Question Number 62047 by hhghg last updated on 14/Jun/19 $$\left(\mathrm{4y}\right)^{\mathrm{2}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\left(\mathrm{4}{y}\right)×\left(\mathrm{4}{y}\right)\:=\mathrm{16}{y}^{\mathrm{2}} \\ $$ Terms…
Question Number 127583 by denizus last updated on 31/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62046 by hhghg last updated on 14/Jun/19 $$\mathrm{4}×\left(\mathrm{3}+\mathrm{2}−\mathrm{3}\right) \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\mathrm{4}×\left(\mathrm{5}−\mathrm{3}\right)\:=\mathrm{4}×\mathrm{2}\:=\mathrm{8} \\ $$ Terms…
Question Number 62045 by hovea cw last updated on 14/Jun/19 $$\mathrm{help} \\ $$$$ \\ $$$$\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{1}/\mathrm{2}} +\left(\mathrm{x}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{1}/\mathrm{3}} =\mathrm{4} \\ $$$$\mathrm{find}\:\mathrm{x} \\ $$ Answered by MJS…
Question Number 127578 by bramlexs22 last updated on 31/Dec/20 $$\:\mathrm{y}\:''\:=\:\mathrm{5y}−\mathrm{10y}^{\mathrm{2}} \\ $$$$\:\mathrm{y}\left(\mathrm{0}\right)\:=\:\mathrm{1} \\ $$ Answered by mr W last updated on 31/Dec/20 $${y}''=\frac{{dy}'}{{dx}}={y}'\frac{{dy}'}{{dy}} \\ $$$${y}'\frac{{dy}'}{{dy}}=\mathrm{5}{y}−\mathrm{10}{y}^{\mathrm{2}}…
Question Number 62041 by mr W last updated on 14/Jun/19 Commented by mr W last updated on 14/Jun/19 $${i}\:{use}\:{these}\:{formulas}\:{to}\:{get}\:{real}\:{roots} \\ $$$${of}\:{cubic}\:{equations}. \\ $$$${maybe}\:{useful}\:{also}\:{for}\:{you}. \\ $$…
Question Number 127575 by Ar Brandon last updated on 30/Dec/20 $$\mathrm{I}_{\mathrm{n}} =\int_{\mathrm{0}} ^{\mathrm{1}} \left(\mathrm{1}−\mathrm{t}^{\mathrm{2}} \right)^{\mathrm{n}} \mathrm{dt} \\ $$ Answered by Ar Brandon last updated on…
Question Number 127572 by mathocean1 last updated on 30/Dec/20 $$\mid\mathrm{1}+{iz}_{\mathrm{0}} \mid=\mid\mathrm{1}−{iz}_{\mathrm{0}} \mid \\ $$$${show}\:{that}\:{z}_{\mathrm{0}} \in\mathbb{R} \\ $$ Answered by mathmax by abdo last updated on…
Question Number 62037 by amingolkar20@gmail.com last updated on 14/Jun/19 $$\mathrm{3}{no}_{\mathrm{2}} +{h}_{\mathrm{2}} {o}\Rightarrow\mathrm{2}{hno}_{\mathrm{3}} +{no} \\ $$$$ \\ $$ Answered by aleks041103 last updated on 17/Jun/19 $${It}\:{is}\:{actually}:…
Question Number 62036 by Cypher1207 last updated on 14/Jun/19 $$\mathrm{Correct}\:\mathrm{me}\:\mathrm{if}\:\mathrm{I}\:\mathrm{am}\:\mathrm{wrong}. \\ $$$$\underset{\:\sqrt{−\mathrm{1}}=\mathrm{1}} {\overset{\mathrm{3}} {\sum}}\mathrm{x}_{\sqrt{−\mathrm{1}}} +\mathrm{y}_{\sqrt{−\mathrm{1}}} \\ $$$$\therefore\left({i}=\sqrt{−\mathrm{1}}\right) \\ $$$$ \\ $$ Commented by Rasheed.Sindhi last…