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Author: Tinku Tara

what-is-the-value-of-dy-dx-if-y-cot-1-1-sinx-1-sinx-1-sinx-1-sinx-x-0-pi-2-please-give-complete-explanation-that-why-can-we-not-take-sinx-2-cosx-2-2-1-sinx-

Question Number 192758 by vishal1234 last updated on 26/May/23 $${what}\:{is}\:{the}\:{value}\:{of}\:{dy}/{dx}\:{if} \\ $$$${y}\:=\:{cot}^{−\mathrm{1}} \left[\frac{\sqrt{\mathrm{1}+{sinx}}+\sqrt{\mathrm{1}−{sinx}}}{\:\sqrt{\mathrm{1}+{sinx}}−\sqrt{\mathrm{1}−{sinx}}}\right];\:{x}\in\left(\mathrm{0},\frac{\pi}{\mathrm{2}}\right) \\ $$$${please}\:{give}\:{complete}\:{explanation}\:{that} \\ $$$${why}\:{can}\:{we}\:{not}\:{take} \\ $$$$\left[{sinx}/\mathrm{2}−{cosx}/\mathrm{2}\right]^{\mathrm{2}} \:=\:\mathrm{1}−{sinx} \\ $$ Answered by a.lgnaoui…

a-0-4-1-tgx-dx-b-0-1-1-lnx-dx-

Question Number 61674 by behi83417@gmail.com last updated on 06/Jun/19 $$\mathrm{a}.\underset{\:\:\:\mathrm{0}} {\overset{\:\:\:\:\:\:\:\frac{\boldsymbol{\pi}}{\mathrm{4}}} {\int}}\sqrt{\mathrm{1}+\boldsymbol{\mathrm{tgx}}}\:\boldsymbol{\mathrm{dx}}=? \\ $$$$\mathrm{b}.\underset{\:\:\mathrm{0}} {\overset{\:\:\:\:\:\:\:\:\mathrm{1}} {\int}}\sqrt{\mathrm{1}+\boldsymbol{\mathrm{lnx}}}\:\boldsymbol{\mathrm{dx}}=? \\ $$ Commented by maxmathsup by imad last updated…

Let-G-be-the-group-1-1-and-let-H-1-show-that-G-H-is-an-Isomorphism-Hello-

Question Number 192746 by Mastermind last updated on 26/May/23 $$\mathrm{Let}\:\mathrm{G}\:\mathrm{be}\:\mathrm{the}\:\mathrm{group}\:\left(\left\{\mathrm{1},\:\imath,\:−\mathrm{1},\:−\imath\right\},\:\centerdot\right) \\ $$$$\mathrm{and}\:\mathrm{let}\:\mathrm{H}\:\leqslant\:\left(\underset{−} {+}\mathrm{1},\:\centerdot\right),\:\mathrm{show}\:\mathrm{that} \\ $$$$\theta:\mathrm{G}\rightarrow\mathrm{H}\:\mathrm{is}\:\mathrm{an}\:\mathrm{Isomorphism}. \\ $$$$ \\ $$$$\mathrm{Hello}! \\ $$ Answered by aleks041103 last…

Prove-it-sin-pi-2m-1-sin-2pi-2m-1-sin-mpi-2m-1-2m-1-2-m-

Question Number 127206 by MathSh last updated on 27/Dec/20 $${Prove}\:{it}: \\ $$$${sin}\frac{\pi}{\mathrm{2}{m}+\mathrm{1}}\centerdot{sin}\frac{\mathrm{2}\pi}{\mathrm{2}{m}+\mathrm{1}}\centerdot…\centerdot{sin}\frac{{m}\pi}{\mathrm{2}{m}+\mathrm{1}}=\frac{\sqrt{\mathrm{2}{m}+\mathrm{1}}}{\mathrm{2}^{{m}} } \\ $$ Answered by Olaf last updated on 28/Dec/20 $$ \\ $$$$\Omega\:=\:\underset{{k}=\mathrm{1}}…