Question Number 126305 by mohammad17 last updated on 19/Dec/20 Answered by liberty last updated on 19/Dec/20 $$\mathrm{2}×\mathrm{5}!×\mathrm{5}!\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 191839 by MATHEMATICSAM last updated on 01/May/23 $$\mathrm{2}^{{a}} \:=\:\mathrm{3}^{{b}} \:=\:\mathrm{36}^{{c}} \:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$${ab}\:=\:\mathrm{2}{c}\left({a}\:+\:{b}\right). \\ $$ Answered by AST last updated on 01/May/23 $${a}={blog}_{\mathrm{2}}…
Question Number 60765 by readone97 last updated on 25/May/19 $${express}\:{in}\:{partial}\:{fraction}\:\mathrm{14}/\left({x}^{\mathrm{2}} +\mathrm{3}\right)\left({x}+\mathrm{2}\right) \\ $$ Commented by Prithwish sen last updated on 25/May/19 $$\frac{\mathrm{1}}{\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3}\right)\left(\mathrm{x}+\mathrm{2}\right)}\:=\:\frac{\mathrm{A}}{\left(\mathrm{x}+\mathrm{2}\right)}\:+\frac{\mathrm{Bx}+\mathrm{C}}{\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3}\right)} \\…
Question Number 191833 by Mingma last updated on 01/May/23 Answered by AST last updated on 01/May/23 $${a}={log}_{\mathrm{2}} \mathrm{900};{b}={log}_{\mathrm{3}} \mathrm{900};{c}={log}_{\mathrm{5}} \mathrm{900} \\ $$$$\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}}+\frac{\mathrm{1}}{{c}}={log}_{\mathrm{900}} \mathrm{2}+{log}_{\mathrm{900}} \mathrm{3}+{log}_{\mathrm{900}} \mathrm{5}…
Question Number 126298 by bramlexs22 last updated on 19/Dec/20 $$\:\:\int_{\:\mathrm{0}} ^{\:\sqrt{\mathrm{ln}\:\left(\pi/\mathrm{2}\right)}} {xe}^{{x}^{\mathrm{2}} } \mathrm{sin}\:\left({e}^{{x}^{\mathrm{2}} } \right)\:{dx}\:? \\ $$ Answered by liberty last updated on 19/Dec/20…
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Question Number 191831 by Shlock last updated on 01/May/23 Answered by mehdee42 last updated on 02/May/23 $${suppose}\:,\:\:{n}=<{abcdefghij}>\:,{is}\:{an}\:<{i}.{n}> \\ $$$${a}+{b}+{c}+…+{i}+{j}\overset{\mathrm{9}} {\equiv}\mathrm{0}\Rightarrow\mathrm{9}\mid{n} \\ $$$$\mathrm{9}\mid{n}\:,\:\mathrm{11111}\mid{n}\:\:,\:\left(\mathrm{9},\mathrm{11111}\right)=\mathrm{1}\Rightarrow\mathrm{99999}\mid{n} \\ $$$${let}\:\:{x}=<{abcde}>\:\:\&\:\:{y}={f}<{fghij}> \\…
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Question Number 126293 by talminator2856791 last updated on 19/Dec/20 $$\: \\ $$$$\: \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{2}_{} }{}\mathrm{5}} \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{7}}{\mathrm{5}}} \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{9}}{\mathrm{8}}} \\ $$$$\:\frac{\mathrm{2}}{\frac{\mathrm{83}}{\mathrm{5}}} \\ $$ Commented by…
Question Number 60756 by readone97 last updated on 25/May/19 $${express}\:{in}\:{partial}\:{fraction}\:\mathrm{5}/\left({x}−\mathrm{2}\right)\left({x}+\mathrm{3}\right)^{\mathrm{2}} \\ $$ Commented by Prithwish sen last updated on 25/May/19 $$\frac{\mathrm{1}}{\left(\mathrm{x}−\mathrm{2}\right)\left(\mathrm{x}+\mathrm{3}\right)^{\mathrm{2}} }\:=\frac{\mathrm{A}}{\left(\mathrm{x}−\mathrm{2}\right)}\:+\frac{\mathrm{B}}{\left(\mathrm{x}+\mathrm{3}\right)}\:+\frac{\mathrm{C}}{\left(\mathrm{x}+\mathrm{3}\right)^{\mathrm{2}} } \\ $$$$\mathrm{and}\:\mathrm{then}\:\mathrm{proceed}.…