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dx-tan-4-x-1-

Question Number 125895 by john_santu last updated on 15/Dec/20 $$\:\:\:\:\int\:\frac{{dx}}{\mathrm{tan}\:^{\mathrm{4}} {x}+\mathrm{1}}\:? \\ $$ Answered by Dwaipayan Shikari last updated on 15/Dec/20 $$\int\frac{{dx}}{{tan}^{\mathrm{4}} {x}+\mathrm{1}}\:\:\:\:\:\:\:\:\:{tanx}={t}\Rightarrow{sec}^{\mathrm{2}} {x}=\frac{{dt}}{{dx}} \\…

Question-60357

Question Number 60357 by Sardor2211 last updated on 20/May/19 Commented by Mr X pcx last updated on 20/May/19 $${the}\:{equation}\:{is}\:{not}\:{clear}\:{but}\:{i}\:{suppose} \\ $$$${that}\:{is}\:\left(\mathrm{1}+{x}^{\mathrm{2}} \right){y}^{'} −\mathrm{2}{xy}\:=\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{\mathrm{2}} \\…

tan-3-x-sec-x-dx-

Question Number 125889 by bramlexs22 last updated on 15/Dec/20 $$\:\:\int\:\frac{\mathrm{tan}\:^{\mathrm{3}} {x}}{\:\sqrt{\mathrm{sec}\:{x}}}\:{dx}\:?\: \\ $$ Answered by bobhans last updated on 15/Dec/20 $$\int\:\frac{\mathrm{tan}\:{x}\left(\mathrm{sec}\:^{\mathrm{2}} {x}−\mathrm{1}\right)}{\:\sqrt{\mathrm{sec}\:{x}}}\:{dx}\:= \\ $$$$\:\left[\:\mathrm{sec}\:{x}\:=\:{u}^{\mathrm{2}} \:\Rightarrow\mathrm{tan}\:{x}\:{dx}\:=\:\frac{\mathrm{2}\:{du}}{{u}}\:\right]…

n-0-5-2-n-2n-n-2n-1-5-1-5-n-1-2-5-1-5-n-1-2-

Question Number 125884 by Dwaipayan Shikari last updated on 14/Dec/20 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(\sqrt{\mathrm{5}}−\mathrm{2}\right)^{{n}} \begin{pmatrix}{\mathrm{2}{n}}\\{{n}}\end{pmatrix}}{\left(\left(\mathrm{2}{n}+\mathrm{1}\right)\left(\left(\sqrt{\mathrm{5}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}\right)^{{n}+\frac{\mathrm{1}}{\mathrm{2}}} +\left(\sqrt{\mathrm{5}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}\right)^{{n}−\frac{\mathrm{1}}{\mathrm{2}}} \right)\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com