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Author: Tinku Tara

prove-that-a-b-a-b-a-b-a-b-4a-3b-2-b-2-

Question Number 191947 by universe last updated on 04/May/23 $${prove}\:{that} \\ $$$$\sqrt{{a}+{b}\sqrt{{a}−{b}\sqrt{{a}+{b}\sqrt{{a}−{b}\sqrt{…}}}}}\:\:=\:\:\frac{\sqrt{\mathrm{4}{a}−\mathrm{3}{b}^{\mathrm{2}} }+{b}}{\mathrm{2}} \\ $$ Answered by ajfour last updated on 05/May/23 $${Let}\:{s}=\sqrt{{a}+{b}\sqrt{{a}−{bs}}}=\frac{{b}+\sqrt{\mathrm{4}{a}−\mathrm{3}{b}^{\mathrm{2}} }}{\mathrm{2}} \\…

Question-126408

Question Number 126408 by morarupaula last updated on 20/Dec/20 Answered by Dwaipayan Shikari last updated on 20/Dec/20 $$\overset{\bullet\bullet\bullet} {{x}}+\overset{\bullet} {{x}}=\mathrm{0}\:\:\:\:\:\:\:{x}={e}^{\lambda{t}} \\ $$$$\lambda^{\mathrm{3}} +\lambda=\mathrm{0}\Rightarrow\lambda=\mathrm{0}\:,\:\lambda=\pm{i} \\ $$$${x}=\Lambda+\Gamma{e}^{\lambda{ti}}…

Question-60873

Question Number 60873 by Kunal12588 last updated on 26/May/19 Commented by Prithwish sen last updated on 26/May/19 $$\left.\mathrm{i}\right)\:\mathrm{log}_{\mathrm{2}} \left(\mathrm{4x}^{\mathrm{2}} −\mathrm{x}−\mathrm{1}\right)−\mathrm{log}_{\mathrm{2}} \left(\mathrm{x}^{\mathrm{2}} +\mathrm{1}\right)\:>\mathrm{0} \\ $$$$\frac{\mathrm{4x}^{\mathrm{2}} −\mathrm{x}−\mathrm{1}}{\mathrm{x}^{\mathrm{2}}…

If-tanA-3-prove-it-3-sinA-cosA-3-4-

Question Number 126405 by amns last updated on 20/Dec/20 $$\boldsymbol{\mathrm{If}}\:{tanA}\:=\:\sqrt{\mathrm{3}}\:,\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{it}}:\:\sqrt{\mathrm{3}}\:{sinA}\:{cosA}\:=\:\frac{\mathrm{3}}{\mathrm{4}} \\ $$ Commented by amns last updated on 20/Dec/20 $$\mathrm{help}\:\mathrm{me},\:\mathrm{plz}… \\ $$ Commented by som(math1967)…

r-t-4sin-2-ti-4cos-2-tj-3k-

Question Number 126398 by sahnaz last updated on 20/Dec/20 $$\overset{\rightarrow} {\mathrm{r}}\left(\mathrm{t}\right)=\mathrm{4sin}^{\mathrm{2}} \mathrm{t}\overset{\rightarrow} {\mathrm{i}}+\mathrm{4cos}^{\mathrm{2}} \mathrm{t}\overset{\rightarrow} {\mathrm{j}}−\mathrm{3}\overset{\rightarrow} {\mathrm{k}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-191935

Question Number 191935 by Rupesh123 last updated on 04/May/23 Answered by som(math1967) last updated on 04/May/23 $${Direction}\:{cosine}\:{of}\:{L} \\ $$$${cos}\alpha,{cos}\beta,{cos}\gamma \\ $$$$\:\therefore{cos}^{\mathrm{2}} \alpha+{cos}^{\mathrm{2}} \beta+{cos}^{\mathrm{2}} \gamma=\mathrm{1} \\…