Question Number 62055 by hhghg last updated on 14/Jun/19 $$\$\mathrm{8}+\$\mathrm{3} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62054 by hhghg last updated on 14/Jun/19 $$\mathrm{484}×\mathrm{27} \\ $$ Commented by Tony Lin last updated on 15/Jun/19 $$=\mathrm{11}^{\mathrm{2}} ×\mathrm{6}^{\mathrm{2}} ×\mathrm{3} \\ $$$$=\left(\mathrm{108}×\mathrm{11}\right)×\mathrm{11}…
Question Number 62053 by hhghg last updated on 14/Jun/19 $$\mathrm{m5}=\mathrm{25} \\ $$ Commented by meme last updated on 15/Jun/19 $${m}=\mathrm{5} \\ $$$$ \\ $$ Terms…
Question Number 127589 by bramlexs22 last updated on 31/Dec/20 Answered by liberty last updated on 31/Dec/20 $$\left(\bullet\right)\:\mathrm{let}\:\mathrm{y}'=\mathrm{z}\:\Rightarrow\:\mathrm{xz}'\:+\:\mathrm{z}\:=\:\mathrm{3x}^{\mathrm{2}} −\mathrm{x}\: \\ $$$$\:\:\:\:\frac{\mathrm{d}}{\mathrm{dx}}\:\left(\mathrm{xz}\right)\:=\:\mathrm{3x}^{\mathrm{2}} −\mathrm{x}\: \\ $$$$\:\:\:\mathrm{xz}\:=\:\mathrm{x}^{\mathrm{3}} −\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}^{\mathrm{2}} \:+\mathrm{C}_{\mathrm{1}}…
Question Number 62052 by hhghg last updated on 14/Jun/19 $$\mathrm{3}\frac{\mathrm{1}}{\mathrm{4}}−\frac{\mathrm{3}}{\mathrm{4}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\frac{\mathrm{3}}{\mathrm{4}}−\frac{\mathrm{3}}{\mathrm{4}}=\mathrm{0} \\ $$ Terms…
Question Number 62051 by hhghg last updated on 14/Jun/19 $$\frac{\mathrm{7}^{\mathrm{5}} }{\mathrm{7}^{\mathrm{3}} } \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\mathrm{7}^{\mathrm{5}−\mathrm{3}} \:=\mathrm{7}^{\mathrm{2}}…
Question Number 127587 by bramlexs22 last updated on 31/Dec/20 Answered by ebi last updated on 31/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62050 by hhghg last updated on 14/Jun/19 $$\left[\mathrm{3}×\mathrm{5}+\mathrm{3}\right]+\left[\mathrm{3}+\left(\mathrm{3}×\mathrm{2}\right)\right] \\ $$ Commented by meme last updated on 15/Jun/19 $$=\mathrm{18}+\mathrm{9} \\ $$$$=\mathrm{27} \\ $$ Terms…
Question Number 62049 by hhghg last updated on 14/Jun/19 $$\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{5}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\frac{\left(\mathrm{1}×\mathrm{5}\right)+\left(\mathrm{4}×\mathrm{1}\right)}{\mathrm{4}×\mathrm{5}}\:=\frac{\mathrm{5}+\mathrm{4}}{\mathrm{20}}\:=\frac{\mathrm{9}}{\mathrm{20}} \\ $$ Terms…
Question Number 62048 by hhghg last updated on 14/Jun/19 $$\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{3}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\frac{\mathrm{1}^{\mathrm{3}} }{\mathrm{2}^{\mathrm{3}} }\:=\frac{\mathrm{1}}{\mathrm{8}} \\…