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Author: Tinku Tara

2-2e-2-ln-e-x-e-x-9-x-dx-

Question Number 126316 by benjo_mathlover last updated on 19/Dec/20 $$\:\:\underset{\:\sqrt{\mathrm{2}}} {\overset{\mathrm{2}{e}^{\sqrt{\mathrm{2}}} } {\int}}\mathrm{ln}\:\left(\frac{{e}^{{x}} +{e}^{−{x}} }{\mathrm{9}\sqrt{{x}}}\right){dx}\:?\: \\ $$ Commented by liberty last updated on 19/Dec/20 $$\int\:\left(\mathrm{ln}\left(\:{e}^{{x}}…

Question-191854

Question Number 191854 by Rupesh123 last updated on 01/May/23 Answered by a.lgnaoui last updated on 02/May/23 $$\mathrm{l}\:\mathrm{image}\:\mathrm{comporte}\:\mathrm{3}\:\mathrm{principale}\boldsymbol{\mathrm{S}}\mathrm{s}\:\mathrm{surfaces} \\ $$$$\bullet\boldsymbol{\mathrm{S}}\mathrm{1}:\:\:\boldsymbol{\mathrm{S}}\mathrm{urface}\:\mathrm{du}\:\mathrm{quart}\:\mathrm{ceecle}\:\mathrm{C1}\:\left(\mathrm{rayon}\boldsymbol{\mathrm{r}}_{\mathrm{1}} =\mathrm{2}\right) \\ $$$$\bullet\mathrm{S2}:\:\boldsymbol{\mathrm{S}}\mathrm{urface}\:\mathrm{petit}\:\mathrm{cercleC2}\left(\mathrm{ryon}\::\boldsymbol{\mathrm{r}}_{\mathrm{2}} \right) \\ $$$$\bullet\boldsymbol{\mathrm{S}}\mathrm{3}:\mathrm{Surface}\:\mathrm{portion}\:\mathrm{cercle}\:\left(\mathrm{rayon}\:\boldsymbol{\mathrm{r}}_{\mathrm{3}}…

dx-1-x-2-1-x-2-

Question Number 126314 by benjo_mathlover last updated on 19/Dec/20 $$\:\:\int\:\frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:? \\ $$ Answered by Dwaipayan Shikari last updated on 19/Dec/20 $$\int\frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:\:\:\:\:\:\:\:{x}={sin}\theta…

Question-60775

Question Number 60775 by Pathen Vincent last updated on 25/May/19 Commented by Prithwish sen last updated on 25/May/19 $$\mathrm{Divide}\:\mathrm{all}\:\mathrm{3}\:\mathrm{eqiations}\:\mathrm{by}\:\mathrm{xyz}\:\mathrm{and}\:\mathrm{then}\:\mathrm{apply} \\ $$$$\mathrm{crammers}\:\mathrm{rule}\:\mathrm{for}\:\frac{\mathrm{1}}{\mathrm{x}},\:\frac{\mathrm{1}}{\mathrm{y}}\:,\frac{\mathrm{1}}{\mathrm{z}} \\ $$ Terms of…

Question-191841

Question Number 191841 by Mingma last updated on 01/May/23 Answered by som(math1967) last updated on 01/May/23 $${from}\bigtriangleup{ADC} \\ $$$$\:\frac{{AD}}{{sin}\mathrm{30}}=\frac{{AC}}{{sin}\mathrm{110}} \\ $$$$\Rightarrow\frac{{AD}}{\mathrm{sin}\:\mathrm{30}}=\frac{{AC}}{\mathrm{sin}\:\mathrm{70}}\:……\mathrm{1} \\ $$$${from}\:\bigtriangleup{ABD} \\ $$$$\:\frac{\mathrm{sin}\:\mathrm{20}}{{AD}}=\frac{\mathrm{sin}\:\mathrm{40}}{{BD}}\:\:\:…..\mathrm{2}…

Question-126304

Question Number 126304 by mohammad17 last updated on 19/Dec/20 Answered by liberty last updated on 19/Dec/20 $$\left(\mathrm{1}\right)\mathrm{2}!×\mathrm{4}! \\ $$$$\left(\mathrm{3}\right)\mathrm{5}!−\mathrm{2}!×\mathrm{4}!=\mathrm{4}!×\mathrm{3} \\ $$ Answered by mr W…