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Author: Tinku Tara

Question-192463

Question Number 192463 by Spillover last updated on 18/May/23 Answered by AST last updated on 18/May/23 $$\mathrm{420}=\mathrm{2}^{\mathrm{2}} ×\mathrm{3}×\mathrm{5}×\mathrm{7} \\ $$$$\mathrm{264}=\mathrm{2}^{\mathrm{3}} ×\mathrm{3}×\mathrm{11} \\ $$$${Third}\:{number}=\mathrm{2}^{{a}} \mathrm{3}^{{b}} \mathrm{5}^{{c}}…

Question-192458

Question Number 192458 by Mingma last updated on 18/May/23 Answered by Frix last updated on 19/May/23 $$\mathrm{log}_{{x}+\frac{\mathrm{7}}{\mathrm{2}}} \:\left(\frac{{x}+\mathrm{7}}{\mathrm{2}{x}+\mathrm{3}}\right)^{\mathrm{2}} \:=\frac{\mathrm{ln}\:\left(\frac{{x}+\mathrm{7}}{\mathrm{2}{x}+\mathrm{3}}\right)^{\mathrm{2}} }{\mathrm{ln}\:\left({x}+\frac{\mathrm{7}}{\mathrm{2}}\right)}= \\ $$$$=\frac{\mathrm{2}\left(\mathrm{ln}\:\mid{x}+\mathrm{7}\mid\:−\mathrm{ln}\:\mid\mathrm{2}{x}+\mathrm{3}\mid\right)}{\mathrm{ln}\:\left(\mathrm{2}{x}+\mathrm{7}\right)\:−\mathrm{ln}\:\mathrm{2}}\geqslant\mathrm{0} \\ $$$$\frac{\mathrm{ln}\:\mid{x}+\mathrm{7}\mid\:−\mathrm{ln}\:\mid\mathrm{2}{x}+\mathrm{3}\mid}{\mathrm{ln}\:\left(\mathrm{2}{x}+\mathrm{7}\right)\:−\mathrm{ln}\:\mathrm{2}}\geqslant\mathrm{0} \\…

Question-126921

Question Number 126921 by sdfg last updated on 25/Dec/20 Commented by mr W last updated on 25/Dec/20 $$\overset{\rightarrow} {{C}}=\overset{\rightarrow} {{A}}+\overset{\rightarrow} {{B}} \\ $$$$\overset{\rightarrow} {{C}}'=\frac{\mathrm{1}}{\mathrm{2}}\overset{\rightarrow} {{A}}+\frac{\mathrm{1}}{\mathrm{2}}\overset{\rightarrow}…