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Category: Ionic Equilibrium

Question-31619

Question Number 31619 by Tinkutara last updated on 11/Mar/18 Answered by Joel578 last updated on 11/Mar/18 $$\mathrm{Cu}\left(\mathrm{OH}\right)_{\mathrm{2}} \:+\:\mathrm{H}_{\mathrm{2}} \mathrm{SO}_{\mathrm{4}} \:\rightarrow\:\mathrm{CuSO}_{\mathrm{4}} \:+\:\mathrm{2H}_{\mathrm{2}} \mathrm{O} \\ $$$$\Rightarrow\:\mathrm{weak}\:\mathrm{acid}\:+\:\mathrm{strong}\:\mathrm{acid}\:\rightarrow\:\mathrm{acid}\:\mathrm{salt},\:\mathrm{pH}\:<\:\mathrm{7} \\…