Question Number 126723 by ajfour last updated on 23/Dec/20 Commented by prakash jain last updated on 23/Dec/20 $$\mathrm{Two}\:\mathrm{assumptions} \\ $$$${p}^{\mathrm{2}} +\mathrm{2}{pq}=\mathrm{1} \\ $$$${q}=\mathrm{2}{c} \\ $$$$\mathrm{You}\:\mathrm{are}\:\mathrm{substituting}\:\mathrm{a}\:\mathrm{given}\:\mathrm{value}…
Question Number 61186 by Tawa1 last updated on 30/May/19 Commented by Prithwish sen last updated on 30/May/19 $$\mathrm{Area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{shadded}\:\mathrm{portion}\:=\mathrm{Area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{incircle}\: \\ $$$$−\mathrm{Area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{quarter}\:\mathrm{circle}\:+\frac{\mathrm{3}}{\mathrm{4}}\left(\mathrm{Area}\:\mathrm{of}\:\mathrm{the}\:\right. \\ $$$$\left.\mathrm{square}\:−\mathrm{Area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{incircle}\right) \\ $$$$=\pi\mathrm{5}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{4}}\pi\left(\mathrm{10}\right)^{\mathrm{2}}…
Question Number 126720 by mathocean1 last updated on 23/Dec/20 $$ \\ $$$${show}\:{that} \\ $$$${cos}\left({a}\right)+{cos}\left({b}\right)=\mathrm{2}{cos}\left(\frac{{a}+{b}}{\mathrm{2}}\right){cos}\left(\frac{{a}−{b}}{\mathrm{2}}\right) \\ $$ Answered by mathmax by abdo last updated on 23/Dec/20…
Question Number 192255 by Spillover last updated on 01/Feb/24 $${If}\:\theta\:{be}\:{the}\:{acute}\:{angle}\:{between}\:{two}\:{regression} \\ $$$${line}\:{in}\:{the}\:{case}\:{of}\:{two}\:{variables}\:{x}\:{and}\:{y} \\ $$$${Show}\:{that} \\ $$$$\:\:\mathrm{tan}\:\theta=\frac{\mathrm{1}−{r}}{{r}}.\frac{\sigma_{{x}} \sigma_{{y}} }{\sigma_{{x}} ^{\mathrm{2}} +\sigma_{{y}} ^{\mathrm{2}} }\:\:\: \\ $$$${where}\:\:{r},\sigma_{{x}} ,\sigma_{{y}}…
Question Number 126716 by sdfg last updated on 23/Dec/20 Answered by liberty last updated on 23/Dec/20 $$\overset{\rightarrow} {{a}}=\left(\mathrm{3},\mathrm{4}\right)\:;\:\overset{\rightarrow} {{b}}=\left({x},{y}\right)\:\rightarrow{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{5}…\left({i}\right) \\ $$$$\:\overset{\rightarrow} {{a}}\:\bot\:\overset{\rightarrow} {{b}}\:\rightarrow\:\overset{\rightarrow}…
Question Number 61181 by mathsolverby Abdo last updated on 30/May/19 $${sove}\:\left(\mathrm{1}+{e}^{−{x}} \right){y}^{''} \:+\left(\mathrm{2}+{e}^{{x}} \right){y}^{'} \:=\left({x}+\mathrm{1}\right){e}^{{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 192254 by Spillover last updated on 01/Feb/24 $${Establish}\:{the}\:{formular}\:\: \\ $$$$\sigma_{{x}−{y}} ^{\mathrm{2}} =\sigma_{{x}} ^{\mathrm{2}} +\sigma_{{y}} ^{\mathrm{2}} −\mathrm{2}{r}\sigma_{{x}} \sigma_{{y}} \:\: \\ $$$${where}\:{by}\:{r}\:{is}\:{the}\:{correlation} \\ $$$${coefficient}\:{between}\:{x}\:{and}\:{y} \\…
Question Number 61180 by mathsolverby Abdo last updated on 30/May/19 $${solve}\:{y}^{''} \:+\mathrm{3}{y}^{'} −{y}\:={sin}\left(\mathrm{2}{x}\right) \\ $$ Answered by tanmay last updated on 30/May/19 $$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }+\mathrm{3}\frac{{dy}}{{dx}}−{y}={sin}\mathrm{2}{x}…
Question Number 126714 by BHOOPENDRA last updated on 23/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 192248 by Tomal last updated on 12/May/23 Commented by Tomal last updated on 19/May/23 $$\boldsymbol{{please}}\:{ANSWER}. \\ $$ Terms of Service Privacy Policy Contact:…