Question Number 191052 by otchereabdullai last updated on 17/Apr/23 $${A}\:{particle}\:{Q}\:{is}\:{moving}\:{with}\:{constant} \\ $$$${velocity}\:\left(−\mathrm{5}{i}+\mathrm{3}{j}\right){m}/{s}.\:{At}\:{time}\: \\ $$$${t}=\mathrm{5}{sec}\:,\:{Q}\:{is}\:{at}\:{the}\:{same}\:{point}\:{with} \\ $$$${position}\:{vector}\:\left(−{i}−\mathrm{5}{j}\right){m}.\:{Find}\:{the} \\ $$$${distance}\:{of}\:{Q}\:{from}\:{the}\:{origin}\:{at}\: \\ $$$${time}\:{t}=\mathrm{2}{sec} \\ $$ Answered by mr…
Question Number 191049 by Mingma last updated on 16/Apr/23 Commented by Mingma last updated on 17/Apr/23 Nice solution, sir! Answered by aleks041103 last updated on 17/Apr/23 $${cos}\left({sin}\left({x}\right)\right)={Re}\left({exp}\left({i}\:{sin}\left({x}\right)\right)\right)…
Question Number 59977 by mjay last updated on 16/May/19 $$\mathrm{4}×\left(\mathrm{5}+\mathrm{5}\right) \\ $$ Answered by meme last updated on 16/May/19 $$=\mathrm{40} \\ $$ Terms of Service…
Question Number 59975 by vajpaithegrate@gmail.com last updated on 16/May/19 Answered by tanmay last updated on 16/May/19 $${T}.{S}.{A}\:{of}\:{cone}=\pi{rl}+\pi{r}^{\mathrm{2}} \\ $$$$\left.{T}\left..{S}.{A}=\pi{r}\left({r}+\sqrt{{h}^{\mathrm{2}} +{r}^{\mathrm{2}} }\:\right)\:\:\:\:\:\right]\right]{when}\:\left[{l}^{\mathrm{2}} ={r}^{\mathrm{2}} +{h}^{\mathrm{2}} \right] \\…
Question Number 125511 by sandy_delta last updated on 11/Dec/20 $$\mathrm{if}\:: \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{f}\left(−\mathrm{x}\right)\:\mathrm{for}\:\mathrm{x}\in\mathbb{R} \\ $$$$\underset{−\mathrm{3}} {\overset{\mathrm{3}} {\int}}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{dx}\:=\:\mathrm{0} \\ $$$$\underset{−\mathrm{2}} {\overset{\mathrm{3}} {\int}}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{dx}\:=\:\mathrm{5} \\ $$$$\mathrm{then}\:\underset{\mathrm{0}} {\overset{\mathrm{2}} {\int}}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{dx}\:=\:? \\…
Question Number 59974 by vajpaithegrate@gmail.com last updated on 16/May/19 Answered by tanmay last updated on 16/May/19 $${lateral}\:{surface}\:{area}=\pi{rl} \\ $$$${given}\:{cos}\mathrm{45}^{{o}} =\frac{{h}}{{l}} \\ $$$${l}=\frac{{h}}{{cos}\mathrm{45}^{{o}} }={h}\sqrt{\mathrm{2}} \\ $$$${tan}\mathrm{45}^{{o}}…
Question Number 125508 by ajfour last updated on 11/Dec/20 Commented by ajfour last updated on 11/Dec/20 $${Find}\:{R}. \\ $$ Answered by ajfour last updated on…
Question Number 191041 by mustafazaheen last updated on 16/Apr/23 Commented by mustafazaheen last updated on 16/Apr/23 $$\mathrm{How}\:\mathrm{is}\:\mathrm{solution}? \\ $$ Commented by mr W last updated…
Question Number 125506 by mathmax by abdo last updated on 11/Dec/20 $$\mathrm{let}\:\mathrm{C}=\left\{\mathrm{z}/\mid\mathrm{z}\mid=\mathrm{2}\right\}\:\mathrm{find}\:\int_{\mathrm{C}} \:\frac{\mathrm{z}^{\mathrm{2}} \mathrm{sinz}\:\mathrm{cosz}}{\left(\mathrm{z}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} }\mathrm{dz} \\ $$ Commented by ZiYangLee last updated on 11/Dec/20…
Question Number 125504 by Study last updated on 11/Dec/20 $${n}!=\mathrm{2}^{\mathrm{10}} \centerdot\mathrm{10}!\left(\mathrm{1}\centerdot\mathrm{3}\centerdot\mathrm{5}\centerdot\mathrm{7}\centerdot\centerdot\centerdot\mathrm{19}\right)\:\:\:\:\:\:\:\:{n}=??? \\ $$$${help}\:{me} \\ $$ Answered by Dwaipayan Shikari last updated on 11/Dec/20 $$\mathrm{1}.\mathrm{3}.\mathrm{5}…{k}=\frac{\mathrm{1}.\mathrm{2}.\mathrm{3}.\mathrm{4}.\mathrm{5}…\mathrm{2}{n}}{\mathrm{2}^{{k}} .{k}!}=\frac{\left(\mathrm{2}{k}\right)!}{\mathrm{2}^{{k}}…