Question Number 125922 by mnjuly1970 last updated on 15/Dec/20 $$\:\:\:\:\:\:\:\:\:…{advanced}\:\:\:{calculus}… \\ $$$$\:\:\:\:\:\:\:{evaluate}\::::\:\:\:\Omega\overset{???} {=}\int_{\mathrm{0}} ^{\:\infty} {cos}\left({x}^{\mathrm{2}} \right){ln}\left({x}\right){dx} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\::::::::::\:\:\:\:\:\: \\ $$ Answered by mathmax by abdo…
Question Number 191456 by Mingma last updated on 24/Apr/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 60386 by Kunal12588 last updated on 20/May/19 $$\underset{{x}\rightarrow\mathrm{0}} {{lim}}\frac{{sin}\left(\pi{cos}^{\mathrm{2}} {x}\right)}{{x}^{\mathrm{2}} } \\ $$$${why}\:{it}\:{can}\:{not}\:{be}\:{solved}\:{this}\:{way} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {{lim}}\:\frac{{sin}\left(\pi{cos}^{\mathrm{2}} {x}\right)}{{x}^{\mathrm{2}} } \\ $$$$=\underset{{x}\rightarrow\mathrm{0}} {{lim}}\:\frac{{sin}\left(\pi{cos}^{\mathrm{2}} {x}\right)}{\pi{cos}^{\mathrm{2}} {x}}×\underset{{x}\rightarrow\mathrm{0}}…
Question Number 191458 by Mingma last updated on 24/Apr/23 Answered by a.lgnaoui last updated on 26/Apr/23 $$\bigtriangleup\mathrm{ACD}\:\:\mathrm{et}\:\bigtriangleup\mathrm{BCD}\:\:\mathrm{semblablables} \\ $$$$\mathrm{AB}\:\mathrm{tangdnte}\:\mathrm{au}\:\mathrm{quart}\:\mathrm{cercle}\:\mathrm{Rouge}\:\mathrm{en}\:\mathrm{D} \\ $$$$\mathrm{CD}=\mathrm{R2}\:\:\:\mathrm{CD}\bot\mathrm{AB}\:\:;\mathrm{BC}=\mathrm{R1}+\mathrm{R2} \\ $$$$\left(\mathrm{R1}\:\mathrm{rayon}\:\mathrm{du}\:\:\mathrm{quart}\:\:\mathrm{cercle}\:\mathrm{vert}.\right. \\ $$$$\mathrm{ABC}\:\mathrm{triangle}\:\:\mathrm{recrangle}\:\mathrm{en}\:\mathrm{C}…
Question Number 60384 by aliesam last updated on 20/May/19 $$\int{e}^{{coth}^{−\mathrm{1}} \left({x}\right)} \:{dx}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125918 by I want to learn more last updated on 15/Dec/20 $$\underset{\mathrm{n}\:\:=\:\:−\:\:\infty} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\left(\mathrm{n}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{3}}\right)^{\mathrm{3}} } \\ $$ Answered by mindispower last updated on…
Question Number 125919 by Eric002 last updated on 15/Dec/20 $$\int_{\mathrm{0}} ^{\infty} \int_{\mathrm{0}} ^{\infty} \int_{\mathrm{0}} ^{\infty} \int_{\mathrm{0}} ^{\infty} \frac{{dx}\:{dy}\:{dz}\:{dt}}{\left({cosh}\left({x}\right)+{cosh}\left({y}\right)+{cosh}\left({z}\right)+{cosh}\left({t}\right)\right)^{\mathrm{4}} } \\ $$$$=\frac{\mathrm{7}\zeta\left(\mathrm{3}\right)−\mathrm{6}}{\mathrm{12}} \\ $$ Terms of…
Question Number 191455 by Mingma last updated on 24/Apr/23 Answered by a.lgnaoui last updated on 25/Apr/23 $$\:\bigtriangleup\mathrm{ANB}\:\:\:\mathrm{BM}\bot\mathrm{AN}\:\:\mathrm{et}\:\measuredangle\mathrm{MBA}=\measuredangle\mathrm{MBN} \\ $$$$\:\Rightarrow\mathrm{AB}=\mathrm{BN}=\frac{\boldsymbol{\mathrm{x}}}{\mathrm{cos}\:\boldsymbol{\theta}}\:\:\:\:\:\:\:\:\left(\mathrm{1}\right) \\ $$$$\:\bigtriangleup\mathrm{PNC}\:\:\:\:\:\:\mathrm{PC}=\mathrm{3cm} \\ $$$$\:\mathrm{BM}\mid\mid\:\mathrm{NP}\:\:\Rightarrow\:\measuredangle\:\mathrm{PNC}=\measuredangle\mathrm{MBN}=\theta=\measuredangle\mathrm{PCN} \\ $$$$\:\Rightarrow\mathrm{NP}=\mathrm{PC}=\mathrm{3}…
Question Number 191454 by Mingma last updated on 24/Apr/23 Commented by mr W last updated on 24/Apr/23 $${xyz}=\frac{\mathrm{646}}{\mathrm{25}} \\ $$ Commented by Mingma last updated…
Question Number 125915 by john_santu last updated on 15/Dec/20 $${Darren}\:{McFaddden}\:{of}\:{Arkansas} \\ $$$${placed}\:{second}\:{overall}\:{in}\:{the}\:{Heisman} \\ $$$${Trophy}\:{voting}.\:{Players}\:{are}\:{given} \\ $$$$\mathrm{3}\:{points}\:{for}\:{every}\:{first}−{place}\:{vote}\: \\ $$$$,\:\mathrm{2}\:{points}\:{for}\:{every}\:{second}−{place}\:{vote} \\ $$$${and}\:\mathrm{1}\:{point}\:{for}\:{every}\:{third}−{place}\:{vote}. \\ $$$${McFadden}\:{received}\:\mathrm{490}\:{total}\:{votes} \\ $$$${for}\:{first}\:,\:{second}\:{and}\:{third}\:{place}\: \\…