Question Number 126482 by ayyoubmaths last updated on 20/Dec/20 Answered by Dwaipayan Shikari last updated on 20/Dec/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{{cosx}−\mathrm{1}}{{x}}\right)=−\frac{\mathrm{2}{sin}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}{{x}}=−\frac{{x}^{\mathrm{2}} }{\mathrm{2}{x}}=\mathrm{0} \\ $$ Terms of…
Question Number 60946 by Tawa1 last updated on 27/May/19 $$\mathrm{Find}\:\mathrm{x}:\:\:\:\:\:\:\mathrm{x}^{\mathrm{x}} \:\:=\:\:\mathrm{2x} \\ $$ Commented by Prithwish sen last updated on 27/May/19 $$\mathrm{x}=\mathrm{2} \\ $$ Commented…
Question Number 126481 by sdfg last updated on 20/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 60944 by pooja24 last updated on 27/May/19 $$\int\frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{\frac{\mathrm{3}}{\mathrm{2}}} } \\ $$$${solve}\:{this}\:{pls} \\ $$ Commented by maxmathsup by imad last updated on 27/May/19…
Question Number 192013 by uchihayahia last updated on 05/May/23 $$ \\ $$$$\:\int{e}^{{at}^{{b}} } {dt} \\ $$$$\:{with}\:{a},{b}\:{as}\:{a}\:{constant} \\ $$$$\:{how}\:{to}\:{evaluate}\:{this} \\ $$$$ \\ $$ Terms of Service…
Question Number 126478 by BHOOPENDRA last updated on 20/Dec/20 $${find}\:\frac{\partial{w}}{\partial\theta}\:{and}\:\frac{\partial{w}}{\partial\phi}\:{given}\:{that}\: \\ $$$${w}\left({x},{y},{z}\right)={f}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \right)\:{where}\:{x}={rcos}\theta{cos}\phi \\ $$$${y}={rcos}\theta{sin}\phi,{z}={rsin}\theta. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 192015 by 073 last updated on 05/May/23 Answered by namphamduc last updated on 05/May/23 $$\mathrm{Use}\:\mathrm{this}:\int_{{a}} ^{{b}} {f}\left({x}\right){dx}=\int_{{a}} ^{{b}} {f}\left({a}+{b}−{x}\right){dx} \\ $$ Terms of…
Question Number 126476 by mnjuly1970 last updated on 20/Dec/20 $$\:\:\:\:\:\:\:\:…{nice}\:\:{calculus}… \\ $$$$\:\:{calculate}\::: \\ $$$$\:\:\:\:\:\:\Omega=\int_{\mathrm{0}} ^{\:\infty} \:\frac{{tanh}\left(\pi{x}\right)}{{x}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)}\:{dx}=? \\ $$ Answered by mathmax by abdo last…
Question Number 192009 by universe last updated on 05/May/23 $$\:\:\:\:\:{if}\:\:{a}>\mathrm{1}\:,\:{show} \\ $$$$\:\:\:\:\:\frac{\underset{{k}=\mathrm{1}} {\overset{{a}^{\mathrm{2}} −\mathrm{1}} {\sum}}\:\:\sqrt{{a}+\sqrt{{k}}}}{\underset{{k}=\mathrm{1}} {\overset{{a}^{\mathrm{2}} −\mathrm{1}} {\sum}}\:\:\sqrt{{a}−\sqrt{{k}}}}\:\:\:=\:\:\:\sqrt{\mathrm{2}}\:\:+\:\:\mathrm{1} \\ $$ Answered by Skabetix last updated…
Question Number 126475 by sdfg last updated on 20/Dec/20 Answered by physicstutes last updated on 20/Dec/20 $$\:\left(\mathrm{a}\right)\:\boldsymbol{\mathrm{a}}\:=\:\frac{\boldsymbol{\Delta\mathrm{v}}}{\boldsymbol{\Delta}{t}}\:=\:\frac{\left[\left(\mathrm{10}\:\boldsymbol{\mathrm{j}}\right)\:−\left(\mathrm{10}\:\boldsymbol{\mathrm{i}}\:+\:\mathrm{20}\:\boldsymbol{\mathrm{j}}\right)\right]\:\mathrm{m}\:\mathrm{s}^{−\mathrm{1}} }{\left(\mathrm{4}−\mathrm{0}\right)\:\mathrm{s}}\:=\:\left[−\left(\frac{\mathrm{10}}{\mathrm{4}}\right)\:\boldsymbol{\mathrm{i}}\:−\:\left(\frac{\mathrm{10}}{\mathrm{4}}\right)\:\boldsymbol{\mathrm{j}}\:\right]\mathrm{m}\:\mathrm{s}^{−\mathrm{2}} \\ $$$$\mathrm{or}\:\boldsymbol{\mathrm{a}}\:=\left(\:−\frac{\mathrm{5}}{\mathrm{2}}\boldsymbol{\mathrm{i}}\:−\:\frac{\mathrm{5}}{\mathrm{2}}\boldsymbol{\mathrm{j}}\:\right)\:\mathrm{m}\:\mathrm{s}^{−\mathrm{2}} \:\:\:\mathrm{ofcourse}\:\mathrm{assuming}\:\mathrm{we}\:\mathrm{are}\:\mathrm{using}\:\mathrm{SI}\:\mathrm{base}\:\mathrm{units}. \\ $$$$\:\left(\mathrm{b}\right)\:\boldsymbol{\mathrm{r}}\:=\:\boldsymbol{\mathrm{r}}_{\mathrm{0}} +\:\:\boldsymbol{\mathrm{v}}_{\mathrm{0}} {t}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\boldsymbol{\mathrm{a}}\:{t}^{\mathrm{2}}…