Question Number 60496 by maxmathsup by imad last updated on 21/May/19 $${calculate}\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\frac{{lnx}}{\left(\mathrm{1}−{x}\right)^{\mathrm{2}} }{dx} \\ $$ Commented by Mr X pcx last updated on…
Question Number 126030 by Fareed last updated on 16/Dec/20 $$\mathrm{2}^{\mathrm{x}} =\mathrm{4x} \\ $$$$\mathrm{solve}\:\mathrm{it}\:\mathrm{please} \\ $$ Answered by Dwaipayan Shikari last updated on 16/Dec/20 $$\mathrm{2}^{{x}} =\mathrm{4}{x}…
Question Number 60495 by Mr X pcx last updated on 21/May/19 $${find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\frac{{ln}\left({x}\right)}{\left(\mathrm{1}−{x}^{\mathrm{2}} \right)^{\mathrm{2}} }{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 60494 by Mr X pcx last updated on 21/May/19 $${find}\:\int\:\sqrt{\sqrt{\mathrm{2}+{x}^{\mathrm{2}} }−{x}}{dx} \\ $$ Commented by maxmathsup by imad last updated on 22/May/19 $${let}\:{use}\:{the}\:{chang}.\:\sqrt{\mathrm{2}+{x}^{\mathrm{2}}…
Question Number 191567 by leandrosriv02 last updated on 26/Apr/23 Answered by Frix last updated on 26/Apr/23 $$\int\frac{\sqrt{{x}}−\mathrm{1}}{{x}^{\pi} }{dx}=\int{x}^{\frac{\mathrm{1}}{\mathrm{2}}−\pi} {dx}−\int{x}^{−\pi} {dx} \\ $$$$\mathrm{Which}\:\mathrm{is}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{using}\:\int{x}^{{r}} {dx}=\frac{{x}^{{r}+\mathrm{1}} }{{r}+\mathrm{1}} \\…
Question Number 60493 by Mr X pcx last updated on 21/May/19 $${let}\:{f}\left({x}\right)=\sqrt{\mathrm{1}+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }} \\ $$$${approximate}\:{f}\left({x}\right)\:{by}\:{a}\:{polynome} \\ $$$${at}\:{v}\left(\mathrm{0}\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 60484 by Askash last updated on 21/May/19 $${If}\:\:{a}\:+\:{b}\:+\:{c}\:=\:\mathrm{4} \\ $$$$ \\ $$$${then}\:{find} \\ $$$${a}^{\mathrm{3}} \:+\:{b}^{\mathrm{3}} \:+\:{c}^{\mathrm{3}\:} =\:? \\ $$ Commented by MJS last…
Question Number 191553 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{If}\:{a}^{\mathrm{2}} \:+\:{a}\:+\:\mathrm{1}\:=\:\mathrm{0}\:\mathrm{then}\:\mathrm{find}\:{a}^{\mathrm{5}} \:+\:{a}^{\mathrm{4}} \:+\:\mathrm{1}. \\ $$ Commented by Tinku Tara last updated on 25/Apr/23 $${a}=\omega,\:\omega^{\mathrm{2}} ,\:\mathrm{where}\:\omega\:\mathrm{is}\:\mathrm{cube}\:\mathrm{root}\:\mathrm{of}\:\mathrm{unity}.…
Question Number 191552 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{If}\:{x}^{\mathrm{2}} \:−\:\mathrm{3}{x}\:+\:\mathrm{1}\:=\:\mathrm{0}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\left({x}^{\mathrm{2}} \:+\:{x}\:+\:\frac{\mathrm{1}}{{x}}\:+\:\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)^{\mathrm{2}} \\ $$ Answered by mr W last updated on 25/Apr/23…
Question Number 191555 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{Solve} \\ $$$$\sqrt{{x}}\:+\:{y}\:=\:\mathrm{11} \\ $$$${x}\:+\:\sqrt{{y}}\:=\:\mathrm{7} \\ $$ Commented by Frix last updated on 26/Apr/23 $$\mathrm{Use}\:\mathrm{your}\:\mathrm{common}\:\mathrm{sense} \\…