Question Number 178019 by Spillover last updated on 12/Oct/22 $$\mathrm{Give}\:\mathrm{the}\:\mathrm{IUPAC}\:\mathrm{name}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{following} \\ $$$$\left(\mathrm{a}\right)\mathrm{H}_{\mathrm{3}} \mathrm{PO}_{\mathrm{4}} \\ $$$$\left(\mathrm{b}\right)\mathrm{H}_{\mathrm{2}} \mathrm{CO}_{\mathrm{3}} \\ $$$$\left(\mathrm{c}\right)\mathrm{HCIO} \\ $$$$\left(\mathrm{d}\right)\:\mathrm{HNO}_{\mathrm{2}} \\ $$$$\left(\mathrm{e}\right)\mathrm{HNO}_{\mathrm{3}} \\…
Question Number 178018 by Spillover last updated on 12/Oct/22 $$\mathrm{8}.\mathrm{1g}\:\mathrm{of}\:\mathrm{a}\:\mathrm{compound}\:\mathrm{Q}\:\mathrm{contain} \\ $$$$\mathrm{magnessium}\:\mathrm{and}\:\mathrm{oxygen}.\mathrm{if} \\ $$$$\mathrm{mass}\:\mathrm{of}\:\mathrm{magnessium}\:\mathrm{is}\:\mathrm{4}.\mathrm{9g} \\ $$$$\mathrm{Determine}\:\mathrm{the}\:\mathrm{empirical}\:\mathrm{formular} \\ $$$$\mathrm{of}\:\mathrm{compound}\:\mathrm{Q}. \\ $$$$\left[\mathrm{given}\:\mathrm{Mg}=\mathrm{24}\:\:\:\mathrm{O}=\mathrm{16}\right] \\ $$ Answered by Spillover…
Question Number 178013 by Spillover last updated on 12/Oct/22 $$\mathrm{Using}\:\mathrm{Electronic}\:\mathrm{diagrams}\:\mathrm{show} \\ $$$$\mathrm{the}\:\mathrm{bonding}\:\mathrm{in}\:\mathrm{the}\:\mathrm{following} \\ $$$$\left(\mathrm{a}\right)\mathrm{Magnesium}\:\mathrm{chloride} \\ $$$$\left(\mathrm{b}\right)\mathrm{Sodium}\:\mathrm{chloride} \\ $$ Answered by Spillover last updated on 12/Oct/22…
Question Number 178009 by Spillover last updated on 12/Oct/22 Commented by Beginner last updated on 12/Oct/22 $${oxygen}\:{should}\:{be}\:\mathrm{16} \\ $$ Commented by Spillover last updated on…
Question Number 178011 by Spillover last updated on 12/Oct/22 $$\mathrm{Hydrocarbon}\:\mathrm{contain}\:\mathrm{80\%}\:\mathrm{by} \\ $$$$\mathrm{mass}\:\mathrm{of}\:\mathrm{carbon}\:\mathrm{and}\:\mathrm{the}\:\mathrm{rest} \\ $$$$\mathrm{is}\:\mathrm{for}\:\mathrm{hydrogen}.\mathrm{calculate}\:\mathrm{the} \\ $$$$\mathrm{empirical}\:\mathrm{formula}\:\mathrm{of}\:\mathrm{the}\:\mathrm{compound} \\ $$$$\left[\mathrm{given}\:\mathrm{H}=\mathrm{1}\:\:\mathrm{C}=\mathrm{12}\right] \\ $$ Answered by a.lgnaoui last updated…
Question Number 177605 by Spillover last updated on 07/Oct/22 Answered by Spillover last updated on 08/Oct/22 Answered by Spillover last updated on 08/Oct/22 Terms of…
Question Number 177606 by Spillover last updated on 07/Oct/22 Answered by Spillover last updated on 08/Oct/22 Answered by Spillover last updated on 08/Oct/22 Terms of…
Question Number 166678 by Laters last updated on 24/Feb/22 $$\mathrm{4}+\boldsymbol{{x}}+\mathrm{2}\boldsymbol{{x}}=\mathrm{8}+\mathrm{2}\left(\mathrm{3}+\boldsymbol{{x}}\right)−\mathrm{3} \\ $$$$\boldsymbol{{F}}{ind}\:{x} \\ $$$$ \\ $$ Answered by nurtani last updated on 24/Feb/22 $$\mathrm{4}+{x}+\mathrm{2}{x}=\mathrm{8}+\mathrm{2}\left(\mathrm{3}+{x}\right)−\mathrm{3} \\…
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