Question Number 61902 by naka3546 last updated on 11/Jun/19 Commented by naka3546 last updated on 11/Jun/19 $$\Omega\:\:=\:\:? \\ $$ Commented by JDamian last updated on…
Question Number 192969 by mustafazaheen last updated on 01/Jun/23 Commented by mustafazaheen last updated on 01/Jun/23 $$\mathrm{how}\:\mathrm{is}\:\mathrm{solution}? \\ $$ Answered by MM42 last updated on…
Question Number 127434 by MathSh last updated on 29/Dec/20 $${y}=\frac{\mathrm{1}}{\mathrm{4}}{ln}\frac{\mathrm{1}+{x}}{\mathrm{1}−{x}}−\frac{\mathrm{1}}{\mathrm{2}}{arctgx} \\ $$$${y}'=? \\ $$ Commented by mohammad17 last updated on 29/Dec/20 $${y}^{'} =\frac{\mathrm{1}}{\mathrm{4}}\left(\frac{\left[\left(\mathrm{1}−{x}\right)\left(\mathrm{1}\right)−\left(\mathrm{1}+{x}\right)\left(−\mathrm{1}\right)\right]\left(\mathrm{1}+{x}\right)}{\left(\mathrm{1}−{x}\right)^{\mathrm{3}} }\right)−\frac{\mathrm{1}}{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}}…
Question Number 127435 by I want to learn more last updated on 29/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 127432 by mnjuly1970 last updated on 29/Dec/20 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…\mathrm{CALCULUS}… \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\varnothing=\int_{−\infty} ^{\:+\infty} {cos}\left(\frac{\pi{x}^{\mathrm{2}} }{\mathrm{2}}\right){dx}=? \\ $$$$ \\ $$ Answered by Dwaipayan Shikari…
Question Number 127430 by mathocean1 last updated on 29/Dec/20 $${The}\:{objective}\:{of}\:{this}\:{exercise} \\ $$$${is}\:{to}\:{calculate}\:\underset{{n}\rightarrow+\infty} {{lim}}\frac{\mathrm{1}}{\:\sqrt{{n}}}\:×\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{\:\sqrt{{n}+{k}}}. \\ $$$${Given}\:{S}_{{n}} =\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{\:\sqrt{\mathrm{k}}};\:{U}_{{n}} =\mathrm{2}\sqrt{\mathrm{2}}−{S}_{{n}} \\ $$$${and}\:{V}_{{n}} =\mathrm{2}\sqrt{{n}+\mathrm{1}}−{Sn}. \\…
Question Number 61895 by maxmathsup by imad last updated on 10/Jun/19 $${let}\:{A}\:=\begin{pmatrix}{\mathrm{1}\:\:\:\:\:\:\:−\mathrm{1}}\\{\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}}\end{pmatrix} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{A}^{{n}} \\ $$$$\left.\mathrm{2}\right)\:{find}\:\:{e}^{{A}} \:\:,{e}^{−{A}} \\ $$$$\left.\mathrm{3}\right)\:{determine}\:{e}^{{iA}} \:\:\:{then}\:\:{cosA}\:\:{and}\:{sinA}\:. \\ $$ Commented by maxmathsup…
Question Number 192966 by Mingma last updated on 01/Jun/23 Answered by aleks041103 last updated on 01/Jun/23 $${at}\:{the}\:{intersection}\:\left(\mathrm{0},\mathrm{0}\right)\in\mathbb{R}^{\mathrm{2}} . \\ $$$${the}\:{whole}\:{circle}\:{is} \\ $$$$\left({x}−\frac{\mathrm{5}}{\mathrm{4}}\right)^{\mathrm{2}} +\left({y}+\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =\frac{\mathrm{125}}{\mathrm{16}}=\left(\frac{\mathrm{5}\sqrt{\mathrm{5}}}{\mathrm{4}}\right)^{\mathrm{2}} \\…
Question Number 127429 by Study last updated on 29/Dec/20 $$\mathrm{6}\boldsymbol{\div}\mathrm{3}\left(\mathrm{2}\right)=??? \\ $$ Commented by talminator2856791 last updated on 29/Dec/20 $$\:\mathrm{why}\:\mathrm{is}\:\mathrm{your}\:\mathrm{name}\:\mathrm{in}\:\mathrm{red}? \\ $$ Terms of Service…
Question Number 61892 by hhghg last updated on 10/Jun/19 $$\frac{\mathrm{1}}{\mathrm{4}}\:\mathrm{of}\:\frac{\mathrm{2}}{\mathrm{5}} \\ $$ Commented by Rasheed.Sindhi last updated on 11/Jun/19 $$\frac{\mathrm{2}}{\mathrm{5}}×\frac{\mathrm{1}}{\mathrm{4}}=\frac{\mathrm{1}}{\mathrm{10}} \\ $$ Terms of Service…