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Author: Tinku Tara

Merry-christmas-0-1-2-tanh-1-x-x-1-5-dx-

Question Number 126907 by Dwaipayan Shikari last updated on 25/Dec/20 $$\boldsymbol{{Merry}}\:\boldsymbol{{christmas}}\:!! \\ $$$$ \\ $$πŸŽ…πŸ€Άβ˜ƒοΈπŸŒ„πŸŽ„πŸ¦Œ $$ \\ $$$$ \\ $$πŸ””πŸ””πŸ””πŸ””πŸ””πŸ””πŸ””πŸ””πŸ”” πŸŽ„πŸŽ„πŸŽ„πŸŽ„πŸŽ„πŸŽ„πŸŽ„πŸŽ„ $$\int_{\mathrm{0}} ^{\frac{\mathrm{1}}{\mathrm{2}}} \frac{\boldsymbol{{tanh}}^{βˆ’\mathrm{1}} \boldsymbol{{x}}}{\:\sqrt[{\mathrm{5}}]{\boldsymbol{{x}}}}\boldsymbol{{dx}}…

Find-the-sum-of-the-first-16th-term-of-the-series-3-1-2-4-3-4-6-7-1-4-

Question Number 192443 by Mastermind last updated on 18/May/23 $$\mathrm{Find}\:\mathrm{the}\:\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{first}\:\mathrm{16th}\:\mathrm{term} \\ $$$$\:\mathrm{of}\:\mathrm{the}\:\mathrm{series}\:\mathrm{3}\frac{\mathrm{1}}{\mathrm{2}}\:+\:\mathrm{4}\frac{\mathrm{3}}{\mathrm{4}}\:+\:\mathrm{6}\:+\:\mathrm{7}\frac{\mathrm{1}}{\mathrm{4}}\:… \\ $$ Answered by AST last updated on 18/May/23 $${S}_{\mathrm{16}} =\mathrm{8}\left(\mathrm{7}+\frac{\mathrm{75}}{\mathrm{4}}\right)=\mathrm{56}+\mathrm{150}=\mathrm{206} \\ $$…

0-x-1-x-2-sin-2-x-dx-

Question Number 126904 by Mustafa2020 last updated on 25/Dec/20 $$\int_{\mathrm{0}} ^{\infty} \frac{{x}}{\mathrm{1}+{x}^{\mathrm{2}} {sin}^{\mathrm{2}} {x}}{dx} \\ $$ Answered by mindispower last updated on 25/Dec/20 $$\geqslant\Sigma\int_{\mathrm{2}{k}\pi} ^{\mathrm{2}{k}\pi+\frac{\pi}{\mathrm{6}}}…

1-a-1-b-1-c-1-a-b-c-Prove-that-1-a-5-1-b-5-1-c-5-1-a-5-b-5-c-5-1-a-b-c-5-

Question Number 192437 by MATHEMATICSAM last updated on 18/May/23 $$\frac{\mathrm{1}}{{a}}\:+\:\frac{\mathrm{1}}{{b}}\:+\:\frac{\mathrm{1}}{{c}}\:=\:\frac{\mathrm{1}}{{a}\:+\:{b}\:+\:{c}}\:.\:\mathrm{Prove}\:\mathrm{that} \\ $$$$\frac{\mathrm{1}}{{a}^{\mathrm{5}} }\:+\:\frac{\mathrm{1}}{{b}^{\mathrm{5}} }\:+\:\frac{\mathrm{1}}{{c}^{\mathrm{5}} }\:=\:\frac{\mathrm{1}}{{a}^{\mathrm{5}} \:+\:{b}^{\mathrm{5}} \:+\:{c}^{\mathrm{5}} }\:=\:\frac{\mathrm{1}}{\left({a}\:+\:{b}\:+\:{c}\right)^{\mathrm{5}} } \\ $$ Answered by Frix last…

lim-x-0-1-cos-ln-3x-1-3x-6-tan-3x-2-

Question Number 192433 by cortano12 last updated on 18/May/23 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}βˆ’\mathrm{cos}\:\left(\mathrm{ln}\:\left(\mathrm{3x}+\mathrm{1}\right)\right)}{\mathrm{3x}^{\mathrm{6}} βˆ’\mathrm{tan}\:\left(\mathrm{3x}^{\mathrm{2}} \right)}=? \\ $$ Answered by mehdee42 last updated on 18/May/23 $${tip}\::{if}\:\:{u}\rightarrow\mathrm{0} \\ $$$$\Rightarrow\mathrm{1}βˆ’{cosu}\sim\frac{\mathrm{1}}{\mathrm{2}}{u}^{\mathrm{2}}…