frac{−\mathrm{6}{x}^{\mathrm{5}} }{\mathrm{2}\sqrt{\mathrm{1}−{x}^{\mathrm{6}} }}+\frac{−\mathrm{6}{y}^{\mathrm{5}}…
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Question Number 127633 by naka3546 last updated on 31/Dec/20 Commented by naka3546 last updated on 31/Dec/20 $${ABC}\:\:{is}\:\:{an}\:\:{equilateral}\:\:{triangle}\:. \\ $$$${Find}\:\:{area}\:\:{of}\:\:{ABC}\:! \\ $$ Commented by mr W…
Question Number 62096 by Tawa1 last updated on 15/Jun/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 127631 by snipers237 last updated on 31/Dec/20 $${Let}\:{f}\in{C}^{\infty} \left(\mathbb{R},\mathbb{R}\right)\:,\:\forall\:{n}\in\mathbb{N}\:\:\:{M}_{{n}} =\mid\mid{f}^{\left({n}\right)} \mid\mid_{\infty} \:\: \\ $$$${and}\:\:{u}_{{n}} =\frac{\mathrm{2}^{{n}−\mathrm{1}} {M}_{{n}} }{{M}_{{n}−\mathrm{1}} }\:\:\:{for}\:{n}\geqslant\mathrm{1}\: \\ $$$${Show}\:{that}\:{if}\:\:\:{M}_{\mathrm{1}} <\sqrt{\mathrm{2}{M}_{\mathrm{0}} {M}_{\mathrm{2}} }\:{then}\:{u}_{{n}}…
Question Number 62094 by Tawa1 last updated on 15/Jun/19 Commented by mr W last updated on 15/Jun/19 $${too}\:{less}\:{information}\:{to}\:{determine}\:\angle{C}! \\ $$$${with}\:{given}\:{conditions}\:{point}\:{C}\:{could} \\ $$$${be}\:{at}\:{any}\:{position}\:{on}\:{line}\:{AB}. \\ $$ Commented…
Question Number 62093 by naka3546 last updated on 15/Jun/19 $$\int\:\:\frac{{dx}}{\mathrm{sin}^{\mathrm{3}} \:{x}\:+\:\mathrm{cos}^{\mathrm{3}} \:{x}}\:\:=\:\:{p} \\ $$ Commented by MJS last updated on 15/Jun/19 $$\mathrm{Weierstrass}\:\mathrm{Substitution} \\ $$$$\int\frac{{dx}}{\mathrm{sin}^{\mathrm{3}} \:{x}\:+\mathrm{cos}^{\mathrm{3}}…
Question Number 62092 by Cypher1207 last updated on 15/Jun/19 $$\mathrm{MATH}\:\mathrm{MEME}: \\ $$$$\mathrm{3}+\mathrm{x}\:=\:\mathrm{1}+\mathrm{8} \\ $$$$\left.:\right) \\ $$$$\frac{\mathrm{3}+\mathrm{x}}{+}\:=\:\frac{\mathrm{1}+\mathrm{8}}{+} \\ $$$${cancel}\:{the}\:{plus}\:{sign} \\ $$$$\mathrm{3}{x}\:=\:\mathrm{18} \\ $$$$\frac{\mathrm{3}{x}}{\mathrm{3}}\:=\:\frac{\mathrm{18}}{\mathrm{3}} \\ $$$$\boldsymbol{{x}}\:=\:\mathrm{6} \\…
Question Number 62088 by Cypher1207 last updated on 15/Jun/19 Commented by Cypher1207 last updated on 15/Jun/19 $$\left({very}\right)^{\mathrm{2}} {easy}…. \\ $$ Commented by maxmathsup by imad…
Question Number 127618 by bramlexs22 last updated on 31/Dec/20 $$\:\int\:\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{2021}} \left(\mathrm{1}+\mathrm{x}^{\mathrm{2020}} \right)}\:?\: \\ $$ Answered by Dwaipayan Shikari last updated on 31/Dec/20 $$\int\frac{\mathrm{1}}{{x}^{\mathrm{2021}} }−\frac{\mathrm{1}}{{x}\left(\mathrm{1}+{x}^{\mathrm{2020}} \right)}{dx}=−\frac{{x}^{−\mathrm{2020}}…