Question Number 127616 by bramlexs22 last updated on 31/Dec/20 $$\:\mathrm{If}\:\int_{\mathrm{1}} ^{\:\mathrm{4}} \mathrm{f}\left(\mathrm{x}\right)\:\mathrm{dx}\:=\:\mathrm{6}\:,\:\mathrm{then}\:\int_{\mathrm{1}} ^{\:\mathrm{4}} \mathrm{f}\left(\mathrm{5}−\mathrm{x}\right)\:\mathrm{dx}\:?\: \\ $$ Commented by liberty last updated on 31/Dec/20 $$\:\mathrm{let}\:\mathrm{5}−\mathrm{x}\:=\:\mathrm{X}\:\Rightarrow\mathrm{dx}\:=\:−\mathrm{dX}\: \\…
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Question Number 62077 by naka3546 last updated on 15/Jun/19 $$\underset{\:\:\mathrm{1}} {\overset{\:\:\:\:\:\:\:\:\:\:\:\:\infty} {\int}}\:\left(\frac{\mathrm{ln}\:{x}}{{x}}\right)^{\mathrm{2018}} \:{dx}\:\:=\:\:? \\ $$$${Any}\:\:{trick}\left({s}\right)\:\:{to}\:\:{solve}\:\:{it}\:? \\ $$ Answered by Smail last updated on 15/Jun/19 $${I}_{{n}}…
Question Number 127610 by pticantor last updated on 31/Dec/20 $$\boldsymbol{{Z}}=\mathrm{1}+\left(\mathrm{1}+{i}\right)\boldsymbol{{cos}\theta} \\ $$$$\boldsymbol{{arg}}\left(\boldsymbol{{z}}\right)=? \\ $$ Answered by MJS_new last updated on 31/Dec/20 $$\mathrm{arg}\:\left(\mathrm{1}+\mathrm{cos}\:\theta\:+\mathrm{i}\:\mathrm{cos}\:\theta\right)\:= \\ $$$$=\frac{\pi}{\mathrm{2}}\mathrm{sign}\:\left(\mathrm{cos}\:\theta\right)\:−\mathrm{arctan}\:\frac{\mathrm{1}+\mathrm{cos}\:\theta}{\mathrm{cos}\:\theta} \\…
Question Number 127607 by bramlexs22 last updated on 31/Dec/20 Answered by liberty last updated on 31/Dec/20 $$\:\mathrm{A}\:\Rightarrow\mathrm{24}\:\mathrm{days}\: \\ $$$$\:\mathrm{B}\:\Rightarrow\:\mathrm{15}\:\mathrm{days} \\ $$$$\:\mathrm{C}\Rightarrow\:\mathrm{12}\:\mathrm{days} \\ $$$$\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{started}\:\mathrm{worked}\:\mathrm{3}\:\mathrm{days}\:\Rightarrow\:\mathrm{3}×\left(\frac{\mathrm{1}}{\mathrm{15}}+\frac{\mathrm{1}}{\mathrm{12}}\right)\:\mathrm{work} \\ $$$$\:\Rightarrow\frac{\mathrm{1}}{\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{4}}\:=\:\frac{\mathrm{9}}{\mathrm{20}}\:\mathrm{works}\:…
Question Number 127604 by Algoritm last updated on 31/Dec/20 Answered by Lordose last updated on 31/Dec/20 Commented by Algoritm last updated on 31/Dec/20 $$? \\…
Question Number 127605 by pticantor last updated on 31/Dec/20 $${find}\:{arg}\left({z}\right) \\ $$$${where}\:\boldsymbol{{z}}=\mathrm{1}+\boldsymbol{{cos}}\alpha+{icos}\beta \\ $$ Answered by MJS_new last updated on 31/Dec/20 $$\mathrm{arg}\:\left(\mathrm{1}+\mathrm{cos}\:\alpha\:+\mathrm{i}\:\mathrm{cos}\:\beta\right)\:= \\ $$$$=\frac{\pi}{\mathrm{2}}\mathrm{sign}\:\left(\mathrm{cos}\:\beta\right)\:−\mathrm{arctan}\:\frac{\mathrm{1}+\mathrm{cos}\:\alpha}{\mathrm{cos}\:\beta} \\…
Question Number 62067 by naka3546 last updated on 15/Jun/19 $$\underset{{x}\:\rightarrow\:−\mathrm{1}} {\mathrm{lim}}\:\:\frac{{x}^{\mathrm{3}} \:+\:\mathrm{2}{x}^{\mathrm{2}} \:−\:\mathrm{1}}{\left({x}\:+\:\mathrm{1}\right)^{\mathrm{2}} }\:\:=\:\:? \\ $$ Commented by gunawan last updated on 15/Jun/19 $$\underset{{x}\rightarrow−\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{3}{x}^{\mathrm{2}}…
Question Number 62057 by hhghg last updated on 14/Jun/19 $$\mathrm{2}^{−\mathrm{2}} \\ $$ Commented by gunawan last updated on 15/Jun/19 $$\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }=\frac{\mathrm{1}}{\mathrm{4}} \\ $$ Commented by…
Question Number 62056 by maxmathsup by imad last updated on 14/Jun/19 $$\left.\mathrm{1}\right)\:{calculate}\:{I}\:=\int{ln}\left(\mathrm{1}+{ix}^{\mathrm{2}} \right){dx}\:{and}\:{J}\:=\:\int{ln}\left(\mathrm{1}−{ix}^{\mathrm{2}} \right){dx} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{A}\:=\int\:{ln}\left(\mathrm{1}+{x}^{\mathrm{4}} \right){dx}\:. \\ $$ Terms of Service Privacy Policy Contact:…