Question Number 159785 by jlewis last updated on 21/Nov/21 $$\mathrm{work}\:\mathrm{out}\:\mathrm{and}\:\mathrm{sketch}\:\mathrm{d}−\mathrm{orbital}\:\mathrm{for}\:\mathrm{the}\:\mathrm{function} \\ $$$$\left.\mathrm{i}\right)\:\mathrm{f}_{\mathrm{1}} =\mathrm{3Cos}^{\mathrm{2}} \theta−\mathrm{1} \\ $$$$\left.\mathrm{i}\right)\:\mathrm{f}_{\mathrm{2}} =\mathrm{Sin}\theta\mathrm{Cos}\theta\mathrm{Cos}\phi \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 159786 by jlewis last updated on 21/Nov/21 $$\mathrm{Work}\:\mathrm{out}\:\mathrm{and}\:\mathrm{sketch}\:\mathrm{P}_{\mathrm{y}} \:\mathrm{orbitals} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28076 by Tinkutara last updated on 20/Jan/18 Commented by Tinkutara last updated on 20/Jan/18 Answer given is 3rd. Is the answer correct? Answered by ajfour last updated on 20/Jan/18 $${Atomic}\:{wt}.\:=\:\mathrm{2}{g}/{mol}…
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Question Number 27475 by Tinkutara last updated on 07/Jan/18 Commented by rish@bh last updated on 07/Jan/18 CuI is the least ionic because Cu is the smallest cation out of all of them. And I is the biggest anion. Commented by Tinkutara last updated on 07/Jan/18 Isn't Na the smallest cation?…
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Question Number 75860 by peter frank last updated on 18/Dec/19 $${complete}\:{and}\:{balance}\: \\ $$$${S}+{HNO}_{\mathrm{3}} \rightarrow \\ $$$$ \\ $$ Answered by Crabby89p13 last updated on 19/Dec/19…