Question Number 191324 by Mingma last updated on 23/Apr/23 Answered by HeferH last updated on 23/Apr/23 $$\mathrm{r}\:=\:\mathrm{20} \\ $$$$\mathrm{S}\:=\:\frac{\mathrm{15}×\mathrm{20}}{\mathrm{2}}\:+\:\frac{\mathrm{7}×\mathrm{24}}{\mathrm{2}}\:=\:\mathrm{150}+\mathrm{84}\:=\:\mathrm{234}\:\mathrm{u}^{\mathrm{2}} \: \\ $$ Commented by Mingma…
Question Number 191323 by Mingma last updated on 23/Apr/23 Answered by mr W last updated on 23/Apr/23 $$\frac{{A}}{{A}+{B}}=\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\frac{{A}}{{A}+{B}+{C}}=\left(\frac{\mathrm{1}}{\mathrm{3}}\right)^{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{9}} \\ $$$$\Rightarrow{A}=\frac{{A}+{B}+{C}}{\mathrm{9}} \\…
Question Number 125785 by Mathgreat last updated on 13/Dec/20 $$\oplus+\oplus+\oplus=\mathrm{33} \\ $$$$\blacktriangle+\blacktriangle+\mathrm{9}\blacktrinagledown=\mathrm{25} \\ $$$$\mathrm{9}\blacktrinagledown+\blacktriangle+\mathrm{2}\bigstar=\mathrm{19} \\ $$$$\mathrm{2}\oplus+\mathrm{8}\blacktrinagledown\:\centerdot\:\bigstar=\:? \\ $$$$\:\: \\ $$ Answered by Olaf last updated…
Question Number 125782 by ajfour last updated on 13/Dec/20 Commented by ajfour last updated on 13/Dec/20 $${Find}\:{radius}\:{of}\:{the}\:{smaller}\:{circle}. \\ $$ Commented by MJS_new last updated on…
Question Number 60247 by pete last updated on 19/May/19 $$\mathrm{A}\:\mathrm{uniform}\:\mathrm{pole}\:\mathrm{PQ},\:\mathrm{30}\:\mathrm{m}\:\mathrm{long}\:\mathrm{and}\:\mathrm{of}\:\mathrm{mass} \\ $$$$\mathrm{4}\:\mathrm{kg}\:\mathrm{is}\:\mathrm{carried}\:\mathrm{by}\:\mathrm{a}\:\mathrm{boy}\:\mathrm{at}\:\mathrm{P}\:\mathrm{and}\:\mathrm{a}\:\mathrm{man}\: \\ $$$$\mathrm{8}\:\mathrm{m}\:\mathrm{away}\:\mathrm{from}\:\mathrm{Q}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{from} \\ $$$$\mathrm{P}\:\mathrm{where}\:\mathrm{a}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{20}\:\mathrm{kg}\:\mathrm{should}\:\mathrm{be}\:\mathrm{attached} \\ $$$$\mathrm{so}\:\mathrm{that}\:\mathrm{the}\:\mathrm{man}'\mathrm{s}\:\mathrm{support}\:\mathrm{is}\:\mathrm{twice}\:\mathrm{that} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{boy},\:\mathrm{if}\:\mathrm{the}\:\mathrm{system}\:\mathrm{is}\:\mathrm{in}\:\mathrm{equilibrium} \\ $$$$\left[\mathrm{Take}\:\mathrm{g}=\mathrm{10ms}^{−\mathrm{2}} \right] \\ $$…
Question Number 125781 by Dwaipayan Shikari last updated on 13/Dec/20 $$\int_{\mathrm{0}} ^{\infty} \frac{\sqrt{{x}}}{\mathrm{1}−{x}^{\mathrm{2}} }.\frac{\mathrm{1}}{{e}^{\mathrm{2}\pi{x}} −\mathrm{1}}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 60241 by ANTARES VY last updated on 19/May/19 Commented by mr W last updated on 19/May/19 $${question}\:{not}\:{clear}. \\ $$ Terms of Service Privacy…
Question Number 60240 by ANTARES VY last updated on 19/May/19 $$\underset{\mathrm{0}} {\overset{\mathrm{2}} {\int}}\frac{\boldsymbol{\mathrm{ln}}\left(\boldsymbol{\mathrm{x}}\right)}{\:\sqrt{\mathrm{4}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} }}\boldsymbol{\mathrm{dx}} \\ $$ Commented by maxmathsup by imad last updated on 19/May/19…
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Question Number 60237 by rahul 19 last updated on 19/May/19 Commented by rahul 19 last updated on 20/May/19 $$?????? \\ $$ Terms of Service Privacy…