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Question Number 126015 by mohammad17 last updated on 16/Dec/20 Commented by mohammad17 last updated on 16/Dec/20 $${please}\:{sir}\:{help}\:{me}\:? \\ $$ Commented by mohammad17 last updated on…
Question Number 60477 by Kunal12588 last updated on 21/May/19 Answered by tanmay last updated on 21/May/19 $${v}\frac{{dv}}{{dx}}=−{k}\left({L}−{x}\right) \\ $$$${intregating} \\ $$$$\frac{{v}^{\mathrm{2}} }{\mathrm{2}}=−{k}\left({Lx}−\frac{{x}^{\mathrm{2}} }{\mathrm{2}}\right)+{c} \\ $$$${v}_{}…
Question Number 126010 by bramlexs22 last updated on 16/Dec/20 Answered by liberty last updated on 16/Dec/20 $${The}\:{area}\:{of}\:{a}\:{tringle}\:{is}\:{A}=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{8}\right)\left(\mathrm{6}\right)\mathrm{sin}\:\theta \\ $$$${A}\:=\:\mathrm{24}\:\mathrm{sin}\:\theta \\ $$$$\frac{{dA}}{{dt}}\:=\:\left(\mathrm{24}\:\mathrm{cos}\:\theta\right)\:\frac{{d}\theta}{{dt}}\:;\:{where}\:\frac{{d}\theta}{{dt}}\:=\:\mathrm{0}.\mathrm{12}\:{rad}/{sec} \\ $$$$\Leftrightarrow\:\frac{{dA}}{{dt}}\:=\:\mathrm{24}×\mathrm{0}.\mathrm{12}×\mathrm{cos}\:\frac{\pi}{\mathrm{6}}=\:\mathrm{2}.\mathrm{49}\:{m}^{\mathrm{2}} /{sec}\: \\…
Question Number 60475 by Tawa1 last updated on 21/May/19 Answered by tanmay last updated on 21/May/19 $$\frac{{dp}}{{dx}}=\frac{{f}\left({x}\right)\frac{{dg}\left({x}\right)}{{dx}}−\left[{g}\left({x}\right)−\mathrm{1}\right]\frac{{df}\left({x}\right)}{{dx}}}{\left\{{f}\left({x}\right)\right\}^{\mathrm{2}} } \\ $$$${p}'\left(\mathrm{2}\right)=\frac{{f}\left(\mathrm{2}\right){g}'\left(\mathrm{2}\right)−\left[{g}\left(\mathrm{2}\right)−\mathrm{1}\right]{f}'\left(\mathrm{2}\right)}{{f}^{\mathrm{2}} \left(\mathrm{2}\right)} \\ $$$$=\frac{\left(−\mathrm{1}\right)\left(−{sin}\mathrm{2}\right)−\left[{cos}\mathrm{2}−\mathrm{1}\right]\mathrm{5}}{\left(−\mathrm{1}\right)^{\mathrm{2}} } \\…
Question Number 126008 by bramlexs22 last updated on 16/Dec/20 $$\:{Find}\:{all}\:{asymptotes}\:{of}\:{the}\: \\ $$$${function}\:{y}=\frac{{x}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}}}\:. \\ $$ Answered by liberty last updated on 16/Dec/20 $${Horizontal}\:{asymptote}\::\:{y}\:=\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{{x}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}}}\:=\:\underset{{x}\rightarrow\infty}…
Question Number 191546 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{If}\:{m}\:+\:\mathrm{1}\:=\:\sqrt{{n}}\:+\:\mathrm{3}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{{m}^{\mathrm{3}} \:−\:\mathrm{6}{m}^{\mathrm{2}} \:+\:\mathrm{12}{m}\:−\mathrm{8}}{\:\sqrt{{n}}}\:−\:{n}\right) \\ $$ Answered by som(math1967) last updated on 25/Apr/23 $$\frac{\mathrm{1}}{\mathrm{2}}×\left\{\frac{\left({m}−\mathrm{2}\right)^{\mathrm{3}} }{\:\sqrt{{n}}}\:−{n}\right\}…
Question Number 126005 by bramlexs22 last updated on 16/Dec/20 $$\:\:{Find}\:{all}\:{solution}\:\mathrm{7cos}\:\left(\mathrm{3}{x}\right)−\mathrm{1}=\:\mathrm{3}\: \\ $$$${for}\:{x}\:{over}\:{the}\:{interval}\:\left[\:\mathrm{0},\mathrm{2}\pi\:\right]\: \\ $$ Commented by liberty last updated on 16/Dec/20 $$\:\mathrm{7}\:\mathrm{cos}\:\left(\mathrm{3}{x}\right)=\mathrm{4}\:\Rightarrow\mathrm{cos}\:\left(\mathrm{3}{x}\right)=\frac{\mathrm{4}}{\mathrm{7}}\: \\ $$$$\:\mathrm{3}{x}\:=\:\mathrm{cos}^{−\mathrm{1}} \left(\frac{\mathrm{4}}{\mathrm{7}}\right)\:=\:\mathrm{0}.\mathrm{963}…
Question Number 191536 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{Factorize} \\ $$$$\frac{\mathrm{2}}{\mathrm{2}{x}\:−\:\mathrm{1}}\:−\mathrm{5}\:+\:\frac{\mathrm{3}}{\mathrm{3}{x}\:−\:\mathrm{1}} \\ $$ Answered by som(math1967) last updated on 25/Apr/23 $$\frac{\mathrm{2}}{\mathrm{2}{x}−\mathrm{1}}−\mathrm{3}+\frac{\mathrm{3}}{\mathrm{3}{x}−\mathrm{1}}−\mathrm{2} \\ $$$$=\frac{\mathrm{2}−\mathrm{6}{x}+\mathrm{3}}{\mathrm{2}{x}−\mathrm{1}}\:+\frac{\mathrm{3}−\mathrm{6}{x}+\mathrm{2}}{\mathrm{3}{x}−\mathrm{1}} \\…