Question Number 192472 by Mastermind last updated on 19/May/23 $$\mathrm{A}\:\mathrm{heat}\:\mathrm{transfer}\:\mathrm{of}\:\mathrm{9}.\mathrm{0}×\mathrm{10}^{\mathrm{5}} \mathrm{J}\:\mathrm{is}\:\mathrm{required} \\ $$$$\mathrm{to}\:\mathrm{convert}\:\mathrm{a}\:\mathrm{block}\:\mathrm{of}\:\mathrm{ice}\:\mathrm{at}\:\mathrm{20}°\mathrm{C}\:\mathrm{to} \\ $$$$\mathrm{water}\:\mathrm{at}\:\mathrm{15}°\mathrm{C},\:\mathrm{what}\:\mathrm{was}\:\mathrm{the}\:\mathrm{mass}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{block}\:\mathrm{of}\:\mathrm{ice}\:? \\ $$ Answered by MikeH last updated on…
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Question Number 192469 by Mingma last updated on 18/May/23 Answered by a.lgnaoui last updated on 19/May/23 $$\bigtriangleup\mathrm{ABC}\:\:\mathrm{triangle}\:\mathrm{isocele}\:\:\mathrm{AB}=\mathrm{AC} \\ $$$$\mathrm{donc}\:\:\measuredangle\mathrm{B}=\measuredangle\mathrm{C}=\mathrm{90}−\frac{\mathrm{78}}{\mathrm{2}}=\mathrm{51}° \\ $$$$\:\:\:\:\:\:\frac{\mathrm{sin}\:\mathrm{78}}{\boldsymbol{\mathrm{BC}}}=\frac{\mathrm{sin}\:\mathrm{51}}{\boldsymbol{\mathrm{AC}}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{1}\right) \\ $$$$\bigtriangleup\mathrm{ABD}\:\:\:\:\mathrm{AB}=\mathrm{BD}\:\:\:\measuredangle\mathrm{CAD}=\mathrm{A}_{\mathrm{1}} \\ $$$$\:\:\:\:\:\:\:\:\:…
Question Number 126934 by Dwaipayan Shikari last updated on 25/Dec/20 $$\frac{\mathrm{1}}{\mathrm{1}!}+\frac{\mathrm{1}!^{\mathrm{2}} }{\mathrm{3}!}+\frac{\mathrm{2}!^{\mathrm{2}} }{\mathrm{5}!}+\frac{\mathrm{3}!^{\mathrm{2}} }{\mathrm{7}!}+\frac{\mathrm{4}!^{\mathrm{2}} }{\mathrm{9}!}+…. \\ $$ Commented by Dwaipayan Shikari last updated on 25/Dec/20…
Question Number 126935 by Raxreedoroid last updated on 25/Dec/20 $${Prove}\:{or}\:{give}\:{a}\:{counter}\:{example}: \\ $$$$\left({a}+\mathrm{1}\right)^{{n}−\mathrm{1}} =\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\underset{{k}−\mathrm{1}} {\overset{{n}−\mathrm{1}} {\:}}\right){a}^{{k}−\mathrm{1}} \\ $$$$\left(\underset{{r}} {\overset{{n}} {\:}}\right)=\frac{{n}!}{{r}!\left({n}−{r}\right)!} \\ $$ Terms of…
Question Number 192470 by Spillover last updated on 19/May/23 Answered by Spillover last updated on 19/May/23 $$\int_{\mathrm{0}} ^{\sqrt{\mathrm{2}}} \sqrt{\mathrm{1}+\left(\mathrm{2}{x}\right)^{\mathrm{2}} }\:{dx} \\ $$$${Let}\:\:\:\mathrm{2}{x}=\mathrm{sinh}\:\theta\:\:\:\:\:\:\:\:\:\:\:{dx}=\:\frac{\mathrm{cosh}\:\theta{d}\theta}{\mathrm{2}} \\ $$$$\int_{\mathrm{0}} ^{\sqrt{\mathrm{2}}}…
Question Number 126930 by bramlexs22 last updated on 25/Dec/20 $$\:\:\sqrt{\mathrm{1997}×\mathrm{1996}×\mathrm{1995}×\mathrm{1994}+\mathrm{1}}\:=? \\ $$ Commented by bramlexs22 last updated on 25/Dec/20 $$\Rightarrow{let}\:\mathrm{1994}={a}\:\rightarrow{a}\left({a}+\mathrm{1}\right)\left({a}+\mathrm{2}\right)\left({a}+\mathrm{3}\right)+\mathrm{1}= \\ $$$$\Leftrightarrow\left({a}^{\mathrm{2}} +{a}\right)\left({a}^{\mathrm{2}} +\mathrm{5}{a}+\mathrm{6}\right)+\mathrm{1}\:= \\…
Question Number 192464 by Engr_Jidda last updated on 18/May/23 Commented by a.lgnaoui last updated on 19/May/23 $${X}'? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 126931 by arash sharifi last updated on 25/Dec/20 $${y}=\left(\mathrm{1}−{x}\right)^{{cosx}} \\ $$ Answered by mahdipoor last updated on 25/Dec/20 $${salam}\:{arash}\:{jan},{soalat}\:{ro}\:{khamel}\:{benevis} \\ $$ Terms of…
Question Number 192466 by Engr_Jidda last updated on 18/May/23 Commented by Frix last updated on 19/May/23 $$\left(\mathrm{sin}^{\mathrm{4}} \:\theta\:−\mathrm{cos}^{\mathrm{4}} \:\theta\right)\mathrm{csc}^{\mathrm{2}} \:\theta\:=\mathrm{2} \\ $$$$\frac{\mathrm{2sin}^{\mathrm{2}} \:\theta\:−\mathrm{1}}{\mathrm{sin}^{\mathrm{2}} \:\theta}=\mathrm{2} \\…