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Author: Tinku Tara

prove-that-Im-iz-Re-z-

Question Number 126231 by mohammad17 last updated on 18/Dec/20 $${prove}\:{that}\::{Im}\left({iz}\right)={Re}\left({z}\right) \\ $$ Answered by floor(10²Eta[1]) last updated on 18/Dec/20 $$\mathrm{z}=\mathrm{a}+\mathrm{bi}\Rightarrow\mathrm{iz}=\mathrm{ai}−\mathrm{b} \\ $$$$\mathrm{Im}\left(\mathrm{iz}\right)=\mathrm{a} \\ $$$$\mathrm{Re}\left(\mathrm{z}\right)=\mathrm{a} \\…

1-y-x-x-

Question Number 126229 by MathSh last updated on 18/Dec/20 $$\left(\mathrm{1}+{y}\right){x}'={x} \\ $$ Answered by Dwaipayan Shikari last updated on 18/Dec/20 $$\left(\mathrm{1}+{y}\right)\frac{{dx}}{{dy}}={x}\:\Rightarrow\int\frac{{dy}}{\mathrm{1}+{y}}=\int\frac{{dx}}{{x}}\:\Rightarrow\mathrm{1}+{y}={Cx} \\ $$ Answered by…

v2-245-Editor-allow-to-post-content-using-following-Font-abc-ab-xyz-test-200-10-10-bc-table-determinant-2-4-3-5-also-you-write-posts-using-any-laguage-font-supported-in-app-You-

Question Number 126226 by Tinku Tara last updated on 18/Dec/20 $$\mathrm{v2}.\mathrm{245} \\ $$$$\mathrm{Editor}\:\mathrm{allow}\:\mathrm{to}\:\mathrm{post}\:\mathrm{content}\:\mathrm{using} \\ $$$$\mathrm{following} \\ $$$$\mathrm{Font}\underline{\:\mathrm{abc}}\:\underset{\mathrm{test}} {\underbrace{\mathrm{ab}..\mathrm{xyz}}}\:\:\:\:\frac{\mathrm{200}×\cancel{\mathrm{10}}}{\cancel{\mathrm{10}}}\:\:\Sigma\mathrm{bc} \\ $$$$\mathrm{table}\:\begin{array}{|c|c|}{\mathrm{2}}&\hline{\mathrm{4}}\\{\mathrm{3}}&\hline{\mathrm{5}}\\\hline\end{array} \\ $$$$\mathrm{also}\:\mathrm{you}\:\mathrm{write}\:\mathrm{posts}\:\mathrm{using}\:\mathrm{any} \\ $$$$\mathrm{laguage}\:\mathrm{font}\:\mathrm{supported}\:\mathrm{in}-\mathrm{app}. \\…