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Author: Tinku Tara

Question-61700

Question Number 61700 by aliesam last updated on 06/Jun/19 Answered by tanmay last updated on 06/Jun/19 $${a}=−{b}−{c} \\ $$$${a}^{\mathrm{2}} =−{ab}−{ac} \\ $$$$\frac{−{ab}−{ac}}{−{ab}−{bc}−{ac}}+\frac{−{ab}−{bc}}{−{ab}−{bc}−{ca}}+\frac{−{ac}−{bc}}{−{ac}−{bc}−{ab}} \\ $$$$=\frac{−\mathrm{2}\left({ab}+{bc}+{ac}\right)}{−\left({ab}+{bc}+{ac}\right)} \\…

calculus-I-complex-analysis-calculate-0-ln-x-x-2-3x-2-dx-ln-2-2-2-

Question Number 127224 by mnjuly1970 last updated on 28/Dec/20 $$\:\:…\:{calculus}\:\:\left({I}\right)\:−{complex}\:{analysis}… \\ $$$$\:\:\:\:{calculate}\:::\: \\ $$$$\:\:\Phi\:=\:\int_{\mathrm{0}} ^{\:\infty} \frac{{ln}\left({x}\right)}{{x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{2}}\:{dx}=\frac{{ln}^{\mathrm{2}} \left(\mathrm{2}\right)}{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by mindispower…