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Question-127568

Question Number 127568 by Ar Brandon last updated on 30/Dec/20 Commented by bramlexs22 last updated on 30/Dec/20 $$\mathrm{R}_{\mathrm{max}} \:=\:\sqrt{\mid\overset{\rightarrow} {\mathrm{a}}\mid^{\mathrm{2}} +\mid\overset{\rightarrow} {\mathrm{b}}\mid^{\mathrm{2}} +\mathrm{2}\mid\overset{\rightarrow} {\mathrm{a}}\mid\mid\overset{\rightarrow} {\mathrm{b}}\mid}\:…

Question-127566

Question Number 127566 by Ar Brandon last updated on 30/Dec/20 Answered by bramlexs22 last updated on 30/Dec/20 $$\left(\overset{\rightarrow} {\mathrm{a}}+\overset{\rightarrow} {\mathrm{b}}\right)×\left(\overset{\rightarrow} {\mathrm{a}}−\overset{\rightarrow} {\mathrm{b}}\right)=\overset{\rightarrow} {\mathrm{a}}×\overset{\rightarrow} {\mathrm{a}}−\overset{\rightarrow} {\mathrm{a}}×\overset{\rightarrow}…

a-6-2-2-2-i-b-1-i-Determinate-possible-values-of-n-N-such-such-that-a-n-R-and-b-n-iR-pure-imaginary-

Question Number 127567 by mathocean1 last updated on 30/Dec/20 $${a}=\frac{\sqrt{\mathrm{6}}}{\mathrm{2}}+\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}{i}\:;\:{b}=\mathrm{1}+{i}. \\ $$$${Determinate}\:{possible}\:{values} \\ $$$${of}\:{n}\:\in\:\mathbb{N}\:{such}\:{such}\:{that}\:{a}^{{n}} \:\in\:\mathbb{R}\:{and} \\ $$$${b}^{{n}} \:\in\:{i}\mathbb{R}\:\left({pure}\:{imaginary}\right). \\ $$$$ \\ $$$$ \\ $$$$ \\…

Question-193093

Question Number 193093 by Mingma last updated on 04/Jun/23 Answered by Subhi last updated on 04/Jun/23 $$\frac{\mathrm{1}}{\mathrm{2}}.\pi.{r}^{\mathrm{2}} \:=\:\mathrm{3}\pi \\ $$$${r}\:=\:\sqrt{\mathrm{6}} \\ $$$${AB}\:=\:{AD}\:=\:{BE}\:=\:\:\mathrm{2}\sqrt{\mathrm{6}} \\ $$$$\left({CD}\right)^{\mathrm{2}} \:=\:{CE}.{BC}={CE}.\left({CE}+\mathrm{2}\sqrt{\mathrm{6}}\right)…