Question Number 60189 by Tinkutara last updated on 18/May/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125722 by Mammadli last updated on 13/Dec/20 $$\underset{\boldsymbol{{x}}\rightarrow\infty} {\boldsymbol{{lim}}}\left(\frac{\mathrm{3}\boldsymbol{{x}}+\mathrm{6}}{\mathrm{3}\boldsymbol{{x}}+\mathrm{2}}\right)^{\boldsymbol{{x}}+\mathrm{2}} =? \\ $$ Answered by liberty last updated on 13/Dec/20 $${let}\:{us}\:{denote}\:{h}\left({x}\right)=\frac{\mathrm{3}{x}+\mathrm{6}}{\mathrm{3}{x}+\mathrm{2}}\:;\:{r}\left({x}\right)={x}+\mathrm{2} \\ $$$$\:\begin{cases}{\underset{{x}\rightarrow\infty} {\mathrm{lim}}{h}\left({x}\right)=\underset{{x}\rightarrow\infty}…
Question Number 125721 by bramlexs22 last updated on 13/Dec/20 $$\:\left(\mathrm{3}{xy}+\mathrm{2}{x}^{\mathrm{2}} \right){dy}\:+\:\left(\mathrm{3}{x}^{\mathrm{2}} +\mathrm{3}{y}\right){dx}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 191254 by anr0h3 last updated on 21/Apr/23 $$ \\ $$$${a}=\frac{{x}−{a}}{{x}−{b}}\:{solve}\:{for}\:{x} \\ $$$$\mathrm{did}\:\mathrm{i}\:\mathrm{make}\:\mathrm{anything}\:\mathrm{wrong}\:\mathrm{in}\:\mathrm{the}\:\mathrm{following}? \\ $$$$ \\ $$$$\mathrm{starpoint}: \\ $$$${ln}\mid{a}\mid={ln}\mid\frac{{x}−{a}}{{x}−{b}}\mid \\ $$$${ln}\mid{a}\mid={ln}\mid{x}−{a}\mid−{ln}\mid{x}−{b}\mid \\ $$$${ln}\mid{a}\mid={ln}\mid\frac{{x}}{{a}}\mid−{ln}\mid\frac{{x}}{{b}}\mid \\…
Question Number 191250 by mnjuly1970 last updated on 21/Apr/23 Commented by mr W last updated on 21/Apr/23 $${it}'{s}\:{not}\:{clear}. \\ $$$${please}\:{give}\:{an}\:{example}\:{what}\:{is}\:{vaild}! \\ $$ Commented by mnjuly1970…
Question Number 60175 by MJS last updated on 18/May/19 $$\mathrm{solving}\:{u}^{{v}} ={w}\:\mathrm{with}\:{u},\:{v},\:{w}\:\in\mathbb{C} \\ $$$$\mathrm{finding}\:\mathrm{all}\:\mathrm{possible}\:\mathrm{solutions} \\ $$$$\mathrm{I}\:\mathrm{tested}\:\mathrm{this}\:\mathrm{with}\:\mathrm{several}\:\mathrm{values}\:\mathrm{and}\:\mathrm{found} \\ $$$$\mathrm{no}\:\mathrm{mistake}.\:\mathrm{please}\:\mathrm{review}\:\mathrm{and}\:\mathrm{comment}. \\ $$$$\mathrm{I}\:\mathrm{hope}\:\mathrm{this}\:\mathrm{will}\:\mathrm{help}\:\mathrm{at}\:\mathrm{least}\:\mathrm{some}\:\mathrm{of}\:\mathrm{you}. \\ $$ Commented by MJS last…
Question Number 125711 by TITA last updated on 13/Dec/20 $$\:\mathrm{I}=\int\frac{\mathrm{cos}\:\mathrm{2x}}{\mathrm{1}+\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}}\mathrm{dx}\:=?\:\:\mathrm{please}\:\mathrm{help} \\ $$$$ \\ $$ Answered by bramlexs22 last updated on 13/Dec/20 $${let}\:\mathrm{tan}\:\left({x}\right)=\:{t}\:\wedge\:{dt}\:=\:\frac{{dx}}{\mathrm{cos}\:^{\mathrm{2}} {x}} \\…
Question Number 125708 by Dwaipayan Shikari last updated on 13/Dec/20 $$\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{1}−{tanhx}}{\:\sqrt[{\mathrm{5}}]{{tanhx}}}{dx} \\ $$ Answered by mindispower last updated on 13/Dec/20 $${e}^{{x}} ={t} \\…
Question Number 125709 by mr W last updated on 13/Dec/20 Commented by mr W last updated on 13/Dec/20 $${the}\:{parabola}\:{of}\:{shape}\:{y}={x}^{\mathrm{2}} \:{rolls} \\ $$$${along}\:{the}\:{circle}\:{with}\:{radius}\:{r}.\: \\ $$$$\mathrm{1}.\:{find}\:{the}\:{locus}\:{of}\:{its}\:{vertex}\:{A}. \\…
Question Number 60170 by necx1 last updated on 18/May/19 $$\int{x}\mathrm{sec}\:^{\mathrm{3}} {xdx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com