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Question-60088

Question Number 60088 by ajfour last updated on 17/May/19 Commented by ajfour last updated on 17/May/19 $$\mathrm{Only}\:\mathrm{hemisphere}\:\mathrm{of}\:\mathrm{radius}\:\mathrm{R}\:\mathrm{is}\:\mathrm{grassy}, \\ $$$$\mathrm{and}\:\mathrm{occupies}\:\mathrm{central}\:\mathrm{area}\:\mathrm{of}\:\mathrm{a} \\ $$$$\mathrm{square}\:\mathrm{field}\:\mathrm{of}\:\mathrm{side}\:\mathrm{a}>\:\mathrm{2R}. \\ $$$$\mathrm{A}\:\mathrm{goat}\:\mathrm{tied}\:\mathrm{at}\:\mathrm{front}\:\mathrm{right}\:\mathrm{corner} \\ $$$$\mathrm{with}\:\mathrm{a}\:\mathrm{rope}\:\mathrm{of}\:\mathrm{length}\:{l}=\:\frac{{a}}{\mathrm{2}}\:,…

Consider-a-continuously-differentiable-function-f-0-1-R-such-that-f-0-0-and-f-1-1-Find-the-minimum-value-of-0-1-f-x-2-1-x-2-dx-

Question Number 125621 by ZiYangLee last updated on 12/Dec/20 $$\mathrm{Consider}\:\mathrm{a}\:\mathrm{continuously}\:\mathrm{differentiable} \\ $$$$\mathrm{function}\:{f}:\left[\mathrm{0},\mathrm{1}\right]\rightarrow\mathbb{R}\:\mathrm{such}\:\mathrm{that}\:{f}\left(\mathrm{0}\right)=\mathrm{0} \\ $$$$\mathrm{and}\:{f}\left(\mathrm{1}\right)=\mathrm{1}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{minimum} \\ $$$$\mathrm{value}\:\mathrm{of}\:\int_{\mathrm{0}} ^{\mathrm{1}} \left({f}'\left({x}\right)\right)^{\mathrm{2}} \sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\:{dx} \\ $$ Terms of Service…

Question-191155

Question Number 191155 by mathlove last updated on 19/Apr/23 Answered by mahdipoor last updated on 19/Apr/23 $${log}\left({xy}\right)={log}\left({x}\right)+{log}\left({y}\right)\Rightarrow{x}={a}\:,\:{y}=\mathrm{1}+\frac{{b}}{{a}}\:\Rightarrow \\ $$$${log}\left({a}+{b}\right)={log}\left({a}\right)+{log}\left(\mathrm{1}+{b}/{a}\right) \\ $$$$…….. \\ $$$${b}=\mathrm{10}^{{B}} \:,\:{a}=\mathrm{10}^{{A}} \:,\:{c}=\mathrm{10}^{{C}}…

f-x-f-1-x-x-2-gt-f-x-

Question Number 191151 by TUN last updated on 19/Apr/23 $${f}\left({x}\right)+{f}\left(\mathrm{1}−{x}\right)={x}^{\mathrm{2}} \\ $$$$=>{f}\left({x}\right)=¿ \\ $$ Answered by Rasheed.Sindhi last updated on 19/Apr/23 $${f}\left({x}\right)+{f}\left(\mathrm{1}−{x}\right)={x}^{\mathrm{2}} …….\left({i}\right) \\ $$$${Replacing}\:{x}\:{by}\:\mathrm{1}−{x}:…