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Author: Tinku Tara

if-pi-is-rational-then-there-exists-a-I-n-v-2n-n-0-pi-x-n-x-pi-n-sin-x-dx-can-someone-give-a-easier-way-to-expaned-this-

Question Number 60621 by fjdjdcjv last updated on 22/May/19 $${if}\:\pi\:{is}\:{rational}\:{then}\:{there} \\ $$$${exists}\:{a}\:{I}_{{n}} =\frac{{v}^{\mathrm{2}{n}} }{{n}!}\underset{\mathrm{0}} {\overset{\pi} {\int}}{x}^{{n}} \left({x}−\pi\right)^{{n}} {sin}\left({x}\right){dx} \\ $$$${can}\:{someone}\:{give}\:{a}\:{easier}\:{way}\:{to}\:{expaned}\:{this} \\ $$ Commented by MJS…

Divide-a-113mm-line-into-ratio-1-2-4-

Question Number 191688 by Mastermind last updated on 29/Apr/23 $$\mathrm{Divide}\:\mathrm{a}\:\mathrm{113mm}\:\mathrm{line}\:\mathrm{into}\:\mathrm{ratio} \\ $$$$\mathrm{1}:\mathrm{2}:\mathrm{4} \\ $$ Commented by Mastermind last updated on 29/Apr/23 $$\mathrm{Ok}\:\mathrm{my}\:\mathrm{BOSS},\:\mathrm{thank}\:\mathrm{you}! \\ $$$$\mathrm{but}\:\mathrm{i}\:\mathrm{have}\:\mathrm{about}\:\mathrm{four}\:\mathrm{questions}\:\mathrm{on} \\…

prove-that-x-2-e-x-2-cos-x-2-sin-x-2-dx-pi-sin-3-2-tan-1-2-4-125-1-4-anyone-can-help-me-with-this-please-

Question Number 60611 by aliesam last updated on 22/May/19 $${prove}\:{that}\:\underset{−\infty} {\overset{\infty} {\int}}{x}^{\mathrm{2}} {e}^{−{x}^{\mathrm{2}} } {cos}\left({x}^{\mathrm{2}} \right){sin}\left({x}^{\mathrm{2}} \right)\:{dx}\:=\:\frac{\sqrt{\pi}{sin}\left(\frac{\mathrm{3}}{\mathrm{2}}{tan}^{−\mathrm{1}} \left(\mathrm{2}\right)\right)}{\mathrm{4}\:\sqrt[{\mathrm{4}}]{\mathrm{125}}} \\ $$$${anyone}\:{can}\:{help}\:{me}\:{with}\:{this}\:{please} \\ $$$$ \\ $$ Answered…

Solve-for-x-x-1-x-1-2-1-1-x-1-2-x-

Question Number 191675 by MATHEMATICSAM last updated on 28/Apr/23 $$\mathrm{Solve}\:\mathrm{for}\:{x}\:: \\ $$$$\left({x}\:−\:\frac{\mathrm{1}}{{x}}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \:+\:\left(\mathrm{1}\:−\:\frac{\mathrm{1}}{{x}}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \:=\:{x} \\ $$ Commented by mehdee42 last updated on 29/Apr/23 $${the}\:{graph}\:{of}\:{the}\:{function}\:{is}\:{as}\:{follows}.{therefore}\:.{the}\:{given}\:\: \\…