Question Number 213342 by Spillover last updated on 03/Nov/24 Commented by MrGaster last updated on 03/Nov/24 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\begin{array}{|c|}{\:\:\int{H}_{{x}} ^{\sqrt{\pi}} {dx}=\frac{{H}_{{x}} ^{\sqrt{\pi}+\mathrm{1}} }{\:\sqrt{\pi}+\mathrm{1}}+{C}\:\:}\\\hline\end{array} \\ $$ Terms of…
Question Number 213343 by Spillover last updated on 03/Nov/24 Answered by MrGaster last updated on 03/Nov/24 $$=\int_{\mathrm{0}} ^{\mathrm{1}} \int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{sin}\left({x}\right)\mathrm{sin}\left({y}\right)\left(\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{sin}\left({z}\right)}{{x}+{y}+{z}}{dx}\right){dydx} \\ $$$$=\int_{\mathrm{0}}…
Question Number 213369 by Frix last updated on 03/Nov/24 $$\mathrm{Old}\:\mathrm{question}\:\mathrm{203835} \\ $$$$\underset{\mathrm{0}} {\overset{\sqrt{\mathrm{2}}} {\int}}\frac{\sqrt{\mathrm{6}−\sqrt{\mathrm{25}{x}^{\mathrm{4}} −\mathrm{50}{x}^{\mathrm{2}} +\mathrm{36}}}}{\:\sqrt{\mathrm{5}}}{dx}=? \\ $$ Commented by MathematicalUser2357 last updated on 06/Nov/24…
Question Number 213371 by otchoumou last updated on 03/Nov/24 Commented by otchoumou last updated on 03/Nov/24 $${aider} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 213376 by RoseAli last updated on 03/Nov/24 $$\int\frac{{dx}}{\:\sqrt{\left(\mathrm{4}{x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{3}} }} \\ $$ Commented by Frix last updated on 03/Nov/24 $$\mathrm{Sometimes}\:\mathrm{just}\:\mathrm{use}\:\mathrm{your}\:\mathrm{brain}\:\&\:\mathrm{experience} \\ $$$$\frac{{d}}{{dx}}\left[\frac{{g}\left({x}\right)}{\:\sqrt{\mathrm{4}{x}^{\mathrm{2}} +\mathrm{1}}}\right]=\frac{{g}'\left({x}\right)\left(\mathrm{4}{x}^{\mathrm{2}}…
Question Number 213276 by thetpainghtun_111 last updated on 02/Nov/24 $$\mathrm{y}^{\mathrm{2}} \:=\:−\:\mathrm{4px} \\ $$$$\:\mathrm{At}\:\left(−\frac{\mathrm{1}}{\mathrm{3}},\mathrm{1}\right)\rightarrow\:\mathrm{1}=\:−\mathrm{4p}\:\left(−\:\frac{\mathrm{1}}{\mathrm{3}}\:−\:\mathrm{h}\right) \\ $$$$\:\mathrm{At}\:\left(−\frac{\mathrm{5}}{\mathrm{3}},\mathrm{2}\right)\rightarrow\:\mathrm{4}\:=\:−\mathrm{4p}\:\left(−\:\frac{\mathrm{5}}{\mathrm{3}}\:−\:\mathrm{h}\right) \\ $$$$\:\:\:\:\:\mathrm{4}\:=\:\frac{−\:\frac{\mathrm{5}}{\mathrm{3}}\:−\:\mathrm{h}}{−\:\frac{\mathrm{1}}{\mathrm{3}}\:−\:\mathrm{h}} \\ $$$$\:\:\:\:\frac{\mathrm{4}}{\mathrm{3}}\:+\:\mathrm{4h}\:=\:\frac{\mathrm{5}}{\mathrm{3}}\:+\:\mathrm{h}\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{3h}\:=\:\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{h}\:=\:\frac{\mathrm{1}}{\mathrm{9}} \\ $$…
Question Number 213264 by efronzo1 last updated on 02/Nov/24 $$\:\:\:\:\:\:\sqrt{\mathrm{2}}\:\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{x}\:+\:\mathrm{1}\:=\:\mathrm{0}\: \\ $$$$\:\:\:\:\:\:\mathrm{x}_{\mathrm{1}} \:,\:\mathrm{x}_{\mathrm{2}} \:\:\underline{\underbrace{\square}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 213330 by MrGaster last updated on 02/Nov/24 Commented by MathematicalUser2357 last updated on 06/Nov/24 $${I}\:{need}\:{to}\:{send}\:{the}\:{equation}\:{to}\:{my}\:{chinese}\:{lover} \\ $$ Answered by MrGaster last updated on…
Question Number 213298 by MathematicalUser2357 last updated on 02/Nov/24 $$\boldsymbol{{Question}}\:\mathrm{29}.\:{Theres}\:\mathrm{2}\:{same}-{ratio}\:{sequences}\:\left\{{a}_{{n}} \right\},\left\{{b}_{{n}} \right\}\:{with}\:{a}\:{ratio}\:{of}\:{non}-{zero} \\ $$$${And}\:{if}\:{two}\:{sums}\:{of}\:{each}\:{sequences}\:\left(\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}{a}_{{n}} ,\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}{b}_{{n}} \right)\:{are}\:{convergent},\:{and}\:{two}\:{equations} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}{a}_{{n}} {b}_{{n}}…
Question Number 213267 by MrGaster last updated on 02/Nov/24 $$ \\ $$$$\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{+\infty} \frac{{x}−{x}^{\mathrm{2}} +{x}^{\mathrm{3}} −\ldots−{x}^{\mathrm{2018}} }{\left(\mathrm{1}+{x}\right)^{\mathrm{2021}} }{dx} \\ $$ Answered by TonyCWX08 last updated…