Question Number 191203 by otchereabdullai last updated on 20/Apr/23 $$\:{If}\:\:\mathrm{3}^{{x}} =−\mathrm{1}\:{find}\:{the}\:{value}\:{of}\:{x} \\ $$ Answered by Frix last updated on 20/Apr/23 $$\mathrm{3}^{{x}} =−\mathrm{1} \\ $$$$\mathrm{e}^{{x}\mathrm{ln}\:\mathrm{3}} =\mathrm{e}^{\mathrm{i}\left(\mathrm{2}{n}+\mathrm{1}\right)\pi}…
Question Number 125664 by fajri last updated on 12/Dec/20 $$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:+\:\mathrm{4}\frac{{dy}}{{dx}}\:\:=\:\mathrm{3}\:{cosec}\:\theta \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125662 by physicstutes last updated on 12/Dec/20 $$\:\mathcal{I}\:=\:\underset{\mathrm{0}} {\overset{\mathrm{4}} {\int}}\:\mathrm{tanh}^{−\mathrm{1}} \:\mathrm{2}{x}\:{dx}\:=\:??? \\ $$ Answered by mathmax by abdo last updated on 12/Dec/20 $$\mathrm{th}\left(\mathrm{x}\right)=\mathrm{y}\:\Rightarrow\mathrm{y}=\frac{\mathrm{sh}\left(\mathrm{x}\right)}{\mathrm{ch}\left(\mathrm{x}\right)}=\frac{\mathrm{e}^{\mathrm{x}}…
Question Number 125663 by Mammadli last updated on 12/Dec/20 $$\frac{\mathrm{1}}{\mathrm{6}^{\mathrm{1}} }+\frac{\mathrm{2}}{\mathrm{6}^{\mathrm{2}} }+\frac{\mathrm{3}}{\mathrm{6}^{\mathrm{3}} }+…+\frac{{n}}{\mathrm{6}^{{n}} }=? \\ $$ Answered by Dwaipayan Shikari last updated on 12/Dec/20 $${S}=\frac{\mathrm{1}}{\mathrm{6}}+\frac{\mathrm{2}}{\mathrm{6}^{\mathrm{2}}…
Question Number 191199 by 073 last updated on 20/Apr/23 Commented by 073 last updated on 20/Apr/23 $$\mathrm{sheed}\:\mathrm{area}=?? \\ $$ Answered by cortano12 last updated on…
Question Number 125661 by Mammadli last updated on 12/Dec/20 $$\boldsymbol{{a}}^{\boldsymbol{{x}}} \:=\:\boldsymbol{{b}}^{\boldsymbol{{y}}} \:=\:\boldsymbol{{c}}^{\boldsymbol{{z}}} \\ $$$$\boldsymbol{{x}}^{\boldsymbol{{a}}} \:+\:\boldsymbol{{y}}^{\boldsymbol{{b}}} \:+\:\boldsymbol{{z}}^{\boldsymbol{{c}}} \:=\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 191192 by ajfour last updated on 20/Apr/23 Commented by ajfour last updated on 20/Apr/23 $${If}\:{lower}\:{circle}\:{has}\:{radius}\:{a}\:{while} \\ $$$${upper}\:{has}\:{radius}\:{b},\:{find}\:\theta. \\ $$ Answered by mr W…
Question Number 125659 by Mammadli last updated on 12/Dec/20 $$\frac{\mathrm{1}}{\mathrm{2020}^{\mathrm{1}} }+\frac{\mathrm{2}}{\mathrm{2020}^{\mathrm{2}} }+\frac{\mathrm{3}}{\mathrm{2020}^{\mathrm{3}} }+…+\frac{\boldsymbol{{n}}}{\mathrm{2020}^{\boldsymbol{{n}}} }=? \\ $$ Answered by Dwaipayan Shikari last updated on 12/Dec/20 $${S}=\frac{\mathrm{1}}{\mathrm{2020}}+\frac{\mathrm{2}}{\mathrm{2020}^{\mathrm{2}}…
Question Number 60121 by rahul 19 last updated on 18/May/19 Commented by rahul 19 last updated on 18/May/19 $${time}\:{period}\:{is}\:{given}\:{as}\::\:\mathrm{2}\pi\sqrt{\frac{\rho{L}}{\sigma{g}}}\:. \\ $$$${Isn}'{t}\:{data}\:{insufficient}\:? \\ $$ Commented by…
Question Number 125654 by ajfour last updated on 12/Dec/20 Commented by ajfour last updated on 12/Dec/20 $${Find}\:{R}/{r}. \\ $$ Answered by mr W last updated…