Question Number 126289 by mr W last updated on 19/Dec/20 $${To}\:{Tinku}\:{Tara}\:{developers}: \\ $$$${the}\:{latest}\:{version}\:{seems}\:{to}\:{have}\:{a} \\ $$$${bug}:\:{i}\:{can}\:{not}\:{write}\:{the}\:{red}\:{part}\:{in} \\ $$$${following}\:{expression}: \\ $$ Commented by mr W last updated…
Question Number 191821 by mehdee42 last updated on 01/May/23 $$\:{Q}\:\blacktriangleright\:{Show}\:{that}: \\ $$$$\underset{{i}=\mathrm{1}} {\overset{\mathrm{2}{n}} {\sum}}\left(−\mathrm{1}\right)^{{i}+\mathrm{1}} \frac{\mathrm{1}}{{i}}=\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{\mathrm{1}}{{i}+{n}} \\ $$ Answered by mehdee42 last updated on…
Question Number 126285 by bramlexs22 last updated on 19/Dec/20 $$\:\:\Rightarrow{solve}\:{x}^{\mathrm{2}} {y}\:=\:\int_{\mathrm{1}} ^{\:{x}^{\mathrm{2}} } {f}\left(\sqrt{{t}}\right){dx}+{x}^{\mathrm{3}} +\frac{\mathrm{1}}{{x}}+\mathrm{1} \\ $$$${y}={f}\left({x}\right)=? \\ $$ Answered by liberty last updated on…
Question Number 60748 by ajfour last updated on 25/May/19 Commented by ajfour last updated on 25/May/19 $${Determine}\:{r}\left(\theta\right). \\ $$ Answered by ajfour last updated on…
Question Number 60745 by Tawa1 last updated on 25/May/19 Commented by Prithwish sen last updated on 25/May/19 $$\frac{\left[\left(\mathrm{n}+\mathrm{1}\right)!\right]^{\mathrm{n}} }{\left(\mathrm{n}!\right)^{\mathrm{n}+\mathrm{1}} }\:=\left[\frac{\left(\mathrm{n}+\mathrm{1}\right)!}{\mathrm{n}!}\right]^{\mathrm{n}} .\frac{\mathrm{1}}{\mathrm{n}!}\:=\frac{\left(\mathrm{n}+\mathrm{1}\right)^{\mathrm{n}} }{\mathrm{n}!} \\ $$$$=\frac{\left(\mathrm{n}+\mathrm{1}\right)}{\mathrm{1}}.\frac{\left(\mathrm{n}+\mathrm{1}\right)}{\mathrm{2}}…………\frac{\left(\mathrm{n}+\mathrm{1}\right)}{\mathrm{n}}\:>\mathrm{1} \\…
Question Number 126274 by bramlexs22 last updated on 19/Dec/20 Answered by liberty last updated on 19/Dec/20 $$\:{letting}\:{x}=\sqrt{\mathrm{2}}\:\mathrm{sec}\:\ell\:{with}\:\rightarrow\begin{cases}{\ell=\frac{\pi}{\mathrm{2}}}\\{\ell=\frac{\pi}{\mathrm{4}}}\end{cases} \\ $$$$\:\int_{\pi/\mathrm{4}} ^{\:\pi/\mathrm{2}} \:\frac{\sqrt{\mathrm{2}}\:\mathrm{sec}\:\ell\:\mathrm{tan}\:\ell}{\:\sqrt{\mathrm{2}}\:\mathrm{sec}\:\ell\:\sqrt{\mathrm{2tan}\:^{\mathrm{2}} \ell}}\:{d}\ell\:= \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\int\:{d}\ell\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\left[\:\frac{\pi}{\mathrm{2}}−\frac{\pi}{\mathrm{4}}\:\right]\:=\:\frac{\pi}{\mathrm{4}\sqrt{\mathrm{2}}}\:=\:\frac{\pi\sqrt{\mathrm{2}}}{\mathrm{8}}\: \\…
Question Number 60739 by Forkum Michael Choungong last updated on 25/May/19 $${evaluate}\:\: \\ $$$${i}.\int\:\left(\frac{{x}+\mathrm{1}}{{x}−\mathrm{1}}\right){dx} \\ $$$${ii}.\:\:\int_{\mathrm{0}} ^{\pi} \left(\mathrm{2}{cosxsinx}\right){dx}\:\: \\ $$$${iii}.\:\:\int_{\frac{\pi}{\mathrm{3}\:}\:} ^{\pi} \left(\frac{{sin}\mathrm{2}{x}}{{cos}\mathrm{2}{x}}\right){dx} \\ $$ Commented…
Question Number 191811 by mathlove last updated on 01/May/23 $$\int{x}^{\mathrm{2}} {e}^{−{x}} {dx}=? \\ $$ Answered by Spillover last updated on 01/May/23 $${use}\:{by}\:{parts} \\ $$ Answered…
Question Number 126273 by bramlexs22 last updated on 19/Dec/20 Commented by talminator2856791 last updated on 19/Dec/20 $$\:\mathrm{we}\:\mathrm{dont}\:\mathrm{do}\:\mathrm{science}\:\mathrm{here}.\:\mathrm{only}\:\mathrm{mathematics} \\ $$ Commented by mr W last updated…
Question Number 126270 by liberty last updated on 19/Dec/20 $$\:\:{Three}\:{coins}\:{tossed}\:{at}\:{once}\:\mathrm{5}\:{times}.\: \\ $$$${The}\:{probability}\:{getting}\:{all}\:{faces}\:{or}\:{all} \\ $$$${hindsight}\:{a}\:{second}\:{time}\:{are}…. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com