Question Number 60152 by Kunal12588 last updated on 18/May/19 $${Join}\:{Telegram}\:{group} \\ $$$$@{booksforjee} \\ $$$${To}\:{get}\:{evry}\:{books}\:{pdfs} \\ $$$${related}\:{to}\:{NEET},\:{JEE}\left({MAIN}\:{ADVANCED}\right) \\ $$$${and}\:{all}\:{engineering}\:{entrance}\:{exam}\:{books} \\ $$$${Also} \\ $$$${Books}\:{for}\:{class}\:{XII},{XI},{X},{IX} \\ $$ Commented…
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Question Number 125686 by mathocean1 last updated on 12/Dec/20 $${show}\:{that} \\ $$$${cos}\frac{\mathrm{4}\pi}{\mathrm{5}}+{cos}\frac{\mathrm{2}\pi}{\mathrm{5}}+\mathrm{1}=\mathrm{0} \\ $$ Commented by bramlexs22 last updated on 13/Dec/20 $$\mathrm{cos}\:\frac{\mathrm{4}\pi}{\mathrm{5}}\:=\:\mathrm{cos}\:\left(\pi−\frac{\pi}{\mathrm{5}}\right)=−\mathrm{cos}\:\frac{\pi}{\mathrm{5}} \\ $$$$\mathrm{cos}\:\frac{\mathrm{4}\pi}{\mathrm{5}}\:=\:−\mathrm{cos}\:\mathrm{36}°\: \\…
Question Number 191220 by anr0h3 last updated on 21/Apr/23 $${x}^{\mathrm{6}} −{x}^{\mathrm{3}} =\mathrm{2}\:{solve}\:{for}\:{x} \\ $$$$ \\ $$$${m}={x}^{\mathrm{3}} \\ $$$${m}^{\mathrm{2}} =\left({x}^{\mathrm{3}} \right)^{\mathrm{2}} \\ $$$${m}^{\mathrm{2}} −{m}=\mathrm{2} \\ $$$${m}^{\mathrm{2}}…
Question Number 125684 by mnjuly1970 last updated on 13/Dec/20 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:….\:\mathrm{INTEGRAL}… \\ $$$$\:\:\:\:\mathrm{prove}\:\:\mathrm{that}\:: \\ $$$$\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\infty} {x}^{\mathrm{3}} \left\{{ln}\left(\mathrm{1}+{e}^{{x}} \right)\:−{x}\right\}{dx}=\frac{\mathrm{45}}{\mathrm{8}}\:\zeta\left(\:\mathrm{5}\:\right) \\ $$$$ \\ $$ Answered by Dwaipayan…
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Question Number 125685 by Hassen_Timol last updated on 12/Dec/20 $$ \\ $$$$\mathrm{Solve}\:\mathrm{this}\:\mathrm{differential}\:\mathrm{equation} \\ $$$$ \\ $$$$\:\:\:\:\:{q}_{\left({t}\right)} ''\:\:+\:\:\frac{\mathrm{1}}{\mathrm{LC}}\:{q}_{\left({t}\right)} \:\:=\:\:\frac{{V}}{{L}} \\ $$$$ \\ $$$$\mathrm{with}\:\left(\mathrm{L},\mathrm{C},\mathrm{V}\right)\:\in\:\mathbb{R}^{\mathrm{3}} \\ $$$$ \\…
Question Number 60143 by pete last updated on 18/May/19 $$\mathrm{Two}\:\mathrm{passenger}\:\mathrm{trains},\:\mathrm{A}\:\mathrm{and}\:\mathrm{B},\:\mathrm{450km}\:\mathrm{apart}, \\ $$$$\mathrm{start}\:\mathrm{to}\:\mathrm{move}\:\mathrm{towards}\:\mathrm{each}\:\mathrm{other}\:\mathrm{at}\:\mathrm{the} \\ $$$$\mathrm{same}\:\mathrm{time}\:\mathrm{and}\:\mathrm{meet}\:\mathrm{after}\:\mathrm{2}\:\mathrm{hours}.\:\mathrm{If}\:\mathrm{train}\:\mathrm{B}, \\ $$$$\mathrm{travels}\:\frac{\mathrm{8}}{\mathrm{7}}\:\mathrm{as}\:\mathrm{fast}\:\mathrm{as}\:\mathrm{train}\:\mathrm{A},\:\mathrm{find}\:\mathrm{the}\:\mathrm{speed} \\ $$$$\mathrm{of}\:\mathrm{each}\:\mathrm{train}. \\ $$ Answered by tanmay last updated…
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Question Number 125672 by mathocean1 last updated on 12/Dec/20 $${N}={x}\mathrm{32}{y}\:{in}\:{base}\:\mathrm{10}.\: \\ $$$${N}\equiv\mathrm{0}\left[\mathrm{3}\right]\:{and}\:{N}\equiv\mathrm{0}\left[\mathrm{4}\right]. \\ $$$${N}>\mathrm{8329} \\ $$$${N}\:{has}\:{four}\:{digits}. \\ $$$${Determinate}\:{N}. \\ $$ Answered by JDamian last updated…