Question Number 213427 by Mingma last updated on 05/Nov/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 213404 by issac last updated on 04/Nov/24 $$\mathrm{pls}\:\mathrm{teach}\:\mathrm{me}\:\mathrm{above}\:\mathrm{question} \\ $$$$\downarrow\downarrow\:\left(\mathrm{prove}\:\mathrm{real}\:\mathrm{analysis}\:\mathrm{pls}\right) \\ $$$$\mathrm{and}\:\mathrm{sorry}\:\mathrm{Mr}\:\mathrm{gaster} \\ $$$$\mathrm{i}\:\mathrm{cant}\:\mathrm{believe}\:\mathrm{you}\:\mathrm{answer}…. \\ $$ Commented by MrGaster last updated on 04/Nov/24…
Question Number 213391 by York12 last updated on 04/Nov/24 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{system}\:\mathrm{of}\:\mathrm{equations}\:\mathrm{where}\:{a},{b},{c}\geqslant\mathrm{0} \\ $$$${a}−\mathrm{2}{bc}={b}−\mathrm{2}{ac}={c}−\mathrm{2}{ab} \\ $$$${a}+{b}+{c}=\mathrm{2}\: \\ $$ Answered by Frix last updated on 04/Nov/24 $$\mathrm{Due}\:\mathrm{to}\:\mathrm{symmetry}\:{a}={b}={c}=\frac{\mathrm{2}}{\mathrm{3}} \\…
Question Number 213417 by hardmath last updated on 04/Nov/24 $$\mathrm{a}\:,\:\mathrm{b}\:,\:\mathrm{c}\:,\:\mathrm{d}\:\in\:\mathbb{N} \\ $$$$\mathrm{a}\:+\:\mathrm{b}\:+\:\mathrm{c}\:+\:\mathrm{d}\:=\:\mathrm{63} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{maksimum}\left(\mathrm{ab}\:+\:\mathrm{bc}\:+\:\mathrm{cd}\right)\:=\:? \\ $$ Answered by Frix last updated on 05/Nov/24 $${d}=\mathrm{63}−{a}−{b}−{c} \\…
Question Number 213413 by hardmath last updated on 04/Nov/24 $$\mathrm{Find}: \\ $$$$\mathrm{A}=\:\left[\sqrt{\mathrm{1}}\right]\:+\:\left[\sqrt{\mathrm{2}}\right]\:+\:\left[\sqrt{\mathrm{3}}\:\right]+…+\:\left[\sqrt{\mathrm{323}}\right]\:=\:? \\ $$ Answered by mehdee7396 last updated on 04/Nov/24 $$=\left(\left[\sqrt{\mathrm{1}}\right]+\left[\sqrt{\mathrm{2}}\right]+\left[\sqrt{\mathrm{3}}\right]+\right)+\left(\left[\mathrm{4}\right]+\left[\mathrm{5}\right]+…+\left[\left[\sqrt{\mathrm{8}}\right]\right)\right. \\ $$$$+\left(\left[\sqrt{\mathrm{9}}\right]+\left[\sqrt{\mathrm{10}}\right]+…+\left[\sqrt{\mathrm{24}}\right]\right)+… \\…
Question Number 213397 by ajfour last updated on 04/Nov/24 Answered by mr W last updated on 04/Nov/24 Commented by mr W last updated on 05/Nov/24…
Question Number 213398 by issac last updated on 04/Nov/24 $$\mathrm{One}\:\mathrm{simple}\:\mathrm{Equation} \\ $$$$\mathrm{pls}\:\mathrm{prove}\:\mathrm{this}\:\mathrm{property} \\ $$$$\underset{{j}=\mathrm{1}} {\overset{{N}} {\sum}}\:{a}_{{j}} \centerdot\underset{{k}=\mathrm{1}} {\overset{{M}} {\sum}}{b}_{{k}} =\underset{{j}=\mathrm{1}} {\overset{{N}} {\sum}}\centerdot\underset{{k}=\mathrm{1}} {\overset{{M}} {\sum}}\:{a}_{{j}} {b}_{{k}}…
Question Number 213340 by Spillover last updated on 03/Nov/24 Commented by mr W last updated on 03/Nov/24 $${no}\:{unique}\:{solution}\:{possible}! \\ $$ Commented by Spillover last updated…
Question Number 213341 by Spillover last updated on 03/Nov/24 Commented by mr W last updated on 03/Nov/24 $${no}\:{unique}\:{solution}\:{possible}! \\ $$ Commented by Spillover last updated…
Question Number 213374 by hardmath last updated on 03/Nov/24 $$\mathrm{Find}:\:\:\:\frac{\mathrm{1}\:−\:\mathrm{2}\:\sqrt[{\mathrm{4}}]{\mathrm{5}}\:+\:\sqrt{\mathrm{5}}}{\left(\sqrt{\mathrm{3}}\:−\:\sqrt[{\mathrm{4}}]{\mathrm{5}}\right)^{\mathrm{2}} }\:=\:? \\ $$ Commented by Frix last updated on 03/Nov/24 $$\frac{\mathrm{29}−\mathrm{15}\sqrt{\mathrm{3}}}{\mathrm{2}}−\frac{\mathrm{8}−\mathrm{5}\sqrt{\mathrm{3}}}{\mathrm{2}}\mathrm{5}^{\frac{\mathrm{3}}{\mathrm{4}}} +\frac{\mathrm{13}−\mathrm{7}\sqrt{\mathrm{3}}}{\mathrm{2}}\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{2}}} −\frac{\mathrm{18}−\mathrm{11}\sqrt{\mathrm{3}}}{\mathrm{2}}\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{4}}} \\ $$…